**Solving Time-Speed-Distance problems without using equations**

8 Sep, 2011

*(Photo credit: Michael Gallacher)*

I guess my first fascination with problems of Time, Speed and Distance began when I first watch a film called Henna. An important portion of the plot, if you can call it that, had Rishi Kapoor floating from India to Pakistan in a river without drowning. I remember arguing with my friends that if he could float that long he could swim back to India as well. My friends nullified the argument by saying,

Speed River > Speed Rishi Kapoor

I know that the reference is a little dated for most readers, but Zeba Bhaktiyar made me look beyond reason. In this post we will discuss some of the ideas that have helped me solve TSD problems without forming too many equations.

**Funda 1**: **Average Speed**

We know that the average speed during a journey is given by (Total Distance Covered) / (Total Time Taken); but there are a few special cases which might help in solving questions,

*- If the **distance covered is constant **(**d1 **= d2 **= d**3 ** = dn**) **in each part of the journey, then the average speed is the Harmonic Mean of the values.*

*SpeedAvg = n / (1/s1 + 1/s2 + 1/s3 ... + 1/sn)*

* **- If the **time taken is constant **(t**1 **= t2 **= t**3 ** = tn**) **in each part of the journey then the average speed is Arithmetic Mean of the values.*

* **Speed**Avg** = (s1 + s2 + s3 ... +sn)/n*

**Funda 2: Using Progressions (Arithmetic & Harmonic)**

** **

In many questions, you will come across a situation when a person is going from point A to point B at various speeds and taking various times. We know that if **distance is constant**, speed and time are inversely proportional to each other. But this information can also be used to deduce the following two facts,

*- If the various speeds which are mentioned are in AP, then the corresponding** **times taken will be in HP.*

* **- If the various speeds which are mentioned are in HP, then the corresponding times taken will be in AP.*

* *Let us use these ideas to solve couple of quant questions.

**Example 1**

** **Arun, Barun and Kiranmala start from the same place and travel in the same direction at speeds of 30, 40 and 60 km per hour respectively. Barun starts two hours after Arun. If Barun and Kiranmala overtake Arun at the same instant, how many hours after Arun did Kiranmala start?

*(Some useless information: Arun Barun Kiranmala is a 1968 Bangladeshi film. Now you can guess what inspires the CAT question setters. Here is a **song from the film**.)*

**Solution **As you can see that the speeds are in HP, so we can say that the times taken will be in AP. Time difference between Arun and Barun is 2 hours, so the time difference between Barun and Kiranbala will also be 2 hours.

Hence, Kiranbala started 4 hours after Arun.

**Example 2**

** **Rishi Kapoor can swim a certain course against the river flow in 84 minutes; he can swim the same course with the river flow in 9 minutes less than he can swim in still water. How long would he take to swim the course with the river flow?

**Solution**

Let us say Speed of Rishi Kapoor in still water is RK and Speed of the river is R. Hence, Rishi Kapoors speeds against the river flow, in still water and with the river flow are,

RK R, RK and RK + R.

As you can see, they are in AP.

Hence, the corresponding times taken will be in HP.

Let us say that the time taken to row down with the stream is t, then 84, t+9 and t are in HP. So,

*t + 9 = (2 * 84 * t) / (84 + t)*

*? t2 + 93t + 756 = 168t*

* **? t2 - 75t + 756 = 0*

* ** ** **? t = 63 or 12*

* *

* *

**Funda 3: Special Case**

Let us say that two bodies a & b start at the same time from two points P & Q towards each other and meet at a point R in between. After meeting at R, a takes ta time to reach its destination (Q) and b takes tb time to reach its destination (P). Then,

*Sa / Sb = ?(tb / ta)*

Also, the time taken by a & b to meet (i.e. to reach point R from P & Q respectively) is given by,

*t = **?*(ta * tb)

*Note: The same formulae will be valid if two bodies a & b start at different times from two points P & Q towards each other. They meet at a point R in between after travelling for ta and tb time respectively. After meeting, they take the same amount of time (t) to reach their respective destinations (Q & P).*

I hope that these ideas will help you reduce the number of equations that you form while solving TSD problems if not completely eliminate them.

*Ravi Handa, an alumnus of IIT Kharagpur, has been teaching for CAT and various other competitive exams for around a decade. He currently runs an online CAT coaching and CAT Preparation course on his website http://www.handakafunda.com*

*more_horiz*

hi everybody.. ijust start preparng for cAT exam .please guide me ..from where i start or what to do??? am in muddle stage.please help me out

replyfavorite_borderplease explain me HP.i didnt get exmple no 2.

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