What range of values of x will satisfy the inequality 2x + 3 > 7x - 2?
A. x 5
B. -1 C. (-1/9) D. (-1/9) E. x 1
Answer shd be C
I applied Hit and trail method.
If x=1, LHS = RHS
If x=2, LHS If x=0, inequality satisfies. Moreover higher values of x will make RHS big and we don't want that.
You can determine th e answer "C"
Plz try the below and explain
How many positive integers between 200 and 300 (both inclusive) are not divisible by 2, 3 or 5?
A. 3
B. 16
C. 75
D. 24
E. 26
Want to see if there is a smarter way to do the below other than normal computing.
If Dave works alone he will take 20 more hours to complete a task than if he worked with Diana to complete the task. If Diana works alone, she will take 5 more hours to complete the complete the task, then if she worked with Dave to complete the task? What is the ratio of the time taken by Dave to that taken by Diana if each of them worked alone to complete the task?
A. 4 : 1
B. 2 : 1
C. 10 : 1
D. 3 : 1
E. 1 : 2
ans : B
Plz try the below and explain
How many positive integers between 200 and 300 (both inclusive) are not divisible by 2, 3 or 5?
A. 3
B. 16
C. 75
D. 24
E. 26
Ans E ..26
3 way venn diagram intersection
total integers neither div by 2,3,5 = total nos - union of div by 2,3,5
= 101 - union of 3 way venn diag
Now,
Numbers divisible by 2 + Numbers Divisible by 3 + Numbers divisible by 5
-Numbers divisible by 2 and 3(ie 6)
-Numbers divisible by 3 and 5 (ie 15)
-Numbers divisible by 2 and 5(ie 10)
+Numbers divisible by 2,3 and 5(ie 30)
Now Numbers divisible by 2 = 51(Since it includes both 200 and 300)
Numbers divisible by 3 = 34 (ie,201-300)
Numbers divisible by 5 = 21 (inclusive of both 200 and 300)
Numbers divisble by 6 = 17
Numbers divisible by 10 = 11 (inclusive of both 200 and 300)
Numbers divisible by 15 = 7
Numbers divisble by 30 = 4
Therefore, union is
51+34+21-(17+11+7)+4
=110-35
=75
Hence, neither div by 2,3 or 5 is 101 - 75 =26 ..
Next sum later
Want to see if there is a smarter way to do the below other than normal computing.
If Dave works alone he will take 20 more hours to complete a task than if he worked with Diana to complete the task. If Diana works alone, she will take 5 more hours to complete the complete the task, then if she worked with Dave to complete the task? What is the ratio of the time taken by Dave to that taken by Diana if each of them worked alone to complete the task?
A. 4 : 1
B. 2 : 1
C. 10 : 1
D. 3 : 1
E. 1 : 2
ans : B
Ans B ..
Let Dave take x days and diana take y days alone to complete the job
Hence, combined would be , xy/(x+y)
By data,
x - = 20 implies x^2/(x+y) = 20
likewise, y^2/(x+y) = 5
Hence, x^2/y^2 = 4
i.e x/y = 2:1
Shorter method wud be appeciated !
The annual interest rate earned by an investment increased by 10 percent from last year to this year. If the annual interest rate earned by the investment this year was 1 percent, what was the annual interest rate last year?
A. 1% B. 1.1% C. 9.1% D. 10% E. 10.8%
The annual interest rate earned by an investment increased by 10 percent from last year to this year. If the annual interest rate earned by the investment this year was 1 percent, what was the annual interest rate last year?
A. 1% B. 1.1% C. 9.1% D. 10% E. 10.8%
110/100 * X = 1
X = 100/110
= 9.1%..IMO C)...only when i'm drunk...
has to be...
X = 100/110 = 0.91%..
Cheers
The annual interest rate earned by an investment increased by 10 percent from last year to this year. If the annual interest rate earned by the investment this year was 1 percent, what was the annual interest rate last year?
