I'm getting the ans as 78.Here is huv I worked it out.
Lets take the 5 nos as x,x,55,55,y where x = smallest no and y = largest no. Avg of all 5 nos is 55.So sum of all 5 nos is 55*5
We get 2x+y = 165
Also, y = 3x+20.
solving above eqn we get x = 29 and y = 107.So range is 107-29 = 78.
The nos are 29,29,55,55,107.
You are
There is no such condition that all elements in a set should be distinct. {1,2,3,3,3,4} is a valid set. :)
Hi Monil,
Actually, {1,2,3,3,3,4} is not a valid set according to the set theory. A set is always a collection of distinct objects.I quote wikipedia here:
By a "set" we mean any collection M into a whole of definite, distinct objects m (which are called the "elements" of M) of our perception or of our thought.
What I was trying to ask here is, did the question really impose the verbatim definition of set in the problem? Or does the problem use the term set loosely to convey a collection of 5 words?
Junta, what is the accepted GMAT norm here?
Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?
A)78
B)77 1/5
C)66 1/7
D)55 1/7
E)52
monil, bhavin, deepak... u all got it right.. :)
I'm so sorry for the late response...
OA -> A
Thanx monil for the explanation...
Nisha , alternatively we can say m/n = (13*25 + 6) / 25
= say (k+6)/25 where k is a multiple of 25 ...
Now when we multiple or divide by the same no, value remains unchanged
If the multiplying factor is 2 then
(2k + 12) / 50 where 2k is mult of 50 hence rem is 12 ...
So if the multiplying factor is n, then
(nk+6n) / 25n ...where nk is multiple of 25 n ...so 6n is remainder ...
Hence, to generalize any multiple of 6 can be a remainder !
Hope that helps !
Bhavin... super explanation!! :clap:
Thanks sooo much!
if m and n are positive integers such that m/n = 13.24, which of the following could not be the remainder when m is divided by n?
A)12
b)16
c)30
d)48
e)120
OA is B
......
Hey puys... I'm gonna disappear for a while. Took the Gmat and not so happy with my score.. :(
Well, I just want to thank u all for so much help.... PG rocks coz of all it's Puys!! 
Bhavin, PJ02, Deepak, Vikram... u all have been of great help... thanks a big bunch.. my quant really improved and a lot of it is coz of ur help!! :clap:
Happy GMATing!!
:cheers:
Hi Monil,
Actually, {1,2,3,3,3,4} is not a valid set according to the set theory. A set is always a collection of distinct objects.I quote wikipedia here:
By a "set" we mean any collection M into a whole of definite, distinct objects m (which are called the "elements" of M) of our perception or of our thought.
What I was trying to ask here is, did the question really impose the verbatim definition of set in the problem? Or does the problem use the term set loosely to convey a collection of 5 words?
Junta, what is the accepted GMAT norm here?
Arey nahi nahi nere bhai ... you are getting confused. :)
Tell me, if all the elements in the set are distinct, how will you calculate Mode of a given set of data? (remember - Mean, Meadian, Mode)
Have a look at this link. Hope it helps.
Feel free to get back if you have any further doubts.
Arey nahi nahi nere bhai ... you are getting confused. :)
Tell me, if all the elements in the set are distinct, how will you calculate Mode of a given set of data? (remember - Mean, Meadian, Mode)
Have a look at this link. Hope it helps.
Feel free to get back if you have any further doubts.
Guess I am getting too technical here...
Thanks Monil!
which of the following inequalities has a solution set that , when drawn on number, is a single line segment of finite length?
a) x^4 >= 1
b) X^3 c) x^2 >= 16
d) 2 e) 2
Please post with explanations.
first three choices have infinite no of solns.
D & E has 8 possible solutions.
Answers later.
IMO = E
a,b,c donot have one end value on numeber line.
d can make two distinct lines. one from -5 to -2 and other from 2 to 5.
E can have only one line.. 
which of the following inequalities has a solution set that , when drawn on number, is a single line segment of finite length?
a) x^4 >= 1
b) X^3 c) x^2 >= 16
d) 2 e) 2
Please post with explanations.
first three choices have infinite no of solns.
D & E has 8 possible solutions.
Answers later.
for which of the following functios is f(x) =f(1-x) for all x?
f(x)= 1-x
f(x)= 1-x^2
f(x)= x^2-(1-x)^2
f(x)= x^2(1-x)^2
f(x)= x/1-x
this question is driving me nuts..... i can't even understand the meaning of question , what its asking anyway?
--------------------------------------------------------
38,69,22,73,31,47,13,82
Which of the following numbers is greater than three fourths of the numbers but less than one-fourth of the number in the number list above ?
56
68
69
71
73
Hi...i'm going to give the gmat on 18th of december...i've gone through princeton review's cracking the gmat 2010 edition...but their math review doesn't seem sufficient...can anyone please let me know where I can get the most thorough math review from? I mean in terms of theory/notes...for gmat math...
thanks in advance!
