GMAT Problem Solving Discussions

MBA
4246
IMO OP D,
HI Switr, m sorry but i think your explanation is completely wrong...
and thats y i think the ans u suggest is also wrong....
pls c the attached word file...i simply reconstructed the diagram as the only
given condition is ab=cd..see the attachment


Thanks AM for correcting me. Excellent analysis.
4247
@gladvijay: A couple of fundamental mistakes. 1 is not an even number so the sequence has to start from 2. and the number of even numbers between 1 and K is (k-1)/2 ... rest all looks fine going by the above two facts the answer is 159
n(n+1) =79*80
n=79=(k-1)/2 ==> K=159


sorry dude.. i shud starting reading the question before answering 😞
4248
Switr Says
It was a mistake. I did not understand your need to be judgemental about it. Just by typing whatever you have typed above you have shown us what a perfectly capable dud(e) you are. Thank you Sir!!:thumbsup:

sorry boss my bad ... i changed it, dont worry and the purpose of that post was to emphasize the fact that replies here need checked and rechecked before posting, since somebody looks for an answer here and can base his/her concepts based on your answer. Aplogies again
4249
sshekhar18 Says
sorry boss my bad ... i changed it, dont worry and the purpose of that post was to emphasize the fact that replies here need checked and rechecked before posting, since somebody looks for an answer here and can base his/her concepts based on your answer. Aplogies again



Agreed, thats a valid concern. It was a mistake on my part to have not rechecked my logic. I generally avoid posting answers w/o the logic. I will be careful in the future to recheck my answers... Apology accepted :cheerio: !!
4250

Looks like E, together they are not sufficient

4251

When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.12, what is the value of y ?
A) 96
B) 75
C) 48
D) 25
E) 12

4252

B
x=96y + 0.12y

0.12y = 9
y = 75

When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.12, what is the value of y ?
A) 96
B) 75
C) 48
D) 25
E) 12
4253
How many roots does this equation have?

sq rt (x^2 + 1) + sq rt (x^2 + 2) =2

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

Hi,

I feel the easiest possible way would be like this -

min value of x^2+1 = 1 and for X^2+2 = 2 for x = 0

This gives us sqrt(1)+sqrt(2), which will always be >2. Therefore from here we can conclude that this equation will not have any real solution. Hence Ans (A).
4254

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14

4255

7x+5y=63
key here is both x and y shud be integers.
only values which satisfy are x=4 and y=7
so total =11
option B

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
4256
A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14



ans 11
.70*4+.50*7=6.30
4257

Six mobsters have arrived at the theater for the premiere of the film "Goodbuddies." One of the mobsters, Frankie, is an informer, and he's afraid that another member of his crew, Joey, is on to him. Frankie, wanting to keep Joey in his sights, insists upon standing behind Joey in line at the concession stand, though not necessarily right behind him. How many ways can the six arrange themselves in line such that Frankie's requirement is satisfied?

6

24

120

360

720

4258

IMO 360.......

J->1st, F can be (2,3,...6) = 5ways, total = 5*4!(to account for the rest of them)
J->2nd, F can be (3,...6) = 4ways, total = 4*4!
.
.
.
J->5th, F 6th = 1way, total = 1*4!
Thus,
Total = (5+4+3+2+1)*4!
= 15*24 = 360


Six mobsters have arrived at the theater for the premiere of the film Goodbuddies. One of the mobsters, Frankie, is an informer, and he's afraid that another member of his crew, Joey, is on to him. Frankie, wanting to keep Joey in his sights, insists upon standing behind Joey in line at the concession stand, though not necessarily right behind him. How many ways can the six arrange themselves in line such that Frankies requirement is satisfied?

6

24

120

360

720
4259

In the diagram above, AB=CD, From this we can deduce that:
A) AB is parallel to CD.
B) AB is perpendicular to BD.
C) AC=BD
D) Angle ABD equals angle BDC.
E) Triangle ABD is congruent to triangle ACD


Hi guys,

this is how i looked at the above problem... please let me know if this approach is correct or has some unforeseen flaws.

1. from the figure we have ABDC to be a cyclic quadrilateral.

2. there are 2 possiblities for AD
a. it is the diameter of the circle.
b. it is NOT the diameter.

3. the data given states that AB=CD

considering the above points, we have 2 possiblities for the quadrilateral
a. it is a rectangle (or a square)
b. it is an isoceles trapezium

now... looking at the options we see that D is the only one that holds true for both the above cases. hence the answer should be D.
4260

First, i guess u need to identify and attack your problem areas, be it Combinatorics, Stats or Probability etc.
Second, try and use standard material like the Mgmat guides or Arun Sharma for getting hold of the concepts and extra practice(apart from OGs)
Third, u need to do well in both Quant and Verbal, because, i would like to believe that a highly skewed breakup in favour of any one section is not well recieved by the people reviewing the profiles.

sashankl Says
Hi fellow puysneed some help. I have been scoring around 47-48 in Quant on the mock gmat tests including the GMAT prep but have been never able to score 50 and above. Can you please give me some suggestions on what I could do, because verbal is my weak point and I really need to score well in Quant to do well on the GMAT.
4261

Q. Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?

As per the instructions, all numbers are real numbers in GMAT; Hence, that means that set R can also contain zero as one of the numbers, right? If it is correct, then the answer will change.

Can someone please clarify?

4262

If i say that it takes 2 years for a to increase by a factor of 5, will the final value after 2 years be 5a or 6a?

4263
Vishal84 Says
If i say that it takes 2 years for a to increase by a factor of 5, will the final value after 2 years be 5a or 6a?



i think that the final value will be '5a' because when u say that the quantity will increase by a factor of 5 what u r essentially saying is that the quantity will become 5 times its current value.

Requesting others to confirm if this reasoning is correct. thanks!
4264

I would say 6a bcos the "increase itself is 5a". When a becomes 6a the increase will be 5a which is 5 times the value.When a becomes 5a the increase is only 4a.

Pls correct me if I'm wrong.

-Deepak.

4265

I dont think it will change anything......please see the explanation below:

Let the nos be a->e, we know e=3a+20,
so R={a,b,55,c, 3a+20}
summing all nos
4a+b+c+75 = 55*5 (since mean is 55)
4a+b+c = 200

Range for R will be e-a (largest - smallest) = 3a+20-a = 2a+20

Our task is to maximise the range, i.e., find Max value of 2a+20
using the first eqn 4a+b+c=200.

Max value of a will be achieved by minimising values of b and c.
Min value of c will be 55(equal to the median)
Min value of b will be a (since it cannot be less than a)

thus, 4a+a+55=200
a=29

Range becomes, 58+20 = 78

Values of a

Q. Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?

As per the instructions, all numbers are real numbers in GMAT; Hence, that means that set R can also contain zero as one of the numbers, right? If it is correct, then the answer will change.

Can someone please clarify?