hi praveen, could you tell me if there are any sites from where i can download free gmat quant papers for practice. they should be closest to the actual gmat itself. really appreciate the help mate. thanks.
GMAT Challenge questions for 14 DEC 2010
GMAT questriona | GMAT4ALL
Is this a credible resource.I tried solving the questions turned out that the answers were wrong. Disappointing. Anyone else saw this question:
If 3-X = 3X-3 Then the square of X-1 is
The correct asnwer is 25/16.
Solution per me:
3-X = 3X-3
=> 4X = 6
=> X = 3/2
=> X-1 = 1/2
=> (X-1)^2 = 1/4. Is this solution wrong?
Is this a credible resource.I tried solving the questions turned out that the answers were wrong. Disappointing. Anyone else saw this question:
If 3-X = 3X-3 Then the square of X-1 is
The correct asnwer is 25/16.
Solution per me:
3-X = 3X-3
=> 4X = 6
=> X = 3/2
=> X-1 = 1/2
=> (X-1)^2 = 1/4. Is this solution wrong?
Seems good...:thumbsup:
Thanks,
Anurag...
15 JUNE 2010 - GMAT DAILY Challenge.
Take the challenge- available at
GMAT Daily Challenge | GMAT4ALL
Is this a credible resource.I tried solving the questions turned out that the answers were wrong. Disappointing. Anyone else saw this question:
If 3-X = 3X-3 Then the square of X-1 is
The correct asnwer is 25/16.
Solution per me:
3-X = 3X-3
=> 4X = 6
=> X = 3/2
=> X-1 = 1/2
=> (X-1)^2 = 1/4. Is this solution wrong?
Yes this question seems to be wrong in the quiz. Your solution is correct
15 JUNE 2010 - GMAT DAILY Challenge.
Take the challenge- available at
GMAT Daily Challenge | GMAT4ALL
Dude are you trying to sell this here?
Is this a credible resource.I tried solving the questions turned out that the answers were wrong. Disappointing. Anyone else saw this question:
If 3-X = 3X-3 Then the square of X-1 is
The correct asnwer is 25/16.
Solution per me:
3-X = 3X-3
=> 4X = 6
=> X = 3/2
=> X-1 = 1/2
=> (X-1)^2 = 1/4. Is this solution wrong?
I also took the quiz but on seeing the answers, I was fed-up.I stopped visiting that site.
Gail.Wynand SaysDude are you trying to sell this here?
rofl ..
Gail.Wynand SaysDude are you trying to sell this here?
No I am not trying to "Sell" this here. I blog/work part time for gmat4all and I publish couple of gmat type questions (on all working days)on that site. I attempted my GMAT in 2008 and I am currently doing my part time MBA along with CFA . As far as the website is concerned, I dont think they will charge for questions any time soon. These forums were handy when I was preparing for gmat and thought I will share the questions that I post.
Regret any issues that you guys had with the question with wrong answer choices.I just provide the questions and answers, I guess the systems guy who created/formatted the quiz goofed up.Its rectified now. I apologize!!
Is this a credible resource.I tried solving the questions turned out that the answers were wrong. Disappointing. Anyone else saw this question:
If 3-X = 3X-3 Then the square of X-1 is
The correct asnwer is 25/16.
Solution per me:
3-X = 3X-3
=> 4X = 6
=> X = 3/2
=> X-1 = 1/2
=> (X-1)^2 = 1/4. Is this solution wrong?
@Gail.Wynad;
I am not sure though. There could have been some printing mistake, I guess.
Had the question been
1. If 6-X = 3X-3 Then the square of X-1 is :
2. If 3-X = 3X-6 Then the square of X-1 is :
then, the solution is justified 😃 😃
EA----------B---------C----------D
Is
CD > BC ?
(1) AD = 20
(2) AB = CD
A Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D EACH Statement ALONE is sufficient.
E Statements (1) and (2) TOGETHER are NOT sufficient.
E
Yes it obviously is E. 😃 But to solve it after 3.5 years, looks quite funny though 😉 He he!!