A. 1% B. 1.1% C. 9.1% D. 10% E. 10.8%
110/100 * x = 1
x = 100/110 = .909 %
no option satisfies :
amsey1382
: Please read the line in red above , if i read it right the number should be less than 1 😐 u got 9.09% :
please correct me if i am wrong
A. 1% B. 1.1% C. 9.1% D. 10% E. 10.8%
110/100 * x = 1
x = 100/110 = .909 %
no option satisfies :
amsey1382
: Please read the line in red above , if i read it right the number should be less than 1 😐 u got 9.09% : please correct me if i am wrong
X = 100/110
= 9.1%..IMO C) ------------ THis is wrong..
right hand side is alreadt in %age. and 100/110 = .91 %..
The annual interest rate earned by an investment increased by 10 percent from last year to this year. If the annual interest rate earned by the investment this year was 1 percent, what was the annual interest rate last year?
A. 1% B. 1.1% C. 9.1% D. 10% E. 10.8%
110/100 * x = 1
x = 100/110 = .909 %
no option satisfies :
amsey1382
please correct me if i am wrong :biggrin:
nope buddy u r perfectly right....i think, i need a break....;-)
The annual interest rate earned by an investment increased by 10 percent from last year to this year. If the annual interest rate earned by the investment this year was 1 percent, what was the annual interest rate last year?
A. 1% B. 1.1% C. 9.1% D. 10% E. 10.8%
110/100 * x = 1
x = 100/110 = .909 %
no option satisfies :
amsey1382
please correct me if i am wrong :biggrin:
The same solution as given by amsey is at :
http://www.pagalguy.com/discussions/gmat-problem-solving-discussions-25019823
I guess I didnot understand the basic crux .....
Thanks.
The annual interest rate earned by an investment increased by 10 percent from last year to this year. If the annual interest rate earned by the investment this year was 1 percent, what was the annual interest rate last year?
A. 1% B. 1.1% C. 9.1% D. 10% E. 10.8%
110/100 * x = 1
x = 100/110 = .909 %
no option satisfies :|
let me help u understand ..
if u have a chocolate which costed u 9 rs last year , and this year its 10 rs then the percent increase would be ?
( (10 -9) / 9 ) * 100 .... = x %
same here !!
here instead of x it is given as 10% instead of 10rs itz given as 1% and instead of 9 they asked u C(u need to find it out )
P.S carefully read the explanation again n again ...write downthe question and solution on a paper 😁 n redo it re-read it if u still dnt understand PM me :D
A. 1% B. 1.1% C. 9.1% D. 10% E. 10.8%
110/100 * x = 1
x = 100/110 = .909 %
no option satisfies :|
let me help u understand ..
if u have a chocolate which costed u 9 rs last year , and this year its 10 rs then the percent increase would be ?
( (10 -9) / 9 ) * 100 .... = x %
same here !!
here instead of x it is given as 10% instead of 10rs itz given as 1% and instead of 9 they asked u C(u need to find it out )
P.S carefully read the explanation again n again ...write downthe question and solution on a paper 😁 n redo it re-read it
if u still dnt understand PM me :D
The annual interest rate earned by an investment increased by 10 percent from last year to this year. If the annual interest rate earned by the investment this year was 1 percent, what was the annual interest rate last year?
A. 1% B. 1.1% C. 9.1% D. 10% E. 10.8%
This year interest rate is 1% and its more than last years interest rate,It means last years rate would be lower than this year rates.
seeing the option i am not sure what will be the answer(
Puys, some more...
1. Heights of women in a city follows a normal distribution with mean 160 cm and standard deviation of 6 cm. In a normal distribution, only 0.0063% of the population is not within 4 standard devistions of the mean. If 5 women are more than 184 cm tall, approximately how many women stay in the city?
a>16000
b>40000
c>80000
d> 100,000
e> 160,000
2. How many positive integers less than 100 have exactly 4 odd factors and no even factors?
a>13
b>14
c>15
d>16
e>17
Puys, please explain ur methods
the OA are as follws:
1.E
2.C
Are you sure these are GMAT questions?
I feel these have more dificulty level than GMAT , I feel these are CAT questions buddy.