1) If n is a multiple of 5 and n=p^2q , p and q are prime numbers.Which of the following is must be multiple of 25
A) p^2 B) q^2 c)pq D) p^2q^2 e) p^3q
2) Of 12 temporary employees, 4 will be hired as permanent employees . If 5 out of 12 temporary employees are women how many of possible groups of 4 temporary employees formed consisting of 3 women and 1 man
a) 22 b) 35 c) 56 d) 70 e) 105
3) A city with population of 132000 is divided into 11 voting districts, no district is to have population that is more than 10% greater than population of any other district. What is minimum possible population that the least population district could have
a) 10700 b)10800 c) 10900 d) 11000 d) 11100
for which of the following functios is f(x) =f(1-x) for all x?
f(x)= 1-x
f(x)= 1-x^2
f(x)= x^2-(1-x)^2
f(x)= x^2(1-x)^2
f(x)= x/1-x
this question is driving me nuts..... i can't even understand the meaning of question , what its asking anyway?
--------------------------------------------------------
38,69,22,73,31,47,13,82
Which of the following numbers is greater than three fourths of the numbers but less than one-fourth of the number in the number list above ?
56
68
69
71
73
Hey Aliz_Khanz,
There are quite simple Qs. Just think step by step, and you should be able to crack both.
Q1:
What this Q simply means is that if you replace x with (1-x) in the expression options provided, you should still get the same expression after solving. Try replacing x with (1-x) in option D, and you will know why D is the right answer.
Q2:
Understanding the question:
"greater than three fourths of the numbers" means that your answer should be greater than at least 3/4th of the numbers (3/4 of 8 is 6). So, see from the given options, which number is greater than at least 6 numbers given in the list.
Solution:
First sort the numbers in increasing order: 13, 22, 31, 38, 47, 69, 73, 82.
Options that satisfy first condition (greater than three fourths of the numbers) : 71 (D) and 73 (E).
Options that satisfy second condition (lesser than one fourth of the numbers) : all options satisfy except 73 (D).
The only common answer between both these sets is 71. Hence the answer is D.
Cheers.
Ankit
1) If n is a multiple of 5 and n=p^2q , p and q are prime numbers.Which of the following is must be multiple of 25
A) p^2 B) q^2 c)pq D) p^2q^2 e) p^3q
2) Of 12 temporary employees, 4 will be hired as permanent employees . If 5 out of 12 temporary employees are women how many of possible groups of 4 temporary employees formed consisting of 3 women and 1 man
a) 22 b) 35 c) 56 d) 70 e) 105
3) A city with population of 132000 is divided into 11 voting districts, no district is to have population that is more than 10% greater than population of any other district. What is minimum possible population that the least population district could have
a) 10700 b)10800 c) 10900 d) 11000 d) 11100
1) IMO: D
My assumption about the Q is: n = (p^2)q and option D is (p^2)(q^2)
2) IMO: D --> not confident
5C3 * 7C1 = 70
3) IMO: D
This is good one.
Thought Process - If any city has to have the least population, then all other cities should accommodate the extra population with equal distribution.
If we go with D ie. 11000, that means this city is having 1000 less than the ideally equal distribution (ie. 132000/11 = 12000). So, this 1000 has to be distributed equally among rest 10 cities, moving their population to 12100. Difference between 11000 and 12100 is exactly 10%, hence D.
OA Please...
Cheers.
Ankit.
for which of the following functios is f(x) =f(1-x) for all x?
f(x)= 1-x
f(x)= 1-x^2
f(x)= x^2-(1-x)^2
f(x)= x^2(1-x)^2
f(x)= x/1-x
this question is driving me nuts..... i can't even understand the meaning of question , what its asking anyway?
I wud go with option 4 for the above q.
We need to check if f(x) = f(1-x)
f(x) = x^2(1-x)^2
f(1-x) = (1-x)^2 (x^2) = f(x)
38,69,22,73,31,47,13,82
Which of the following numbers is greater than three fourths of the numbers but less than one-fourth of the number in the number list above ?
56
68
69
71
73
Lets first arrange them in ascending order
we get : 13,22,31,38,47,69,73,82.
We have to find a number which is greater than 6 of the nos and less than of nos in the above list.So the no must lie between 69 and 73.From the options only 71 satisfies the above condition.
I wud go with option D)71
If x, y, and k are positive numbers such that (x/x+y)(10) + (y/x+y)(20) = k and if x A. 10
B. 12
C. 15
D. 18
E. 30
------------------------------------------------------------------------------------------------------------
need expln..
Can u please correct the q :(yxx+)(10) + (yxy+)(20)
1) IMO: D
My assumption about the Q is: n = (p^2)q and option D is (p^2)(q^2)
2) IMO: D --> not confident
5C3 * 7C1 = 70
3) IMO: D
This is good one.
Thought Process - If any city has to have the least population, then all other cities should accommodate the extra population with equal distribution.
If we go with D ie. 11000, that means this city is having 1000 less than the ideally equal distribution (ie. 132000/11 = 12000). So, this 1000 has to be distributed equally among rest 10 cities, moving their population to 12100. Difference between 11000 and 12100 is exactly 10%, hence D.
OA Please...
Cheers.
Ankit.
OA 1)D 2)D 3)D u got all 3 right can u explain the first one