forgot to mention the metholdogy.Let take the case of 8^1/4 and 12^ 1/5
This can also be written as 8 ^ (5/20) and 12 ^ ( 4/20).
Now , ^ 1/20 and ^ 1/20
compare 8^5 and 12^ 4 . 12^ 4 is less than 8^ 5..So 12^ 1/5 is less than 8^1/4.
Follow the same method for the other options as well.
im getting the ans as E... any one for support
Puys help me with this DS question..
The numbers x and y are not integers. The value of x is closest to which integer ?
1.) 4 is the integer which is closest to x+y
2.) 1 is the integer which is closest to x-y
Puys help me with this DS question..
The numbers x and y are not integers. The value of x is closest to which integer ?
1.) 4 is the integer which is closest to x+y
2.) 1 is the integer which is closest to x-y
Statement 1:
==========
certainly nut suff to ans the q,as x and y can be +ve or -ve
Statement 2:
==========
Nt suff to ans the q,as x and y can be +ve or -ve
combining both the statements we can get 2 possible values:
(i) x = 2.6 y = 1.5 ====> x is close to 3
(ii) x = 2.4 , y = 1.5 ====> x is close to 2
So my take is option E
Puys help me with this DS question..
The numbers x and y are not integers. The value of x is closest to which integer ?
1.) 4 is the integer which is closest to x+y
2.) 1 is the integer which is closest to x-y
IMO E
wats the OA?
Puys help me with this DS question..
The numbers x and y are not integers. The value of x is closest to which integer ?
1.) 4 is the integer which is closest to x+y
2.) 1 is the integer which is closest to x-y
statement 1 : 3.5 No idea about y,insufficient by itself.
=======================================================
statement 2 means that 0.5 this likewise tells us nothing about the individual values of x and y ,insufficient by itself.
=========================================================
together, we can add inequalities,to get rid of 'y'
this gives
3.5 0.5 add
4 therefore
2
this is still insufficient, because x could be closer to 2, closer to 3, or neither (if it's exactly in the middle, at 2.5).
ans : E
Help in another sitter...
If p and q are consecutive natural nos (in increasing order), then which of the following is true?
a. q^2
p
c. (q+1)^2 > p^2
d (p+2)^3
If i am not wrong, natural nos are positive nos starting from 1. In that case option b and c, both seem to satisfy.
However the OA is option C.
Am i missing out on something.
Help in another sitter...
If p and q are consecutive natural nos (in increasing order), then which of the following is true?
a. q^2p
c. (q+1)^2 > p^2
d (p+2)^3
If i am not wrong, natural nos are positive nos starting from 1. In that case option b and c, both seem to satisfy.
However the OA is option C.
Am i missing out on something.
I suppose there is a flaw in option B in the above q
Could you explain in detail how you got the answer as 80% please.
Puys help me with this DS question..
The numbers x and y are not integers. The value of x is closest to which integer ?
1.) 4 is the integer which is closest to x+y
2.) 1 is the integer which is closest to x-y
Statement 1 is Not Sufficient
x + y = 4
x could be 2.2 and y 1.8, meaning y = 2
OR x could be 0.1 and y could be 3.8, meaning y = 4
Statement 2 is Not Sufficient
x -y = 1
x could be 1.1 and y = 0.1, y closest to 0
x could be 4.2 and y = 3,2, y closest to 3
Same reasoning applies to evaluating C...Correct = E
Help in another sitter...
If p and q are consecutive natural nos (in increasing order), then which of the following is true?
a. q^2p
c. (q+1)^2 > p^2
d (p+2)^3
If i am not wrong, natural nos are positive nos starting from 1. In that case option b and c, both seem to satisfy.
However the OA is option C.
Am i missing out on something.
please check if second option is 2p>p or 2p > q.
There is a 10% chance that it won^t snow all winter long. There is a 20%
chance that schools will not be closed all winter long. What is the greatest
possible probability that it will snow and schools will be closed during the
winter?
(A) 55%
(B) 60%
(C) 70%
(D) 72%
(E) 80%
How is the answer 80% for this ? Please could anybody explain this clearly.This was discussed in the earlier posts but I didn't quite understand.
Alright this is from my IMS Gmat Prep material and I am posting on prob solving thread for the first time. I am bad at quant.
1. X, Y & Z are moving along a circular path of 500 yards and speeds 10, 20 & 45 yards/ minute respectively. All three of them start from the same point and move in the same direction. When and where will all three of them meet for the first time?
2. At what time after 2 O Clock the hour hand and the minute hand of a clock forms a right angle?
3. If 12 persons can a do a job in 18 days then 15 persons with thrice the efficiency can do the same job in how many days?
