I am not quite sure how to go about this one, will need some help....
total people = 8, no of ways to arrange them = 7!
no of arrangements where 2 girls sit together = 3P2(select 2 girls out of the three and arrange them)*6! (treat them as one and total no of people becomes 7) = 6*6!
Thus no of ways when no 2 girls sit together = 7!-(6*6!) = 720....oops........ can anyone point out the mistake in this solution
This can be done in a way that we arrange 5 boys first which can be done in 4! ways. Now girls can be arranged anywhere in the 5 gaps between boys which can be done in 5*4*3. So answer is 4!*5*4*3
One more on probability: If we have to choose 4 cards at random from a pack of well shuffled cards, what is the probability that, 3 of them are honours of the same suit and the remaining 1 is a honour from a different suit?
Tom, **** and Harry went for lunch to a restaurant. Tom had $100 with him, **** had $60 and Harry had $409. They got a bill for $104 and decided to give a tip of $16. They further decided to share the total expenses in the ratio of the amounts of money each carried. The amount of money which Tom paid more than what Harry paid is
Two identical taps fill 2/5 of a tank in 20 minutes. When one of the taps goes dry in how many minutes will the remaining one tap fill the rest of the tank ?
Tom, **** and Harry went for lunch to a restaurant. Tom had $100 with him, **** had $60 and Harry had $409. They got a bill for $104 and decided to give a tip of $16. They further decided to share the total expenses in the ratio of the amounts of money each carried. The amount of money which Tom paid more than what Harry paid is
120
200
60
24
36
There seems to be something amiss here, how can Tom pay more than harry when the initial amount with Tom,100 please check this again, also, even if we assume that it was a mistake and eventually Harry wud pay more, the options are not approximated, we will never get the exact values since all calculations will have 100+60+409 = 569 in the denominator.
So wat will be the calculation like if we assume that the question is correct: T = 100*120/569 and H = 409*120/569 H-T = (409*120)-(100*120)/569 = 309*120/569 = approx 65
So none of the options are correct, please re-check the question !
Two identical taps fill 2/5 of a tank in 20 minutes. When one of the taps goes dry in how many minutes will the remaining one tap fill the rest of the tank ?
5 minutes
10 minutes
15 minutes
20 minutes
None of the above
1 Tap fills (2/5)/2=1/5th tank in 20 mins
Remaining tank to be filled (I am assuming this since nothing specific is mentioned in the ques) = 1-(2/5) = 3/5
One more on probability: If we have to choose 4 cards at random from a pack of well shuffled cards, what is the probability that, 3 of them are honours of the same suit and the remaining 1 is a honour from a different suit?
Regards, Sabby
Can u clarify whether the cards are being put back in the deck or not?
I have no other link which has more number of questions. Anyways, send me a good link of questions-- I am sittin at office dude.. cant help myself searchin..!!! thanks.!!
I have no other link which has more number of questions. Anyways, send me a good link of questions-- I am sittin at office dude.. cant help myself searchin..!!! thanks.!!
You can go through all the questions from Page 1 of this forum and the DS Forum. I think you will have more than enough questions to handle then !
In a family, there is a mother, a father, 2 daughters and a son. The family is planning to go for a picnic. They decide to travel in their new car.The car has 2 seats in the front and 3 seats in the back.The car should be driven either by the dad or the mother.The two daughters should never sit together.How many ways can this arrangement be done?
in a family, there is a mother, a father, 2 daughters and a son. The family is planning to go for a picnic. They decide to travel in their new car.the car has 2 seats in the front and 3 seats in the back.the car should be driven either by the dad or the mother.the two daughters should never sit together.how many ways can this arrangement be done?
In a family, there is a mother, a father, 2 daughters and a son. The family is planning to go for a picnic. They decide to travel in their new car.The car has 2 seats in the front and 3 seats in the back.The car should be driven either by the dad or the mother.The two daughters should never sit together.How many ways can this arrangement be done?
Regards, Sabby :)
2(either mom or dad) x 2(either of the daughter) x 3!(rest of the three among themselves) = 24
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Hello Guys, I request you help me with the following query:
Q: A certain amount was to be divided between A,B & C in the ratio of 4:5:6 but by mistake, it was divided in such a way that 4 times A's share was equal to 5 times B's share and 6 times C's share. As a result, 'A' got $154 more than the expected amount. What was the amount that was divided among them? a)$370 b)$450 c)$560 d)$1000 e)$1110
One more on probability: If we have to choose 4 cards at random from a pack of well shuffled cards, what is the probability that, 3 of them are honours of the same suit and the remaining 1 is a honour from a different suit?
Regards, Sabby
Back in action after a hiatus....
No of honours card in a deck = 20 (A,K,Q,J,10)
P1(Card 1)-> P(choosing honurs card) = 20/52 P2(Card 2)-> P(choosing honours card of different suit than Card 1) = 15/51, since there are 15 honours cards to choose from and total 51 cards remaining in the deck. P3(Card 3)-> P(choosing honours card of same suit as Card 2) = 4/50, since we have to choose from the same suit as Card 2 and out of the 5 honours cards of that suit, one has already been picked up as Card 3) P4(Card 4)-> P(choosing honours card of same suit as Card 2 and Card3) = 3/49
Total P = P1*P2*P3*P4 P = 20/52 * 15/51 * 4/50 * 3/49
@Sabby87, my apologies for not understabding the question clearly earlier !
2(either mom or dad) x 2(either of the daughter) x 3!(rest of the three among themselves) = 24
I would just add one more possibility to this one, 2(mom/dad)*2(son/mom/dad)*1(only one arrangement to make them sit at the back daughter1-dad/mom/son-daughter2)
Hello Guys, I request you help me with the following query:
Q: A certain amount was to be divided between A,B & C in the ratio of 4:5:6 but by mistake, it was divided in such a way that 4 times A's share was equal to 5 times B's share and 6 times C's share. As a result, 'A' got $154 more than the expected amount. What was the amount that was divided among them? a)$370 b)$450 c)$560 d)$1000 e)$1110
I request you to help me with the query.
Thanks.
@alaynaik
Pl find the new ratio:
Now 4A=5B, and 4A=6C. so, simplifying New A:B:C=15:12:10.
So, if the amount to be divided is x then x*15/37-x*4/15=154. or, x=1110. simple.
