Let us say that the Centre of the Circle is X ;
then PXO = 70 degree ( theorem: angle at the centre is double the circumference)
Now let us find QOR ;
as PQ is // to OR ;PQRO is an isosceles trapezium ,and hence PO = QR
so , PRO= QOR = 35 degrees;
Since QOR = 35 degrees ; QXR = 70 degrees (theorem : same as above)
Now that means PXQ= 40 degrees( angle of st line is 180 degrees)
SO,
Measure of Minor arc PQ =
40 . 2 ..radius
360
1 . 2 .. 9 ( radius = 9 as dia = 1 )
9
= 2
Hope this is helpful.:p
Thanks Sir for your informative messages..
I have a very humble question, What I should do to make my profile look different.. its different in negative way that I have poor acads in BE though FC.
Nill Ec.
Thanks Sir for your informative messages..
I have a very humble question, What I should do to make my profile look different.. its different in negative way that I have poor acads in BE though FC.
Nill Ec.
In GMAT ...poor GPA can be balanced with higher SCORE
and EC you dont need to really worry about that.
Right now focus on your GMAT and get a good score.
Hi ...can someone help me with this
This year Henry will save a certain amount of his income, and he will spend the rest. Next year
Henry will have no income, but for each dollar that he saves this year, he will have 1 + r dollars
available to spend. In terms of r, what fraction of his income should Henry save this year so that
next year the amount he was available to spend will be equal to half the amount that he spends this
year?
A. 1/(r+2)
B. 1/(2r+2)
c. 1/(3r+2)
d. 1/(r+3)
e. 1/(2r+3)
Hi ...can someone help me with this
This year Henry will save a certain amount of his income, and he will spend the rest. Next year
Henry will have no income, but for each dollar that he saves this year, he will have 1 + r dollars
available to spend. In terms of r, what fraction of his income should Henry save this year so that
next year the amount he was available to spend will be equal to half the amount that he spends this
year?
A. 1/(r+2)
B. 1/(2r+2)
c. 1/(3r+2)
d. 1/(r+3)
e. 1/(2r+3)
Answer is B.I have tried by taking initial amount as 200 and taking r as 1.
The number of passengers on a certain bus at any given time is
given by the equation P = -2(S 4)2 + 32, where P is the number of
passengers and S is the number of stops the bus has made since
beginning its route. If the bus begins its route with no passengers,
how many passengers will be on the bus two stops after the stop
where it has its greatest number of passengers?
1. 32
2. 30
3. 24
4. 14
5. 0
In a room filled with 7 people, 4 people have exactly 1 friend in
the room and 3 people have exactly 2 friends in the room. If two
individuals are selected from the room at random, what is the
probability that those two individuals are NOT friends?
5/21
3/7
4/7
5/7
16/21
Two questions :
The number of passengers on a certain bus at any given time is
given by the equation P = -2(S 4)2 + 32, where P is the number of
passengers and S is the number of stops the bus has made since
beginning its route. If the bus begins its route with no passengers,
how many passengers will be on the bus two stops after the stop
where it has its greatest number of passengers?
1. 32
2. 30
3. 24
4. 14
5. 0
In a room filled with 7 people, 4 people have exactly 1 friend in
the room and 3 people have exactly 2 friends in the room. If two
individuals are selected from the room at random, what is the
probability that those two individuals are NOT friends?
5/21
3/7
4/7
5/7
16/21
P = -2(S 4)2 + 32
friend this bold part is correct?
because -2 before bracket and 2 after?
P = -2(S 4)2 + 32
friend this bold part is correct?
because -2 before bracket and 2 after?
yes it is correct ; but you can write it as
P = - 4(S 4) + 32
P = -2(S 4)2 + 32
friend this bold part is correct?
because -2 before bracket and 2 after?
yes it is correct ; but you can write it as
P = - 4(S 4) + 32
the 1st question is from OG11
it is basically, P= -2(S-4)^2 +32
do u need the answer as well ??
hey!!
I was unable to solve this sum. anyone with d solution??
At a game in billiards, A can give B 15 points in 60 and A can give C 20 pints in 60. How many points can B give C in a game of 90?
A) 11
B) 13
C) 10
D) 14
Not able to solve the below problem. It must be a sitter for most of you on the forum.
The average of 5 consecutive integers starting with x is 'a'. What is the average of 9 consecutive integers that start with x+3?
a. x+a b. a+5 c. 2x d. 2a e. 2x+a
Not able to solve the below problem. It must be a sitter for most of you on the forum.
The average of 5 consecutive integers starting with x is 'a'. What is the average of 9 consecutive integers that start with x+3?
a. x+a b. a+5 c. 2x d. 2a e. 2x+a
Not Really!!!
Let x=1
so 5 nos will be
1,2,3,4,5
Average=15/5=3=a
for x+3
nos are-
4,5,6,7,8,9,10,11,12
Average=72/9=8
so lets see the answer choices-
1.1+3=4
2.3+5 aha matches
3.2*1=2
4. I am bored now
Not able to solve the below problem. It must be a sitter for most of you on the forum.