I would suggest not to solve these Q without multiple choice options as it is time consuming. But We can still find answers:-
1. X and Y with speed 10 and 20 will meet exactly after 2 rounds and will keep on meeting after every 2 rounds. So, Now we have to check where is Z when X and Y meet 1st time.
Distance covered by Z = SxT => 45*20 => 900
Next time X,Y meet - Dist. covered by Z => 45*40 => 1800
... Finally all three will meet when X covers 4500 after 100 mins..
2. should be at 2:27 (much easier if we have choices)
3. 3*15*X = 18*12 ==> X = 4.8 => 5 days
(efficiency * no of people * number of days is used in eqn.)
Alright this is from my IMS Gmat Prep material and I am posting on prob solving thread for the first time. I am bad at quant.
1. X, Y & Z are moving along a circular path of 500 yards and speeds 10, 20 & 45 yards/ minute respectively. All three of them start from the same point and move in the same direction. When and where will all three of them meet for the first time?
2. At what time after 2 O Clock the hour hand and the minute hand of a clock forms a right angle?
3. If 12 persons can a do a job in 18 days then 15 persons with thrice the efficiency can do the same job in how many days?
Thanks Nipunbans,
I would have loved to put in the options but there weren't any.
Help in another sitter...
If p and q are consecutive natural nos (in increasing order), then which of the following is true?
a. q^2p
c. (q+1)^2 > p^2
d (p+2)^3
If i am not wrong, natural nos are positive nos starting from 1. In that case option b and c, both seem to satisfy.
However the OA is option C.
Am i missing out on something.
Take 2 cases - Case 1 => p=1; q=2 and Case 2 => p=3; q=4
(a) => sq 2 (Wrong; No need to check the second case)
(b) It should be 2p>q => Case 1 --- 2 X 1 > 2 (Wrong)
(c) => (2+1)^2 > 2^ 2 (True, try the second case as well, it will also be true)
(d) => try this one also, will come Wrong.
Hence, Answer is 'C'
coolmia SaysCould you explain in detail how you got the answer as 80% please.
In question, nowhere it is mentioned that the two events are independent.
Means, there may be the case that the probability of snow is different for
the case when schools are closed from the case when schools are not closed.
But, as the question asks for greatest probability of schools closed and it
snows, we should look for maximum number of cases for this event to happen.
And this will be in the case when for 80 cases with schools closed, we
assume that it will rain.
hence, greatest probability is 80%.
deepakraam SaysOA please.
OA : C
Explanation :
ab = 30x
Means, x = ab / 30.
To find if x is not an integer.
*Taking 1)*
a^2 is divisible by 21.
say a^2 = 21 * y
means a = sqrt(21) * sqrt(y)
as it is given that 'a' is an integer.this means, sqrt(y) must be a multiple
of sqrt(21), say y = sqrt(21) * p, where p is an integer
hence, a = sqrt(21) * sqrt(21) * p = 21p
as a and b are consecutive integers
say b = 21p + 1 ( Note : b may also equal 21p-1 )
x = ab / 30
x = 21p * (21p+1) / 30
Checking values of x for p = 1 and 5, we get x as non-integer and integer
resp.
hence 1) is not sufficient.
*Now taking 2)*
as done for 1) , b = 35q where q is an integer
x = 35q * (35q+1) / 30
Checking values of x for q = 1 and 2, we get x as integer and non-integer
resp.
hence 2) is not sufficient
*Taking 1) and 2) together.*
a=21p=3*7*p
b=35q=5*7*q
ab=3*5*7*7*p*q
Hence x = ab/30 = 49pq/2
Now as we know that 'a' and 'b' are consecutive integers, either of the two
is even. Hence either of 'p' or 'q' is a multiple of 2.
this means x is an integer
Ans is C.
It took Ellen 6 hours to ride her bike a total distance of 120 miles.
For the first part of the trip, her speed was constantly 25 miles per hour.
For the second part of her trip, her speed was constantly 15 miles per hour. For how many miles did Ellen travel at 25 miles per hour?
(A) 60
(B) 62.5
(C) 66 2/3
(D) 75
(E) 80
It took Ellen 6 hours to ride her bike a total distance of 120 miles.
For the first part of the trip, her speed was constantly 25 miles per hour.
For the second part of her trip, her speed was constantly 15 miles per hour. For how many miles did Ellen travel at 25 miles per hour?
(A) 60
(B) 62.5
(C) 66 2/3
(D) 75
(E) 80
D= 120 miles; Time = 6hrs
Let the time taken for first part be "x" hrs.
25x + 15(6-x) = 120
10x = 30
x = 3hrs
First part = 75 miles
Second part = 45 miles