Right triangle LMN is to be constructed in the xy-plane so that the right angle is at point L and LM is parallel to the x-axis. The x- and y- coordinates of L, M, and N are to be integers that satisfy the inequalities -3 (A) 72 (B) 576 (C) 4032 (D) 4608 (E) 6336
I guess there is an error in this sum buddy ...it shud be an inclusive range i.e less than or equal to ...onlythen correct answer appears in the ans option ...
Similar sum in OG 12 ...sum 229 ..
Answer C
Explanation : Permissible x values : 8 permissible y values : 9
So L can take any of the 8*9 = 72 points formed by rectangular grid
M has same y value, so it can take any of the rem 8 values .. N has same x value, so it can take any of the rem 7 values
Right triangle LMN is to be constructed in the xy-plane so that the right angle is at point L and LM is parallel to the x-axis. The x- and y- coordinates of L, M, and N are to be integers that satisfy the inequalities -3 (A) 72 (B) 576 (C) 4032 (D) 4608 (E) 6336
My answer does not match any of the choices. Please correct me where I am going wrong !! :banghead:
--------------- L shares the same y coordinate with M L shares the same x coordinate with N
x = {-2,-1,0,1,2,3} y={4,5,6,7,8,9,10}
Total coordinate combinations that L can have is 6*7 = 42 For each of these, M can have the same y, and diff x in: 5 ways For each of L, N can have the same x, and diff y in: 6 ways.
My answer does not match any of the choices. Please correct me where I am going wrong !! :banghead:
--------------- L shares the same y coordinate with M L shares the same x coordinate with N
x = {-2,-1,0,1,2,3} y={4,5,6,7,8,9,10}
Total coordinate combinations that L can have is 6*7 = 42 For each of these, M can have the same y, and diff x in: 5 ways For each of L, N can have the same x, and diff y in: 6 ways.
So overall: 42 * 5 * 6 = 1260 --------------
Perfect analysis vikram ...nothing wrong with your approach ....for the given sum, 1260 is absolutely correct ...
I guess it should be -3Then will have 2 additional pts fr each x and y ... Hence, 4032
Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5 ? A. 1/6 B. 1/5 C. 1/3 D. 2/5 E. 2/3
Ya this indeed was a simple problem. I myself made it look more tough or messed up by considering the individual probabilities of choosing each card (3,5)(5,3)(4,4)(2,6)(6,2)
Right triangle LMN is to be constructed in the xy-plane so that the right angle is at point L and LM is parallel to the x-axis. The x- and y- coordinates of L, M, and N are to be integers that satisfy the inequalities -3 (A) 72 (B) 576 (C) 4032 (D) 4608 (E) 6336
Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5 ? A. 1/6 B. 1/5 C. 1/3 D. 2/5 E. 2/3
hi all, what's the best material for quant prep for the gmat apart from kaplan & OG-12? am aiming for a full score in the quant section!! looking forward to hearing from you, puys!!
I guess there is an error in this sum buddy ...it shud be an inclusive range i.e less than or equal to ...onlythen correct answer appears in the ans option ...
Similar sum in OG 12 ...sum 229 ..
Answer C
Explanation : Permissible x values : 8 permissible y values : 9
So L can take any of the 8*9 = 72 points formed by rectangular grid
M has same y value, so it can take any of the rem 8 values .. N has same x value, so it can take any of the rem 7 values
Total poss triangles = 72 * 8*7 = 4032 ..Ans C
yup ..absolutely correct... i think when i pasted the problem.. the = didnt appear somehow..
2. The function f is defined for each positive three-digit integer n by f(n) = 2^x3^y5^z , where x, y and z are the hundreds, tens, and units digits of n, respectively. If m and v are three-digit positive integers such that f(m)=9f(v), them m-v=? (A) 8 (B) 9 (C) 18 (D) 20 (E) 80
2. The function f is defined for each positive three-digit integer n by f(n) = 2^x3^y5^z , where x, y and z are the hundreds, tens, and units digits of n, respectively. If m and v are three-digit positive integers such that f(m)=9f(v), them m-v=? (A) 8 (B) 9 (C) 18 (D) 20 (E) 80
ahh ...missed this question earlier .. IMO ans is D ..
N = 2^x*3^y*5^z and also N = 100x+10y+z
Let x1, y1, z1 and x2, y2, z2 be the powers of 2,3 and 5 for m and v resp
So, F(m)= 2^x1 *3^y1 * 5^z1 and F(v) = 2^x2*3^y2*5^z2
2. The function f is defined for each positive three-digit integer n by f(n) = 2^x3^y5^z , where x, y and z are the hundreds, tens, and units digits of n, respectively. If m and v are three-digit positive integers such that f(m)=9f(v), them m-v=? (A) 8 (B) 9 (C) 18 (D) 20 (E) 80
I sooo agree with you!! but the OA is 360.. using permutations... and i have no clue why!! :-(
fyi - the ques is from a score800 test..
wordings could be tricky sometimes ...but i still feel it cannot be 6P4
if the 4 choices are idli, dosa, utappa and wada ...problem wordings imply it does not matter who has ordered what ....coz it is not a different order ..
In this question the key is words "nobody orders the same meal". This means order, although not mentioned, is to be kept in mind while solving this question.
A-can order from 6 choices B-has now only 5 choices to select from C-has 4 after B has selected D-has 3 choices after C has selected
Total - 6*5*4*3 = 360. So order came into play.
I hope this helps.
A family of 4 is at a restaurant with 6 choices on the menu. If nobody orders the same meal, how many possible combinations of meals could they order?
A) 15
B) 30
C) 60
D) 180
E) 360
pls provide explanation... thanks
Pure combinations ...internal pattern of choices does not matter
6C4 = 15 ..Option A
wordings could be tricky sometimes ...but i still feel it cannot be 6P4
if the 4 choices are idli, dosa, utappa and wada ...problem wordings imply it does not matter who has ordered what ....coz it is not a different order ..
I sooo agree with you!! but the OA is 360.. using permutations... and i have no clue why!! :-(
