IMHO, (C)...both statements are needed.....
What's the OA??
In the rectangular co-ordinate system, are the points (r,s) and (u,v) equidistant from the origin?
(1) r+s=1
(2)u=1-r and v=1-s
IMO E
for distance to be equal, following eq'n must be satisfied,
r^2 + s^2 = u^2 + v^2
Clearly op A alone is insufficient as no info of "u" and "V" is given
Op B again alone insufficient as the eq'n, u+v= 2-(r+s), gives no information
if u combine both the options then u get u+v =1, now one may think that
as u + v =1
and r + s =1,
so the necessary condition r^2 + s^2 = u^2 + v^2 will be fulfilled, BUT its NOT TRUE
for ex u = 1/2 and v = 1/2 and r = 2/3 and s = 1/3
so here,
u + v =1
and r + s =1,
But r^2 + s^2 NOT EQUAL TO u^2 + v^2
while if u make all the coordinates equal to 1/2 then the above condition will satisfy,
so u didn't get any definite answer, hence E
IMO E
for distance to be equal, following eq'n must be satisfied,
r^2 + s^2 = u^2 + v^2
Clearly op A alone is insufficient as no info of "u" and "V" is given
Op B again alone insufficient as the eq'n, u+v= 2-(r+s), gives no information
if u combine both the options then u get u+v =1, now one may think that
as u + v =1
and r + s =1,
so the necessary condition r^2 + s^2 = u^2 + v^2 will be fulfilled, BUT its NOT TRUE
for ex u = 1/2 and v = 1/2 and r = 2/3 and s = 1/3
so here,
u + v =1
and r + s =1,
But r^2 + s^2 NOT EQUAL TO u^2 + v^2
while if u make all the coordinates equal to 1/2 then the above condition will satisfy,
so u didn't get any definite answer, hence E
your explanation is wright...but if we square both of them in 2nd option then we will get u^2=1-2r+r^2 and v^2=1-2s+s^2, or u^2+v^2=2-2(r+s)+(r^2+s^2)...from statement 1 and 2, we can write u^2+v^2=2-2(1)+(r^2+s^2)... or u^2+v^2=r^2+s^2....so answer is C..OA is C....but i think E is also equally justifiable...any explanation..
Bhailogon,
after u combine the statements, u need to satisfy them, when we are plugging numbers.
so if r = 1/3 and s = 2/3, then, u = 1-r = 2/3 and v = 1-s = 1/3,
so if u notice, they will always be the same, just the numbers will change from one axis to the other.
But, the distance will always be the same !!
So C is the correct choice.
casmba Saysyour explanation is wright...but if we square both of them in 2nd option then we will get u^2=1-2r+r^2 and v^2=1-2s+s^2, or u^2+v^2=2-2(r+s)+(r^2+s^2)...from statement 1 and 2, we can write u^2+v^2=2-2(1)+(r^2+s^2)... or u^2+v^2=r^2+s^2....so answer is C..OA is C....but i think E is also equally justifiable...any explanation..
Bhailogon,
after u combine the statements, u need to satisfy them, when we are plugging numbers.
so if r = 1/3 and s = 2/3, then, u = 1-r = 2/3 and v = 1-s = 1/3,
so if u notice, they will always be the same, just the numbers will change from one axis to the other.
But, the distance will always be the same !!
So C is the correct choice.
@sausi
Good, i overlooked that fact, thanks for the necessary explanation...
Begining in january of last year, carl made deposits of $120 into his account on the 15th of each month for several consicutive months and then made withdrawals of $50 from the account on the 15th of each of the remaining months of last year.There were no other transactions in the account last year.If the closing balance of carl,s account for may of last year was $2600, what was the range of the monthly closing balances of carl,s account last year?
(1) Last year the closing balance of carl,s account for april was less than $2625.
(2) Last year the closing balance of carl,s account for june was less than$2675.
Begining in january of last year, Carl made deposits of $120 into his account on the 15th of each month for several consecutive months and then made withdrawals of $50 from the account on the 15th of each of the remaining months of last year.There were no other transactions in the account last year. If the closing balance of Carl,s account for May of last year was $2600, what was the range of monthly closing balances of Carl,s account last year?
(1) Last year the closing balance of Carl,s account for April was less than $2625.
(2) Last year the closing balance of Carl,s account for June was less than $2675.
IMO C, i.e, can be answered using both statements combined. Reasons below.
