ndhadha Sayscan u pls share ur approach...
x is the sum of y consecutive integers. w is the sum of z consecutive integers. If y = 2z, and y and z are both positive integers, then each of the following could be true EXCEPT
A) x = w
B) x > w
C) x/y is an integer
D) w/z is an integer
E) x/z is an integer
Pls explain ur approach
x is the sum of y consecutive integers. w is the sum of z consecutive integers. If y = 2z, and y and z are both positive integers, then each of the following could be true EXCEPT
A)x = w
B)x > w
C)x/y is an integer
D)w/z is an integer
E)x/z is an integer
Pls explain ur approach
regarding ths...
i jus assumed a value of z.. den we can get value of y... nw chck for a set of consecutive numbers...
say we r taking z=3
den y=6
nw we can chck for ne set of 6 consecutive numbers....
every case can b satisified according to ur diff choice of the set of numbers....
but A will nt get satisfied...
if u go by neoder approach... jus let me kno... pls..
Option A will get satisfied with the below values
y = 6(0-5); x = 15;
z = 3 w = 15(4,5,6)
So, x = w
Bhavin,
Thanks for the solution. It is simple and effective approach.
But, when I worked on this problem, my thought did not take me towards using relative speed. So I was wondering what is wrong with my approach.
Please be patient and evaluate for my sake:
B traveled for 10 hrs before A was brought into picture.
From that point,
Let us say A and B meet at a point on the circle.
Distance traveled by B is : x ; So time taken by B is : x/2
Distance traveled by A is : 20pi -x ; so time taken by A is: (20pi -x) /2
Equating these two and solving for x we get x = 8pi
So, B traveled 8pi and A traveled 12pi.
From this point, let y be the distance that B travels, until the point when A travels some distance so that they both are 12 miles apart.
Let t be the time of travel for the above.
Based on the rates:
For B: (8pi + y) / t = 2
For A: (12pi + 12 - y)/t = 3
Solving we get y = 24/5, so t = 2.4
So,
time taken by B would be time taken for it to cover 8pi distance + t
8pi distance takes 4pi hours for B to cover.
So 4pi + t = 4pi + 2.4
Overall time for B therefore is: 4pi + 2.4 + original 10, 4pi + 12.4
Obviously I went wrong somewhere. Where ?
Can you pour in your thoughts please !!
for the 2nd one....
we can select exactly 2 women out of 5 in 5C2 ways... den d remainin member will b men... so 3C2 ways...
we multiply both nd divide the number of ways in which we can select 4 member out of d total 8 employees....
so answer will be... (3C2 * 5C2)/8C4....
i hope i made maself clear.. if nt.. feel free to ask again...:-P
x is the sum of y consecutive integers. w is the sum of z consecutive integers. If y = 2z, and y and z are both positive integers, then each of the following could be true EXCEPT
A)x = w
B)x > w
C)x/y is an integer
D)w/z is an integer
E)x/z is an integer
Pls explain ur approach
Try these
1) A certain company employs 6 seniors and 4 juniors. If a committee to be created is made up of 3 seniors and 1 junior,how many different committees are possible
1) 8 2) 24 3) 58 4) 80 5) 210
2) A tree of 4feet tall is planted. Its height increases by constant amount each year for next 6 years. At end of 6th year, tree was 1/5th taller than it was at end of 4th year. By how many feet height increases each year
1) 3/10 2) 2/5 3) 1/2 4) 2/3 5) 6/5
Plz try to explain
2) A tree of 4feet tall is planted. Its height increases by constant amount each year for next 6 years. At end of 6th year, tree was 1/5th taller than it was at end of 4th year. By how many feet height increases each year
1) 3/10 2) 2/5 3) 1/2 4) 2/3 5) 6/5
Plz try to explain
Try these
1) A certain company employs 6 seniors and 4 juniors. If a committee to be created is made up of 3 seniors and 1 junior,how many different committees are possible
1) 8 2) 24 3) 58 4) 80 5) 210
A hiker walking at a constant rate of 4mph is passed by a cyclist traveling in the same direction along the same path at a constant rate of 20mph. The cyclist stops to wait for the hiker 5 min after passing her, while the hiker continues to walk.How many minutes must the cyclist wait until the hiker catches up?
A. 6 2/3
B. 15
C. 20
D. 25
E. 26 2/3
In 5 mins,the cyclist would have travelled 5/3 miles.
At the sametime(5mins), walker could have walked : 1/3 miles.Now,the distance b/wn them would be 4/3 miles.
Walker walks @ 4mph.He could travel 4/3 miles in 4/12*60 = 20 mins
I wud go with option C
A hiker walking at a constant rate of 4mph is passed by a cyclist traveling in the same direction along the same path at a constant rate of 20mph. The cyclist stops to wait for the hiker 5 min after passing her, while the hiker continues to walk.How many minutes must the cyclist wait until the hiker catches up?
A. 6 2/3
B. 15
C. 20
D. 25
E. 26 2/3
double post..
A hiker walking at a constant rate of 4mph is passed by a cyclist traveling in the same direction along the same path at a constant rate of 20mph. The cyclist stops to wait for the hiker 5 min after passing her, while the hiker continues to walk.How many minutes must the cyclist wait until the hiker catches up?
A. 6 2/3
B. 15
C. 20
D. 25
E. 26 2/3
A tree of 4feet tall is planted. Its height increases by constant amount each year for next 6 years. At end of 6th year, tree was 1/5th taller than it was at end of 4th year. By how many feet height increases each year
A) 3/10 B) 2/5 C) 1/2 D) 2/3 E) 6/5
A hiker walking at a constant rate of 4mph is passed by a cyclist traveling in the same direction along the same path at a constant rate of 20mph. The cyclist stops to wait for the hiker 5 min after passing her, while the hiker continues to walk.How many minutes must the cyclist wait until the hiker catches up?
A. 6 2/3
B. 15
C. 20
D. 25
E. 26 2/3
A tree of 4feet tall is planted. Its height increases by constant amount each year for next 6 years. At end of 6th year, tree was 1/5th taller than it was at end of 4th year. By how many feet height increases each year
A) 3/10 B) 2/5 C) 1/2 D) 2/3 E) 6/5