A room has the following dimensionz..
Length : 6 metres
Breadth : 6 metres
Height : 5 metres
an Ant which is @ one end of the longest diagonal needs to reach the other end of the diagonal in the shortest possible path ..!!
whats the length of the shortest path ?
A room has the following dimensionz..
Length : 6 metres
Breadth : 6 metres
Height : 5 metres
an Ant which is @ one end of the longest diagonal needs to reach the other end of the diagonal in the shortest possible path ..!!
whats the length of the shortest path ?
isnt it the diagonal distance?sqrt(36+36+25)
guy with guts Saysisnt it the diagonal distance?sqrt(36+36+25)
I again thought of this in different light.
The answer will be little less then the main diagonal.I calculate by using maxima and minima funda and landed with 9.4 as answer.
here its assumed that ant will travel only through end to end diagonal but one possibility exists whr its travelling through a different path digonally.
One more:
A Rectangular Box is ten inches long, ten inches wide and half that in depth. What is the longest possible distance between any two points on this box.
A) 20
B) 25
C) 10 root 2
D) 15
E) 10 root 3
We are looking for the longest distance, so start from point, travel along the side to the diagonally opposite point (10+10), and then travel along the depth to reach the point, which is the end point of the main diagonal of the rectangular room.
Hence 10 + 10 + 5 = 25
B.
Any takers?
We are looking for the longest distance, so start from point, travel along the side to the diagonally opposite point (10+10), and then travel along the depth to reach the point, which is the end point of the main diagonal of the rectangular room.
Hence 10 + 10 + 5 = 25
B.
Any takers?
the longest distance will be the main diagonal only
sqrt(100*2+25)=15
Q-1 1.61 .No option in the answer( even I was surprised when I took theTest and found this question as wrong...). Any puy pls help if he finds the answer in the option.
Q-2 No. of integers between two no.s={(198-102)/3}+1=33
Q-3 2/3 of x(total games)=17+3=20
x=30
team has already played 2/3 of 30 =20 games
remaining are 10 games
atleast 3/4 of 30=22.5 games to win.take it as 23 games.
7 games total lost. 3 are already lost.
So max 4 games the team can loose.
Q-4 Please some puy help in solving it.
Hardback -- Paperback
36K -- 0
y -- 9(y+36k)
(y+36k) + 9(y+36k) = 441,000
y = 8.1K
Paperback = 9(y+36k) = 396,900
Q-5
eggs sold in may=x
eggs sold in april=2/3 of x=2x/3
eggs sold in june=2(2x/3)=4x/3
Av price over 3 mnths=x(1.2)+(2x/3)*(1.26)+(4x/3)*(1.08 )=3.48x
No. of eggs sold over 3 mnths=3x
Av price per dozen over 3 mnths=1.16
I agree with rest all the answers.
See one explanation embedded in red.
the longest distance will be the main diagonal only
sqrt(100*2+25)=15
We are not asked the longest diagonal, but the longest possible distance that can be traversed between any 2 points.
Why is that not the case?
Hi Pearlcrystal,
For the paperback q prlm says "From the time the first paperback copy was sold until the last copy of the novel was sold"-This clearly should not include the 36k hardcopies already sold.
ardback -- Paperback
36K -- 0
y -- 9(y+36k)
(y+36k) + 9(y+36k) = 441,000
y = 8.1K
Paperback = 9(y+36k) = 396,900
We are looking for the longest distance, so start from point, travel along the side to the diagonally opposite point (10+10), and then travel along the depth to reach the point, which is the end point of the main diagonal of the rectangular room.
Hence 10 + 10 + 5 = 25
B.
Any takers?
I too agree with the answer and the explanation.
Find how many roots satisfy both the below equations:
x(pow)3+6x(pow)2+x+5 = 0.
x(pow)3+5x(pow)2+6x+1 = 0.
1. One
2. Two
3. Three
4. Four
5. None.
At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?
(A) $0.30
(B) $0.45
(C) $0.60
(D) $0.75
(E) $0.90
OA: E (I had 1.62, seems like the choices are wrong.)
-----------------------------
What is the total number of integers between 100 and 200 that are divisible by 3?
(A) 33
(B) 32
(C) 31
(D) 30
(E) 29
OA: A
-----------------------------
A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3
OA: D
-----------------------------
There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441,000 copies of the novel were sold in all, how many paperback copies were sold?
(A) 45,000
(B) 360,000
(C) 364,500
(D) 392,000
(E) 396,900
OA: E
-----------------------------
Month Average Price per Dozen
____________________________________
April | $1.26
May | $1.20
June $1.08
The table above shows the average (arithmetic mean) price per dozen of the large grade A eggs sold in a certain store during three successive months. If 2/3 as many dozen were sold in April as in May, and twice as many were sold in June as in April, what was the average price per dozen of the eggs sold over the three-month period?
