The product of the units digit, the tens digit, and the hundreds digit of the positive integer m is 96. What is the units digit of m ? (1) m is odd. (2) The hundreds digit of m is 8.
Factorization problem: The prime factors of 96 = 2*2*2*2*2*3 (Remember digits have to be single) from stmt 1: m is odd. The only odd digit possible in the units place is 3. Hence m=3(sufficient) from stmt 2: if hundreds digit is 8 then units digit of m can be 2,4,6,3... (Insufficient)
Q7 PS in OG11. I am not able to understand the answer...can somebody help?
Thanks in advance.
It is very hard to draw a diagram (I tried hard) here...but it is X Y coordinate plane with an oval kind of shape touching X and Y base.
Question is
On the graph above, when x=1/2, y = 2; and when x =1 and y =1. The graph is symmertrical with respect to the vertical line at x=2. According to the graph, when x=3, y =?
Answer is = 1. Since the paragraph is symmetric with respect to x=2, the y value when x=3 will be the same as they y value when x=1, which is 1.
Factorization problem: The prime factors of 96 = 2*2*2*2*2*3 (Remember digits have to be single) from stmt 1: m is odd. The only odd number possible is 3. Hence m=3(sufficient) from stmt 2: if hundreds digit is 8 then m can be 2,4,6 (Insufficient)
Hence answer choice was (A)
Boss when it is written m is odd means abc is odd number and factors of 96 are 2^5*3 which is odd*even is even. can u elaborate pls.they have not written unit digit is odd.pls explain the concept.
Boss when it is written m is odd means abc is odd number and factors of 96 are 2^5*3 which is odd*even is even. can u elaborate pls.they have not written unit digit is odd.pls explain the concept.
The number m = a b c will ONLY be odd number when the units digit of m is odd. Since 3 is required to make the products of the digits 96, the units digit will have to be 3
The number m = a b c will ONLY be odd number when the units digit of m is odd. Since 3 is required to make the products of the digits 96, the units digit will have to be 3
got your pooint thanx.c can u pls tell me why x^2-4| is positive or >0 why not negative.
The product of the units digit, the tens digit, and the hundreds digit of the positive integer m is 96. What is the units digit of m ? (1) m is odd. (2) The hundreds digit of m is 8.
When 96 is factorised we get 3*4*8.We need to find which is the unit digit among the 3 nos.
Statement 1: m is odd...There is only one odd no in the above factorisation.So unit digit has to be 3 to make m odd. Sufficient.
Statement 2: no use.Cannot find the unit digit from this.
A challenging probability question which came to my mind...
Q) If a man climbs a staircase having 12 steps by jumping one step, two steps or three steps at a time in any order. What is the probability that he took at least two three step jumps?
On comparing the 2007 bases ,I get x = 1 . I'm not sure abt this
-Deepak.
Ya I posted the complete question. how do u get to that? i asked someone else about this who explained it this way: 2008^2008-2008^2007 comes to 2008 by way of this formula: a^m - a^n = a^m-n. so that means 2008 = 2007^x. Is that how its to be done?
Ya I posted the complete question. how do u get to that? i asked someone else about this who explained it this way: 2008^2008-2008^2007 comes to 2008 by way of this formula: a^m - a^n = a^m-n. so that means 2008 = 2007^x. Is that how its to be done?
I'm sure this formula is not correct. a^m - a^n is NEVER EQUAL to a^(m-n)
a^m / a^n = a^(m-n) .
Simply substitution will tell
2^3 - 2^2 = 8-4 = 4
By your formula : 2^3 - 2^2 = 2^(3-2) = 2^1 = 2
So I think there must be some other method that I'm not aware of to solve this problem.
Factorization problem: The prime factors of 96 = 2*2*2*2*2*3 (Remember digits have to be single) from stmt 1: m is odd. The only odd digit possible in the units place is 3. Hence m=3(sufficient) from stmt 2: if hundreds digit is 8 then units digit of m can be 2,4,6,3... (Insufficient)
Hence answer choice was (A)
245857anu Says
Boss when it is written m is odd means abc is odd number and factors of 96 are 2^5*3 which is odd*even is even. can u elaborate pls.they have not written unit digit is odd.pls explain the concept.
euros Says
The number m = a b c will ONLY be odd number when the units digit of m is odd. Since 3 is required to make the products of the digits 96, the units digit will have to be 3
@245857anu, There was slight misinterpretation at my end. @euros is correct. The answer choice however remains the same. I have modified the explanation. I actually read this "What is the units digit m" so for me m was the units digit, but fortunately this question can be done with the misinterpreted form ...But can't always get lucky :shocked:....so I will be more careful the next time.
Hi, I recently took the GMAT and got a question that I wasn't sure of how to answer. I hope one of you can solve this for me in steps:
2008^2008 - 2008^2007 = 2007^x
what is the value of x?
Options were like: 0, 1, 2007, 2008, 2006, etc
Let me this say first, I don't see this as a correct Question. Here is a proposed solution. 2008^2007(2008-1) = (2008^2007)*2007 => (2007+1)^2007 = 2007^(x-1) Using LOG base 10, 2007 log (2007 + 1) ~ 2007 log 2007 2007*log 2007 = (x-1) log 2007 Hence x-1 = 2007 , so x=2008 (Ans)