If x is real and │log(x + 5)(2x – 1)│= 1, then find the number of possible values of x.
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There are 76 posts in xat 2015 quant thread
If x is real and │log(x + 5)(2x – 1)│= 1, then find the number of possible values of x.
There are 76 posts in xat 2015 quant thread
@Nipun008 You are missing a 10 or 1/10 (depending on log(x+5)(2x-1) being 1 or -1 ) in your equations I believe. Please check. Also as long as (x+5)(2x-1) >0, any value of x will be acceptable, whether it is negative of positive. You should not break it into (x+5) and (2x-1). It will be like breaking -2 into i and 2i. I hope you are getting my point.
@Nipun008 And base of log function can be any positive value, so can be domain on which the function is applied. i.e. logb (a) is defined if a,b>0 and real