XAT- 30 days Quant Preparation

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All puys and pals, CAT is over and its time for all to move to another big exam XAT (after all XLRI is no less tahn IIM). If CAT was tough XAT was toughest ( those who have appeared last year wil testify that). Historically XAT quant is more...
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www.raghavabbhi.com | My take on CAT: http://www.pagalguy.com/discussions/all-i-wanted-to-speak-about-cat-25002933/6315307
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shankla Says
What should be the decent number of attempts to get a score of 30 or above in XAT keeping in mind that scores in all the sections should be equal...


i doubt,you will find anyone lurking on this thread at this time.please post your query on this thread to get help asap.

http://www.pagalguy.com/discussions/xat-2009-queries-25034106

hope that helps.
all the best for the exam :thumbsup:
Captain, PG Dream Team 2010 | CAT 11 - 100%ile | CET 10 - Rank 1 (211/240) | Co-founder Learningroots
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What should be the decent number of attempts to get a score of 30 or above in XAT keeping in mind that scores in all the sections should be equal...

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keep up the gud work..

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Ah...and I was thinking NMAT or snap!
My memory seems really bad now :-?

I have also uploaded mock xat 1...see the new post there...that site has some bug I guess...I'd uploaded both the paper simultaneously..but it chose the bigger fille...bummer!

Dude!..happened to notice your JMET result in the signature...wasn't it supposed to be out on 5th Jan? (JMET :: Indian Institute of Technology Kanpur)
Where did you check it?!
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I don't know what but your post really make me laugh (although I had to control since I am in office) coz of your memory.:biggrin::biggrin:
Anyways the question is from XAT Mock test 2 and the answer is posted by you only in XAT 2008 queries thread.
But i am not able to find the Mock test 1 answer key:huh:


Ah...and I was thinking NMAT or snap!
My memory seems really bad now :-?

I have also uploaded mock xat 1...see the new post there...that site has some bug I guess...I'd uploaded both the paper simultaneously..but it chose the bigger fille...bummer!
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Wasn't this a question that has already appeared in some exam this year?
I'm sure i've solved it.

Anyways,
resolve 4n-1 = (2n)-1 into partial fractions
=0.5(1/2n-1 - 1/2n+1)

Put n = 12 in the summation ...= 20(1-1/25)
n = 21 .... = 20(1-1/43)

Add and then = 20(2-1/25-1/43) = 4164/215

After solving I still cant remember where it had come!:rockedov:


I don't know what but your post really make me laugh (although I had to control since I am in office) coz of your memory.:biggrin::biggrin:
Anyways the question is from XAT Mock test 2 and the answer is posted by you only in XAT 2008 queries thread.
But i am not able to find the Mock test 1 answer key:huh:
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Ques:If P(n) =20/3+20/15+20/35+...+20/(4n^2-1).
What is the value of P(12)+P(21).


Wasn't this a question that has already appeared in some exam this year?
I'm sure i've solved it.

Anyways,
resolve 4n-1 = (2n)-1 into partial fractions
=0.5(1/2n-1 - 1/2n+1)

Put n = 12 in the summation ...= 20(1-1/25)
n = 21 .... = 20(1-1/43)

Add and then = 20(2-1/25-1/43) = 4164/215

After solving I still cant remember where it had come!:rockedov:
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Ques:If P(n) =20/3+20/15+20/35+...+20/(4n^2-1).
What is the value of P(12)+P(21).

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this is the different approach i hv applied..urs is also rite
we can hv various solns to a problem

coolsurd, I am not challenging your approach, I have no interest in doing so. I am only asking you to explain it better ("how does it take into account that the curves meet at three points?")
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