Hello All,
I'm starting my preparation for GMAT not finalized the dates though , I will take it up once I feel confident. I have been through many thread and still not able to finalize the material for Quant sections.
I dont have any CAT related material.
Is it Kaplan-800 or Kaplan Math work book ? which Kaplan book is better ?
By the way I will take the OG later.
I have finished the Kaplan Math Foundation Book
Looking forward for your help.
There are 20 students in a class, such that no two students are of same height. In how many ways can any 5 students stand in queue in increasing order of height?
How many 4 - digit numbers can be formed by using the digits 0 - 9, so that it contains exactly a distinct digits?.....
Please post your answers with approach....
Thanking in advance...
Didnt understand your question completely,
but still, i will try with whatever i understood.
Say the 4 digit number is abcd, d in units, c in tens place and so on.
a = can be anything from 1-9, 9 ways
b = can be anything from 0-9, except the one digit already used for a, 9 ways
c = can be anything from 0-9, except the 2 digits already used for a, b, 8 ways
d = can be anything from 0-9, except the 3 digits already used for a, b,c, 7 ways
Total = 9*9*8*7 = 4536 ways
kumoh02 SaysThere are 20 students in a class, such that no two students are of same height. In how many ways can any 5 students stand in queue in increasing order of height?
This problem is essentially asking us to find the number of ways to choose any 5 students out of the available 20, and, since there is only one way in which these 5 students will be arranged in the queue, we dont need to do anything else.
So, simply, 20C5 should give us the answer = 15504
E...
both the clues doesn't help in ny way
Use the below instructions to solve the Questions:
= Greatest integer less than or equal to x.
{x} = Smallest integer greater than or equal to x.
1)If x is not an integer, what is the value of ( - {x})?
a.) 0
b.) 1
c.) -1
d.) 2
2)If x is not an integer, then ({x} + ) is
a.) An even integer
b.) An odd integer
c.) > 3x
d.)
Please explain the above problems....
Use the below instructions to solve the Questions:
= Greatest integer less than or equal to x.
{x} = Smallest integer greater than or equal to x.
1)If x is not an integer, what is the value of ( - {x})?
a.) 0
b.) 1
c.) -1
d.) 2
2)If x is not an integer, then ({x} + ) is
a.) An even integer
b.) An odd integer
c.) > 3x
d.)
Please explain the above problems....
The greatest integer
Eg. For -1.5, will be, = -2 (since we find the greatest integer For 1.3, will be = 1
The smallest integer {x}
Eg. For -1.5, will be, {-1.5} = -1 (since we find the smallest integer >= x)
For 1.3, will be {1.3} = 2
Coming back to the questions:
1. -{x} needs to be found, taking cues from above examples,
-{-1.5}= -2 - (-1) = -1 and
-{1.3} = 1-2 = -1
So, (c) is correct
2. {x}+
{-1.5} + = -2+(-1) = -3 and
{1.3}+ = 1+2 = 3
Thus, odd integer, (b)
This question might sound stupid to some of the people who post on this thread.. I'm planning to take GMAT somewhere in this year end..Just want to know which books should i refer to brush up my quant..Basic stuff..some people have suggested to buy CBSE 9th/10th standard books..Could junta throwsome light on this please !!
monsterkartik SaysThis question might sound stupid to some of the people who post on this thread.. I'm planning to take GMAT somewhere in this year end..Just want to know which books should i refer to brush up my quant..Basic stuff..some people have suggested to buy CBSE 9th/10th standard books..Could junta throwsome light on this please !!
I guess going back to the CBSE books will take up lot of your time, probably, before doing that, you can take a look at the books from IMS(the CAT material). The books are brief, structured and cover all the topics almost from scratch. Another book is Arun Sharma.
I would suggest you to have a look at the available options, some books work well for some and not for others, there's no best way for all, it just has to be the best way for you !!
I guess going back to the CBSE books will take up lot of your time, probably, before doing that, you can take a look at the books from IMS(the CAT material). The books are brief, structured and cover all the topics almost from scratch. Another book is Arun Sharma.
I would suggest you to have a look at the available options, some books work well for some and not for others, there's no best way for all, it just has to be the best way for you !!
Would it be suitable to read thru CAT material when we know the level of GMAT quants is far lower than what you get in CAT ?? and again m not sure about how the modules of IMS are designed, whether they give u a clarity about the concept or just take u thru the formula and get cracking on the questions.. not looking for latter !!
monsterkartik SaysWould it be suitable to read thru CAT material when we know the level of GMAT quants is far lower than what you get in CAT ?? and again m not sure about how the modules of IMS are designed, whether they give u a clarity about the concept or just take u thru the formula and get cracking on the questions.. not looking for latter !!
IMS material is fairly standard and covers all the topics, you wont get the complete details here, on the forum, get out there, go through all the books in a store or at some friend's place and pick up the one/s which suits you.
And if you say that the level of GMAT quant is far lower, i would beg to differ, the concepts are the same for both, its just CAT is more detailed. If you want a really good score, I dont think you should take Quant lightly.