The average of 5 consecutive integers starting with x is 'a'. What is the average of 9 consecutive integers that start with x+3?
a. x+a b. a+5 c. 2x d. 2a e. 2x+a
hi,
i have solved it on the quant thread.but,nevertheless for the visitors here,
5 numbers starting from x are
x,x+1,x+2,x+3,x+4
average is x+2=a.....(1)
9 numbers starting from x+3 are
x+3,x+4....,x+11
average is x+7
which is a+5
option (b)
Not able to solve the below problem. It must be a sitter for most of you on the forum.
The average of 5 consecutive integers starting with x is 'a'. What is the average of 9 consecutive integers that start with x+3?
a. x+a b. a+5 c. 2x d. 2a e. 2x+a
answer is B.
i dont think it needs much explanation nw...
Q. Six mobsters have arrived at the theater for the premiere of the film Goodbuddies. One of the mobsters, Frankie, is an informer, and he's afraid that another member of his crew, Joey, is on to him. Frankie, wanting to keep Joey in his sights, insists upon standing behind Joey in line at the concession stand, though not necessarily right behind him. How many ways can the six arrange themselves in line such that Frankies requirement is satisfied?
(A) 6
(B) 24
(C) 120
(D)360
(E)720
Hi Pguys,
Could you help with the above problem?
Thanks,
Rohit.
Q. Six mobsters have arrived at the theater for the premiere of the film Goodbuddies. One of the mobsters, Frankie, is an informer, and he's afraid that another member of his crew, Joey, is on to him. Frankie, wanting to keep Joey in his sights, insists upon standing behind Joey in line at the concession stand, though not necessarily right behind him. How many ways can the six arrange themselves in line such that Frankies requirement is satisfied?
(A) 6
(B) 24
(C) 120
(D)360
(E)720
Hi Pguys,
Could you help with the above problem?
Thanks,
Rohit.
ans is 360
here
position 1 2 3 4 5 6
if Joey at 1st then franke 2/3/4/5/6 so total cases=5*4!
if joey at 2nd then possible =4*4!
same 3*4!,2*4!,1*4!
so total=5*6/2 *4!=15*24=360
hey!!
I was unable to solve this sum. anyone with d solution??
At a game in billiards, A can give B 15 points in 60 and A can give C 20 pints in 60. How many points can B give C in a game of 90?
A) 11
B) 13
C) 10
D) 14
when A hit 45 point B hit 60
when A hit 40 point B hit 60
so when A hit 40 points B hit 53.33
so in game of 60 difference between B and C=6.67
so in 90 its 10
so ans is 10
Hi Puys , i encountered the below mentioned questions while doing the earlier paper format tests and was really stuck in these-
Plz see the attachement.
Hi guys, it feels like ages when i started preparing for the GMAT and today I stand nowhere, you would get to know this by the level of problems I am posted below. However, I have thought that this time when I give the GMAT I really wanna focus on only my weak areas , so here they are some of them ;)
I really hope some angel would help me with them. I know the answer to many of them but I dont know the correct reasoning and explanation behind them so if someone can help me with it, it would be great !
Q1. If ba. x > -3
b. x c. x=3
d. x e. x > 3
Q2. A certain population of bacteria doubles every 10 minutes. If the number of bacteria in the population initially was 10^4, what was the number in the population 1 hour later ?
a. 2(10^4)
b. 6(10^4)
c. (2^6)(10^4)
d. (10^6)(10^4)
e. (10^4)^6
Q3. A certain clock marks every hour by striking a no of times equal to the hour, and the time required for a stroke is exactly equal to the time interval between the strokes. At 6:00 the time lapse between the beginning of the first stroke and the end of the last stroke is 22 seconds. At 12:00, how many seconds elapse between the beginning of the first stroke and the end of the last stroke ?
a. 72
b. 50
c. 48
d. 46
e. 44
Q4. The addition problem below shows four of the 24 different integers that can be formed by using each of the digits 1,2,3 and 4 exactly once in each integer. What is the sum of these 24 integers ?
1,234
1,243
1,324
....
....
+ 4,321
--------
a. 24,000
b. 26,664
c. 40,440
d. 60,000
e. 66,660
Q5. Four hours from now, the population of the a colony of bacteria will reach 1.28x10^6. If the population of the colony doubles every 4 hours, what was the population 12 hours ago ?
a. 6.4 x 10^2
b. 8.0 x 10^4
c. 1.6 x 10^5
d. 3.2 x 10^5
e. 8.0 x 10^6
Q6. At a certain pizzeria, 1/8 of the pizzas sold in one week were mushroom and 1/3 of the remaining pizzas sold were pepperoni. If n of the pizzas sold were pepperoni. How many were mushroom ?
a. 3/8n
b. 3/7n
c. 7/16n
d. 7/8n
e. 3n
Q7. If it is true that x > -2 and x a. x > 2
b. x > -7
c. x d. -7 e. None of the above
Q.8. A rectangular box is 10 inches wide, 10 inches long and 5 inches high. What is the greatest possible (straight-line) distance, in inches, between any two points on the box ?
a. 15
b. 20
c. 25
d. 10 (2)^1/2
e. 10 (3)^1/2
Many Thanks for all your help and support.