Regards,
but then dude,
Thsi was my first answer I gave in my career on GMAT. I am an GMAT alien. But then I would want to start my preparation for same going forward so that I can apply at IIMB Bangalore for 2011 batch!
thanks for your reply1!
try solving this DS question within 2 mintutes..
if (x^2 - bx + c = 0) has integer solution(s), where b and c are integers, what is the solution?
1. b is a prime number.
2. c is a prime number.
try solving this DS question within 2 mintutes..
if (x^2 - bx + c = 0) has integer solution(s), where b and c are integers, what is the solution?
1. b is a prime number.
2. c is a prime number.
Statement 1 is insuff bcos it doesn't talk about the product of the roots.
Statemnt 2 is insuff bcos it doesn't talk about sum of the roots.
Combining both the statements, we arrive at a condition where sum of the roots and product of the roots are prime nos.When product of the roots is a prime nos then it means tht one of the root has to 1.Bt this contradicts the sum of the roots. Bcos prime number + 1 can't be a prime number.
So I will say that the eqn doesn't have any solution when you combine both the statements. I will go with option C.
Wats the OA?
-Deepak.
Statement 1 is insuff bcos it doesn't talk about the product of the roots.
Statemnt 2 is insuff bcos it doesn't talk about sum of the roots.
Combining both the statements, we arrive at a condition where sum of the roots and product of the roots are prime nos.When product of the roots is a prime nos then it means tht one of the root has to 1.Bt this contradicts the sum of the roots. Bcos prime number + 1 can't be a prime number.
So I will say that the eqn doesn't have any solution when you combine both the statements. I will go with option C.
Wats the OA?
-Deepak.
Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?
20%
30%
40%
50%
60%
my solution:
assume micheal and anthony are already in a committee
out of 3 places in that committee, remaining one can be filled in 4 ways (by any other 4 persons.
so number of favorable cases = 4
total number of cases = 6(C)3 = 20 (selecting 3 out 6 people. the remaining 3 will automatically be in other committee)
so ans = 4 /20 = 20 %
what is the flaw?? ans is 40%
Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?
20%
30%
40%
50%
60%
my solution:
assume micheal and anthony are already in a committee
out of 3 places in that committee, remaining one can be filled in 4 ways (by any other 4 persons.
so number of favorable cases = 4
total number of cases = 6(C)3 = 20 (selecting 3 out 6 people. the remaining 3 will automatically be in other committee)
so ans = 4 /20 = 20 %
what is the flaw?? ans is 40%
there r 2 sub-committees.. n i guess u've solved it for only 1 sub-committee..
this is an OR case..
either both r selected in 1st OR in 2nd committee..
1st committee - 4 cases OR(+) 2nd committee - 4 cases = total 8 cases
Statement 1 is insuff bcos it doesn't talk about the product of the roots.
Statemnt 2 is insuff bcos it doesn't talk about sum of the roots.
Combining both the statements, we arrive at a condition where sum of the roots and product of the roots are prime nos.When product of the roots is a prime nos then it means tht one of the root has to 1.Bt this contradicts the sum of the roots. Bcos prime number + 1 can't be a prime number.
So I will say that the eqn doesn't have any solution when you combine both the statements. I will go with option C. y did u select C instead of E here?
Wats the OA?
-Deepak.
either statements is not sufficient.. now combining them..
lets solve it using ur method, taking sum n product of roots.. let the roots be m and n.
equation is x^2 - bx + c = 0
(m+n)=b----->(1)
mn=c ---------->(2)
from (2) since c is prime, either m or n shd be 1(if both m & n are prime then c will become composite)
lets say m=1, then n=c
or from (1)
1+n = b => 1+c =b (where both b and c are primes)
this is possible only when c=2 and b=3.
so both statements r sufficient.. hence option C..
either statements is not sufficient.. now combining them..
lets solve it using ur method, taking sum n product of roots.. let the roots be m and n.
equation is x^2 - bx + c = 0
(m+n)=b----->(1)
mn=c ---------->(2)
from (2) since c is prime, either m or n shd be 1(if both m & n are prime then c will become composite)
lets say m=1, then n=c
or from (1)
1+n = b => 1+c =b (where both b and c are primes)
this is possible only when c=2 and b=3.
so both statements r sufficient.. hence option C..
I can say if tht the eqn has a solution or not only by combining both the statements...So I selected option C.
-Deepak.