(A) $1.08
(B) $1.10
(C) $1.14
(D) $1.16
(E) $1.18
OA: D
I did get all the questions except obviously #1 where the choices are wrong, and #2 for which I took too long and guessed it.
I did see that some of you have used (198-102/3) + 1 for counting integers between any two numbers.
Is this a standard formula? I somehow seem to miss most of the questions of this type.
Please advise.
One more:
A Rectangular Box is ten inches long, ten inches wide and half that in depth. What is the longest possible distance between any two points on this box.
A) 20
B) 25
C) 10 root 2
D) 15
E) 10 root 3
OA: D (15)
I was torn between 15 and 25.
I guess that is what that makes it a tough word problem.
OA: D (15)
I was torn between 15 and 25.
I guess that is what that makes it a tough word problem.
15 is actually the shortest possible distance being the main diagonal.. and 25 is really the longest possible. One can draw the lines and add up the distances to check.. I dont get why the OA says otherwise!
Although, when its an ant crawling problem, the shortest distance between the two end points of the main diagonal is the diagonal of the base of the cube+height, since ants cant crawl along the main diagonal
Find how many roots satisfy both the below equations:
x(pow)3+6x(pow)2+x+5 = 0.
x(pow)3+5x(pow)2+6x+1 = 0.
1. One
2. Two
3. Three
4. Four
5. None.
Two roots 4 and 1.
I did see that some of you have used (198-102/3) + 1 for counting integers between any two numbers.
Is this a standard formula? I somehow seem to miss most of the questions of this type.
Please advise.
Yes Vikram ...It is a standard formula ...
It is actually derived from AP series ..
In AP,
Sum of n terms, Sn = n/2
And, Tn = T1 + (n-1)d
Hence,the no of terms divisible within a given range is derived from second formula ...i.e n =
-----------------------------
There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441,000 copies of the novel were sold in all, how many paperback copies were sold?
(A) 45,000
(B) 360,000
(C) 364,500
(D) 392,000
(E) 396,900
-----------------------------
Q-4 Please some puy help in solving it.
Hi Pearlcrystal,
For the paperback q prlm says "From the time the first paperback copy was sold until the last copy of the novel was sold"-This clearly should not include the 36k hardcopies already sold.
ardback -- Paperback
36K -- 0
y -- 9(y+36k)
(y+36k) + 9(y+36k) = 441,000
y = 8.1K
Paperback = 9(y+36k) = 396,900
shorter way for the same ...
Why bother to find actual sales before and after of launch ..
We know at the end , sales of one is 9 times the other ...
Hence, by ratio Paper back : hardback is 9:1
Hence, paper back is 9/10 * 441000 = 396900
Hi Pearlcrystal,
For the paperback q prlm says "From the time the first paperback copy was sold until the last copy of the novel was sold"-This clearly should not include the 36k hardcopies already sold.
ardback -- Paperback
36K -- 0
y -- 9(y+36k)
(y+36k) + 9(y+36k) = 441,000
y = 8.1K
Paperback = 9(y+36k) = 396,900
From the time the first paperback was sold (36k hardback till now) to the time when the last copy of novel was sold (paper/hard back both) -- then we are given the total copies sold. So I think it should include 36K paperback already sold also.
shorter way for the same ...
Why bother to find actual sales before and after of launch ..
We know at the end , sales of one is 9 times the other ...
Hence, by ratio Paper back : hardback is 9:1
Hence, paper back is 9/10 * 441000 = 396900
Hi Bhavin,
We must care abt the launch time.
Ur calculations can also yield another result when it is done this way : 9/10 *(441000-36000) = 364500
The ratio of 9:1 holds only for certain window and not for total sales period.So they have clearly specified the timeframe they are starting to measure.Else they cud have st mentioned the total sales and ratio.
PearlCrystal SaysFrom the time the first paperback was sold (36k hardback till now) to the time when the last copy of novel was sold (paper/hard back both) -- then we are given the total copies sold. So I think it should include 36K paperback already sold also.
Yes you are correct.The total sales also includes 36k of hard copies sold but the ratio should not include the 36k bcos when their time frame starts 36k copies are already sold and so it doesn't fall under that bracket.
Riva_M SaysTwo roots 4 and 1.
i dont think 1 and 4 both are the roots of the equation :)
aX^3 + bX^2 +C^X +D ..if A B C D r of the same sign ... then the roots r negative(can be imaginary) :)
is the answer NOne ?