1) If you form a subset of integers chosen from between 1 & 3000, such that no two no.s add up to a multiple of 9, what can b the max no. of elements in the subset?
(a) 1668
(b) 1332
(c) 1333
(d) 1334
2) A triangular no. is defined as the no. which has the property of being expressed as a sum of consecutive natural no.s starting with 1. How many triangular no.s less than 1000, have the property that they are the difference of squares of two consecutive natural no.s?
(a) 20
(b) 21
(c) 22
(d) 23
Plz help me solve this..
1) If you form a subset of integers chosen from between 1 & 3000, such that no two no.s add up to a multiple of 9, what can b the max no. of elements in the subset?
(a) 1668
(b) 1332
(c) 1333
(d) 1334
2) A triangular no. is defined as the no. which has the property of being expressed as a sum of consecutive natural no.s starting with 1. How many triangular no.s less than 1000, have the property that they are the difference of squares of two consecutive natural no.s?
(a) 20
(b) 21
(c) 22
(d) 23
Plz help me solve this..
1.observe the pattern of numbers which would appear between 1 and 3000 both included
9m+1---334 out of 3000
9m+2---334 out of 3000
9m+3---334
9m+4---333
9m+5---333
9m+6---334
9m+7---334
9m+8---334
pairs sud be (9m+1,9m+
---------------334-------------334-----------333----------333
Total 334+334+334+333=1335 : but umber suld be between 1-3000
hence total 1335-2=1333
2.they will be form of 1,3,6,10,15... i.e n(n+1)/2 form
Note:-
All odd numbers can be expressed as difference of squares of two consecutive natural numbers starting from 3.
Till 1000, there are 44 triangular numbers(44*45/2=960)
total set 44/2=22
but 44, 22 are odd hence subtract 1
22-1=21 ans
I have a doubt in q numbr LOD1 18 , inequalities...The answer options are wrong I guess...It should have been X> in (a) and X
ganz2iima SaysI have a doubt in q numbr LOD1 18 , inequalities...The answer options are wrong I guess...It should have been X> in (a) and X
Please post the question as well so that people who don't have the book can help too.
Heres another one:
A speaks the truth 3 times out of 4, B 7 times out of 10. They both assert that a white ball is drawn from a bag containing 6 balls, all of different colours. Find the probability of the truth of the assertion.
a)12/49 b)3/10 c)21/40 d)None of these
answer : c) 21/40
p(A) = 3/4 , P(B) = 7/10
Let C be the event that both are speaking truth
= P(A). p(B) = 3/4 * 7*10 = 21/ 40
Puys .. !!
1Question ...
I have the PAGE NO. & Question No ..
can you please help me out .. ??
GEOMETRY
PAGE : 349
Q23
hi all,i have problem solving this ques....
The following is known abt 3 real nos x,y,z.
-4a. -16ans a
think
x*z will max at : -4 *-8 = 32
x*z/y , so y suld be min i.e y=2
hence 32/2=16
siml.
x*z is max range covered 4 * -8 = -32
again x*z/y @y=2 hence M=-16
hence range sud be
-16
what if i take y=1 in both cases?
Puys .. !!
1Question ...
I have the PAGE NO. & Question No ..
can you please help me out .. ??
GEOMETRY
PAGE : 349
Q23
Please Post a question...
if its finding QM then answer is (a+b)/2
Please Post a question...
if its finding QM then answer is (a+b)/2
yeah ... dat's the answer ..
can u tell me , how was that done ??
yeah ... dat's the answer ..
can u tell me , how was that done ??
How many 3 digit positive integer with digits x,y,z in hundred and tens and units place resp. exist such that x
How many 3 digit positive integer with digits x,y,z in hundred and tens and units place resp. exist such that x
Since y has to greater than x and z,take y as the highest value and then start decreasing it...
CASE 1:8c1*1*9c1
8c1 denotes values of x(1,2,3,4,5,6,7,
9c1 denotes values of z(1,2,3,4,5,6,7,8,0)
So case 1(value of y=9):8*9=72
case 2(value of y=
case 3(value of y=7): 6*7=42
case 4(value of y=6): 5*6=30
case 5(value of y=5): 4*5=20
case 6(value of y=4): 3*4=12
case 7(value of y=3): 2*3=06
case 8(value of y=2): 1*2=02
So total of 240..


Please help me Geometry LOD 1 Problem no 12 Thanks in Advance
hey puys...was just about to start preparing for cat...got mocks from previous years, arun sharma and trishna's quantitative ability....but i m really confused..i mean wid just three months to go...do u think trishna or arun sharma are worth doing as there is large pool of questions out of which only sm r worth doing...
also if one should go for it...which do u think is better in terms of diversity of questions and level and offcourse consistency wid the keys and all...i know doing previous years mock is a must bt wanted to substantiate my preparation wid sm quatitative book so m confused...my basics r clear....or do u think i should stick to mocks only n do as many as i can...waiting for replies from all dose who have done arun sharma or trishna or from sm1 who actually knows wat is important in dis regard...
Dear PUYs i hav just started CAT preps but with just 3 months left i don't know whether there is any merit in doing this.............
I have started quants with Arun Sharma but i m even stuck up in LOD I.
Please help me in following ques:
Q1: If a,b,c,d are in continued proportion then (a-d)/(b-c) =>x.
What is the value of x.
(a) 2 (b) 3 (c) 1 (d) 0
ans b
Q2: If a,b,c,d are proportional, then (a-b)*(a-c)/a = ?
(a)a+c+d (b)a+d-b-c (c) a+b+c+d (d) none of these
ans b
Please help me as I am getting desperate..............
:
dinesh1787 SaysPlease help me Geometry LOD 1 Problem no 12 Thanks in Advance
If you really want help on a problem, please post it too, because very few people would actually take the trouble to search for the question and reply. Of course, if there's a figure that you're unable to post, write it in your post and probably then it makes sense for others to refer the book, but atleast write the question.
Originally Posted by dinesh1787 View Post
Please help me Geometry LOD 1 Problem no 12 Thanks in Advance
Simple use PT^2=PA x PB
What is the maximum value of 'n' such that the expression
42*57*92*91*52*62*63*64*65*66*67 is divisible by 42^n ??
Please give me funda for the same...
Which is the largest 4 digit number that can be added to 7249 in order to make the derived number divisible by each of 12,14,21,33 and 54?
Please explain how to solve this one.
avinav2712 SaysIf you really want help on a problem, please post it too, because very few people would actually take the trouble to search for the question and reply. Of course, if there's a figure that you're unable to post, write it in your post and probably then it makes sense for others to refer the book, but atleast write the question.
It is a problem on circles Im unable to insert the figure So I mentioned the Problem no and chapter else I would have posted the problem