Please confirm.
Are you sure these are GMAT questions?
I feel these have more dificulty level than GMAT , I feel these are CAT questions buddy.
Please confirm.
Could not find Arijit's post ...hence quoted youes pj02.
The second one could be a GMAT problem...I have not worked on the solution though.
-> the basic logic behind this seems to be any number which is less than 100 and is product of two prime no's will fit the bill.
Thanks.
( mama,i know nothing about the distribution's ...even Papa Ji can not save me 😞 )
Hey Puys,
If one one has any doc's on the distribution or standard deviation which could help to solve the problems like above ...pls post ( urgently 😁 )
Regards,
Papa Ji
PG Rocks!
Could not find Arijit's post ...hence quoted youes pj02.
The second one could be a GMAT problem...I have not worked on the solution though.
-> the basic logic behind this seems to be any number which is less than 100 and is product of two prime no's will fit the bill.
Thanks.
( mama,i know nothing about the distribution's ...even Papa Ji can not save me 😞 )
Hey Puys,
If one one has any doc's on the distribution or standard deviation which could help to solve the problems like above ...pls post ( urgently 😁 )
Regards,
Papa Ji
PG Rocks!
Thank you papa ji... But i think First one you can say is GMAT problem as standard deviation is involved and in CAT standard deviation is not in syllabus.
Anyways... i found both question hard and think that they are not GMAT problems...
Papaji,
The approach you described for problem 2 sounds correct but I am not getting the right answer. Below is what I get.
Listing down prime nos( except 2):
3 , 5, 7, 11, 13, 17 , 19 , 23, 29, 31, 37
Starting with 3, we get 9 possible numbers( after multiplying 3 with prime nos upto 31 only because 37*3=111 >100)
Similarly for 5, we get 5 numbers( multiplying upto 19)
For 7, we get 2 ( multiplying upto 13)
No numbers after 7 is applicable.
Hence I get a total of 9 + 5 + 2= 16 but the ans as it seems is 15.
Could not find Arijit's post ...hence quoted youes pj02.
The second one could be a GMAT problem...I have not worked on the solution though.
-> the basic logic behind this seems to be any number which is less than 100 and is product of two prime no's will fit the bill.
Thanks.
( mama,i know nothing about the distribution's ...even Papa Ji can not save me 😞 )
Hey Puys,
If one one has any doc's on the distribution or standard deviation which could help to solve the problems like above ...pls post ( urgently 😁 )
Regards,
Papa Ji
PG Rocks!
Even I followed the same approach.
N = (a^p) * (b^q) * (c^r)
where a,b,c are prime nos and p,q,r are positive integers
N
So, p=1 and q=1.
the prime factors can be 3,5,7....33(only prime nos).
So we get a total of 16 nos.
Are you sure these are GMAT questions?
I feel these have more dificulty level than GMAT , I feel these are CAT questions buddy.
Please confirm.
Could not find Arijit's post ...hence quoted youes pj02.
The second one could be a GMAT problem...I have not worked on the solution though.
-> the basic logic behind this seems to be any number which is less than 100 and is product of two prime no's will fit the bill.
Hey Puys,
If one one has any doc's on the distribution or standard deviation which could help to solve the problems like above ...pls post ( urgently 😁 )
Regards,
Papa Ji
PG Rocks!
Hello Guys ...u can ver well expect SD on GMAT ...its not out of syllabus ...
All the 3 questions posted by arijit have been answered long back ...
And For prime factors, my Ans is 17 ...
Here are the links for reference:
http://www.pagalguy.com/forum/gmat-and-related-discussions/19823-gmat-problem-solving-discussions-267.html#post1609572
Hello Guys ...u can ver well expect SD on GMAT ...its not out of syllabus ...
All the 3 questions posted by arijit have been answered long back ...
And For prime factors, my Ans is 17 ...
Here are the links for reference:
http://www.pagalguy.com/forum/gmat-and-related-discussions/19823-gmat-problem-solving-discussions-267.html#post1609572
How dd u get 17 for the prime factors?