Stmnt 1. May 15th - 2600
Case 1: Deposit of 120 on this date, means on 15th April balance was 2480
Case 2: Withdrawl of 50 on this date, means on 15th April balance was 2650
Since Case 2 is not possible(AprilBut we do not know what happens on 15th June(withdrawl or deposit), so we cannot decide what the ranges are.
Stmnt 2. June 15
Case 1: Deposit of 120 on this date, means on 15th June balance will be 2720
Case 2 : Withdrawl of 50, means on this date balance will be 2550
Since Case 1 is not possible according to the statement, we know that from hereon, balance will continue reducing but we cannot deduce the min and max range of Carl's account balance.(Since we do not when the withdrawls started, this month or the last month)
Only after Combining both statements we get the range.
Begining in january of last year, Carl made deposits of $120 into his account on the 15th of each month for several consecutive months and then made withdrawals of $50 from the account on the 15th of each of the remaining months of last year.There were no other transactions in the account last year. If the closing balance of Carl,s account for May of last year was $2600, what was the range of monthly closing balances of Carl,s account last year?
(1) Last year the closing balance of Carl,s account for April was less than $2625.
(2) Last year the closing balance of Carl,s account for June was less than $2675.
What is the value of integer n?
(1) n(n+1)=6
(2) 2^2n=16
What is the value of integer n?
(1) n(n+1)=6
(2) 2^2n=16
i think the answer should be B
reason:
1>
n = 2 : 2(2+1) = 2(3) = 6
n = -3: (-3)(-3+1) = (-3)(-2) = 6
hence two possible values of n. NOT SUFFICIENT.
2>
n=2 : 2^(2*2) = 2^4 = 16.
just one possible value for n. SUFFICIENT.
What is the value of integer n?
(1) n(n+1)=6
(2) 2^2n=16
IMO B as well.....
1) n(n+1)=6
can be factored as (n+3)(n-2)=0, which gives us 2 values of n
Not sufficient
2) 2^2n=16
=> 2^2n=2^4
=> 2n=4, i.e n=2
Only one value of n, thus sufficient .
Of the 9,000 people who voted in a recent election, how many women voted for candidate X?
(1) The percentage of women voting for candidate X was twice the percentage of women voting against candidate X.
(2) Three thousand men voted for candidate X.
Of the 9,000 people who voted in a recent election, how many women voted for candidate X?
(1) The percentage of women voting for candidate X was twice the percentage of women voting against candidate X.
(2) Three thousand men voted for candidate X.
my take is E...correct?
Of the 9,000 people who voted in a recent election, how many women voted for candidate X?
(1) The percentage of women voting for candidate X was twice the percentage of women voting against candidate X.
(2) Three thousand men voted for candidate X.
I will go with option E for the above DS. Here is how I worked it out
Statement A - Only talks abt the %.Nothing concrete. Nt suff
Statement B - Talks about the Men..Nt suff
Combining both, No of Men voted for Candidate X = 3000..Huv many Women voted in the election?How many Men voted in the Election?Ans cannot be derived from the above information.
So,I would go with option E
-Deepak.
I will strengthen above logic with my take as E....though deepak sir gave the best explanation..
even if you combine the two statements:
"2w" :- the no of women who voted in favour of x
"w" :- women who voted against X
"m" :- men who voted against X
You'll come down to an equation which looks something like
(2w+3000) + (m+w) = 9000
i.e. (3w+m)=6000
and we can have multiple options with this eqn in hand.
so my take will be E
correct me if I am wrong
If (X^2) - 8X - 9 = 0, What is the maximum value of f(x) = ?
(1) x| Less than or equal to 9
(2) |Y Less than or equal to 9
Please explain your answers.....
The equation gives us 2 values for "x" i.e (-1,9)
now the f(x) can be broken down to x^2 - 1*|y. Coming on to the conditions -
(1) to calculate maximum we also need the value of y
so this alone is insufficient
(2) y| so f(x) max will be 80 * 9=720
this alone is sufficient.
Hence my take will be B
whats the OA
ANSWER-C
x- SQUARE OF AN INTEGER N CUBE OF AN INTEGER IS 64
8*8=64
4*4*4=64
Every item in an apparel shop has a tag that is either blue, green or yellow in colour. The items with a blue tag are priced between $20 and $30. The items with a green tag are priced between $12 and $18 and the items with a yellow tag $5 and $10. Mary buys three items, each with a different color tag. Is the total discount on three items greater than 10%?......
1) The discount on the items with a blue tag is 20% and that on the items with a green tag is 25%.
2)The discount on the items with a yellow tag is 40%.
Please provide the answer with your explanation....Thanks in advance.