Kurt, a painter, has 9 jars of paint:
4 are yellow
2 are red
rest are brown
Kurt will combine 3 jars of paint into a new container to make a new color, which
he will name accordingly to the following conditions:
Brun Y if the paint contains 2 jars of brown paint and no yellow
Brun X if the paint contains 3 jars of brown paint
Jaune X if the paint contains at least 2 jars of yellow
Jaune Y if the paint contains exactly 1 jar of yellow
What is the probability that the new color will be Jaune
a) 5/42
b) 37/42
c) 1/21
d) 4/9
e) 5/9
Kurt, a painter, has 9 jars of paint:
4 are yellow
2 are red
rest are brown
Kurt will combine 3 jars of paint into a new container to make a new color, which
he will name accordingly to the following conditions:
Brun Y if the paint contains 2 jars of brown paint and no yellow
Brun X if the paint contains 3 jars of brown paint
Jaune X if the paint contains at least 2 jars of yellow
Jaune Y if the paint contains exactly 1 jar of yellow
What is the probability that the new color will be Jaune
a) 5/42
b) 37/42
c) 1/21
d) 4/9
e) 5/9
Options for Jaune-X,
2Y+1B (4C2.3C1) or 2Y+1R(4C2.2C1) or 3Y(4C3)
So Total(J-X) = 18+12+4 = 34
Options for Jaune-Y,
1Y+2B (4C1.3C2) or 1Y+2R (4C1.2C2) or 1Y+1B+1R(4C1.3C1.2C1)
So Total(J-Y) = 12+4+24 = 40
And total options are = 9C3 = 84
Thus P = P(J-X)+P(J-Y)/84
=(40+34)/84 = 74/84 = 37/42
(b) should be the answer.
Hey guys,
I am Varshini. I have jus started to prepare for GMAT. I saw the thread and kinda freaked out. i find the SCs a lil decent but i find the quants racking my head.... Can someone suggest books i can work these out from.....???
Varsh :D:D:D
37/42 is correct.
A group of 8 friends want to play doubles tennis. How many different ways can the group be divided into 4 teams of 2 people?
A. 420
B. 2520
C. 168
D. 90
E. 105
37/42 is correct.
A group of 8 friends want to play doubles tennis. How many different ways can the group be divided into 4 teams of 2 people?
A. 420
B. 2520
C. 168
D. 90
E. 105
We have to make 4 Teams out of the available 8 people.....
8C2*6C2*4C2*2C2 should give us the answer = 2520
Thus, B
But I doubt if this is correct, because 2520 is an insanely high number for just 8 teams, what is it that I am missing? Can someone please figure out.
Hey guys... I am jus starting off with GMAT prep... and all this GMAT discussion is taking me for a ride... can someone suggest wat do i start off wid...?
Varsh!!!
We have to make 4 Teams out of the available 8 people.....
8C2*6C2*4C2*2C2 should give us the answer = 2520
Thus, B
But I doubt if this is correct, because 2520 is an insanely high number for just 8 teams, what is it that I am missing? Can someone please figure out.
Hey even I got 2520. All permutations of the 8 members considering repetitions of A/B B/A combinations.
8!/2^4.
The answer given was 105. But I'm not quite convinced with the explanation. I'll post it here:
QUOTE:
1st team could be any of 2 guys... there would be 4 teams (a team of A&B; is same
as a team of B&A;)... possible ways 8C2 / 4.
2nd team could be any of remaining 6 guys. There would be 3 teams (a team of A&B; is
same as a team of B&A;)... possible ways 6C2 / 3
3rd team could be any of remaining 2 guys... there would be 2 teams (a team of A&B; is
same as a team of B&A;). Possible ways 4C2 / 2
4th team could be any of remaining 2 guys... there would be 1 such teams... possible
ways 2C2 / 1
total number of ways...
8C2*6C2*4C2*2C2
-------------------
4 * 3 * 2 * 1
=
8*7*6*5*4*3*2*1
--------------------
4*3*2*1*2*2*2*2
= 105 (ANSWER)...
Another method: say you have 8 people ABCDEFGH
now u can pair A with 7 others in 7 ways.
Remaining now 6 players.
Pick one and u can pair him with the remaining 5 in 5 ways.
Now you have 4 players.
Pick one and u can pair him with the remaining in 3 ways.
Now you have 2 players left. You can pair them in 1 way
so total ways is 7*5*3*1 = 105 ways i.e. E
UNQUOTE
37/42 is correct.
A group of 8 friends want to play doubles tennis. How many different ways can the group be divided into 4 teams of 2 people?
A. 420
B. 2520
C. 168
D. 90
E. 105
I got the very same... 2520.
This problem is essentially asking us to find the number of ways to choose any 5 students out of the available 20, and, since there is only one way in which these 5 students will be arranged in the queue, we dont need to do anything else.
So, simply, 10C5 should give us the answer = 15504
sausi,
I am sorry but this might seem silly. But i am a little lost with the explanation. Can you detail it? Thanks in advance.