Alchemist, I have some doubts in ur reasoning for 2nd & 3rd questions.......
2.The question is asking for no specific value of P/Q .It is asking " Does the decimal equivalent of P/Q, where P and Q are positive integers, contain only a finite number of nonzero digits?"
ie is P/Q is a terminating decimal...... If a fraction P/Q with Q having 2 or 5 as its prime factors, regardless of the value of P, the fraction will terminate......u can use values to check this In B it is said that Q=8=2^3 so it has finite value....... So i think B
3.The question is asking for the amount in 30th May and not 1st May........ I think ur variable 'a' denotes the amount in 1st may.......then without 2nd statement hw can u calculate amount in 30th may.......so i think C
Simmy, Pls check for OA of 2nd question.......it will be B.....wats the source of these questions.?is it areliable one?
Pls correct me if i'm wrong
Hi..
2nd question... the decimal equivalent of 9/8 = 1.125. but the decimal equivalent of 82/8 is 10.25 -> contains a zero.. but 16/8 = 2 -- doent contain zero.. hence my answer.
3rd Qn.. Yes.. the answer shld be C.. First stmt gives principal.. second statment gives rate.
2nd question... the decimal equivalent of 9/8 = 1.125. but the decimal equivalent of 82/8 is 10.25 -> contains a zero.. but 16/8 = 2 -- doent contain zero.. hence my answer.
3rd Qn.. Yes.. the answer shld be C.. First stmt gives principal.. second statment gives rate.
I dont understand why zero in 82/8 and no zero in 16/8 cause any difference to the statement that 82/8 and 16/8 and 9/8 have finite no: of nonzero no:s........ In 9/8 4 nonzero digit so finite no: of digits In 82/8 3 nonzero digit so finite no: of digits In 16/8 1 nonzero digit so finite no: of digits
I dont understand why zero in 82/8 and no zero in 16/8 cause any difference to the statement that 82/8 and 16/8 and 9/8 have finite no: of nonzero no:s........ In 9/8 4 nonzero digit so finite no: of digits In 82/8 3 nonzero digit so finite no: of digits In 16/8 1 nonzero digit so finite no: of digits
Ur logic on the prime factors make sense to me... but i m still trying hard to get a counter example... to disprove ur statement.
Jus a qn.. Can you pls tell me why this holds for 2 and 5?
An integer greater than 1 that is not prime is called composite. If the two digit integer n is greater than 20, is n composite?
1. The tens digit of n is a factor of the units digit of n 2. The tens digit of n is 2
Guess the ans. is 'C'.
stmt 1: The tens digit of n is a factor of the units digit of n => tens position units position 2 4, 6, 8 3 6,9 4 8 1 1,2,3,4,5,6,7,8,9
Only when tens postion is 1 - we cant decide whether or not the number is composite.. combing with 2nd statement... only can we say that.. the number is composite for sure
Stmt 2 alone is insufficient.. for example consider.... 29
Can you plz explain?.. I was under the assumption that whenever the tens digit is 1 the units digit can range from 1 - 9 and the 2 digit numbers formed as a result can be both composite and prime!..
Alchemist, I have some doubts in ur reasoning for 2nd & 3rd questions.......
2.The question is asking for no specific value of P/Q .It is asking " Does the decimal equivalent of P/Q, where P and Q are positive integers, contain only a finite number of nonzero digits?"
ie is P/Q is a terminating decimal...... If a fraction P/Q with Q having 2 or 5 as its prime factors, regardless of the value of P, the fraction will terminate......u can use values to check this In B it is said that Q=8=2^3 so it has finite value....... So i think B
3.The question is asking for the amount in 30th May and not 1st May........ I think ur variable 'a' denotes the amount in 1st may.......then without 2nd statement hw can u calculate amount in 30th may.......so i think C
Simmy, Pls check for OA of 2nd question.......it will be B.....wats the source of these questions.?is it areliable one?
Pls correct me if i'm wrong
Hi Ashish,
Even I answered B for second question and C for the third one. I have some PBTs- Paper based tests of GMAT. These questions are from one of the PBTs and answers are provided at the end. But those answers might be wrong, you never know. Thanks.
Hi - I Posted the answer just few posts before...anyways the answer is 'C'
stmt 1 => m > 3z --- not sufficient stmt 2 => m combining both statement we get 3z 0 (if z 0....clubbing this with first statement.. we can have m > 0..
I thought on the same lines.. but the OA is (C). This is one of the ETS GMAT prep questions.
I can't figure out why statement (1) is insufficient.
My pick would be A
1) Sufficient Let l,b,h be the length,breadth and height of the solid. Assuming l*b=15 and b*h=24, we can easily arrive at l=5 b=3 h=8. The reason being 15 can only be equal to 5x3. Thus either b or l will be equal to 3. l cant be 3 as then 5*h=24 will yield a non integer value for h.
Thus, vol = l*b*h= 120
Note: we can take any two pairs out of lb,bh,hl to arrive at this answer. 2)insufficient: This gives us info only about one of the three possible pairs of lb,bh,hl. Thus not sufficient.
1) Sufficient Let l,b,h be the length,breadth and height of the solid. Assuming l*b=15 and b*h=24, we can easily arrive at l=5 b=3 h=8. The reason being 15 can only be equal to 5x3. Thus either b or l will be equal to 3. l cant be 3 as then 5*h=24 will yield a non integer value for h.
Thus, vol = l*b*h= 120
Note: we can take any two pairs out of lb,bh,hl to arrive at this answer. 2)insufficient: This gives us info only about one of the three possible pairs of lb,bh,hl. Thus not sufficient.
Ankit, Hw u could infer that any of the 3 dimensions cannot be non-integers.......? second, If i take l=15, b=1 & h=24 then l*b= 15 and b*h=24.....so many possible sets of (l,b,h).....
the question has already been answered on page 72 of this thread.....please refer to the posts before reposting the question..... IMO too, the answer shud be C. Adequate explanation has been provided by the Puys out here
Thanx for the info..
Actually i still have a doubt...
By solving both the stems we get 3z Now if we take z=1 so 30
Now if we take z=-1 so -3>z>-4 so in this case m+z Can anyone tell me where i am going wrong???
in xy plane at what two points does the graph of y=(x+a)(x+b) intersects the x-axis. 1) a+b= -1 2) the graph intersects the y-axis at (0,-6)
the answer is c Please anyone can explain me the reason why the answer is c.I will be pleased to see some helping me to solve the problem as i have tried this sum for 10 times and i cannot understand the question itself.
