ps25 SaysMy choice C. Please confirm
Answer is indeed C. Can you explain with equations on what is missing in the individual cases?
ps25 SaysMy choice C. Please confirm
Its a warehouse, so assuming CP is same lets say c
year 1 year 2
n 1.1n (n = number of sofas , statement A is not alone sufficient to find the answer)
p p+30 ( p = selling price , Statement B is not alone sufficient to find the answer)
Hence option D,B and A are removed.
now using both the statement together
percentage greater=[ {(p+30)-c}*1.1n - (p-c)*n ] / (p-c)*n
hence using both the statement the answer can be found.
Hence the answer is C
[Assumed that CP is same "c" for both the year otherwise the answer is "E"]
If r is the remainder when the positive integer n is divided by 7, what is the value of r?
(1) When n is divided by 21, the remainder is an odd number.
(2) When n is divided by 28, the remainder is 3.
mbaQuest12 SaysAnswer is indeed C. Can you explain with equations on what is missing in the individual cases?
mbaQuest12 SaysThanks for the response. Answer is E. The question is from one of the GMATPrep Tests. Not sure if assumptions are allowed since it results in 2 different answers.
If r is the remainder when the positive integer n is divided by 7, what is the value of r?
(1) When n is divided by 21, the remainder is an odd number.
(2) When n is divided by 28, the remainder is 3.
Warehouse W's revenue from the sale of sofas was what percentage greater this year than it was last year?
(1) Warehouse W sold 10 percent more sofas this year than it did last year
(2) Warehouse W's selling price per sofa was $30 greater this year than it was last year.
Please confirm the solution with official answer -
n = 7 * Q + r
what is r?
1) n = 21 * Q' + x where 0
divide n by 7, remainder will be x/7 so it will be 1, 3, 5, 0...
NOT SUFFICIENT
2) n = 28 * Q'' + 3
divide n by 7 and remainder will always be 3
Sufficient
Answer B
mbaQuest12 SaysAwesome solution! You make it look so simple!
Is it D?
If you take combination of 15 and 30 it will still give u LCM of 30, you get reminder 0. so statement 2 is also not sufficent. Please come up with better explaination.
QUOTE]
Q. The integers m and p are such that 21 ?
1. the greatest common factor of m and p is 2
2. the least common multiple of m and p is 30
a b c d
e f g h
i j k l
m n o p
In the grid above, the variables a through p are each equal to 2, 3, 5, or 7, with exactly one occurrence of each value in any row and in any column. What is the value of fgjk?
(1) bcehilno = 35^4
(2) (2.25^2)afkp = dgjm
PS: (consider it as a 4X4 grid, couldn't draw them using this editor)
a b c d
e f g h
i j k l
m n o p
In the grid above, the variables a through p are each equal to 2, 3, 5, or 7, with exactly one occurrence of each value in any row and in any column. What is the value of fgjk?
(1) bcehilno = 35^4
(2) (2.25^2)afkp = dgjm
PS: (consider it as a 4X4 grid, couldn't draw them using this editor)
a b c d
e f g h
i j k l
m n o p
In the grid above, the variables a through p are each equal to 2, 3, 5, or 7, with exactly one occurrence of each value in any row and in any column. What is the value of fgjk?
(1) bcehilno = 35^4
(2) (2.25^2)afkp = dgjm
PS: (consider it as a 4X4 grid, couldn't draw them using this editor)
2) (2.25^2)afkp = dgjm
5^2 afkp = 2^2dgjm
This means afkp will have one 2^2 and dgjm will have one 5^2
In dgjm j * g can be 5 ^ 2 or 5 * (something !=5 ) or (something !=5 ) *(something !=5 )
In afkp f*k can be 2^2 or 2* (something !=2 ) or (something !=2 )*(something !=2 )
This is not sufficient
So I will go for A
Hi ps25,
(2.25^2)afkp = dgjm
Now 2.25^2 = (9/4)^2 = 9 ^2/4^2 = 3*3*3*3/2*2*2*2
Therefore dgjm/afkp = 3*3*3*3/2*2*2*2
So, all these alphabets will correspond to either 3 or 2.
Therefore, II is sufficient.
if x is not equal to 0, is ((x^2 + 1)/x) > y?
1. x=y
2. y>0
if x is not equal to 0, is ((x^2 + 1)/x) > y?
1. x=y
2. y>0
ps25 Sayswill go with C