Time Speed and Distance, Work, Alligations & Mixtures

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Katrina walks down an up-escalator and counts 150 steps. Priyanka walks up the same escalator and counts 75 steps. Katrina takes three times as many steps in a given time as Priyanka. How many steps are visible on the escalator?
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Can somebody solve this by the "units of work" method? As In, we take the lcm of all the numbers and take is a the total units of work and then find the no of units per day and so on.

Post 5881128012480512
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gdi006
@gdi006  ·  4 karma

@Gayathri.Keerthana okayzzzz... Thank you for the reply.

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DreamerIIMC
@DreamerIIMC  ·  146 karma

3

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Post 4619690494132224
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vishiac
@vishiac  ·  5,074 karma

@harsimran29fe according to question, consider initial cost as 100, 40% increase means 140... Question no. 6 says he can spend 5% more than initial so he can spend 105... New cost is 140 and he spends only 105, so decrease % is (35/140)* 100= 25%

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harsimran29fe
@harsimran29fe  ·  10 karma

@vishiac done!

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Post 5398269045768192
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harsimran29fe
@harsimran29fe  ·  10 karma

😂 @vishiac cleared!

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vishiac
@vishiac  ·  5,074 karma

@harsimran29fe Its a concept... dont forget bro..

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@vishiac how can we solve this using options!

Post 5089955590176768
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vishiac
@vishiac  ·  5,074 karma

@harsimran29fe you should be very good with numbers for that, 720 = 24*30 = 30*24 = 36*20.....see difference bwn first values 24, 30 and 36 each is 6, which is speed , and also the second values 30 - 20 = 10hrs, 24 -20 = 4hrs....which matches with data in question...

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vishiac
@vishiac  ·  5,074 karma

@harsimran29fe suppose x is initial speed and time is t, we get xt =(x+6)(t-4), which gives 6t -4x = 24, then second eqn xt = (x-6)(t+6), which gives x - t =6, solve for x and t, we get x =30, t = 24, dist =xt =30*24 = 720

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Post 6653020253192192
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harsimran29fe
@harsimran29fe  ·  10 karma
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vishiac
@vishiac  ·  5,074 karma

@harsimran29fe it depends on how one perceives a question... I had both in mind but went with 4...

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Post 4874761622519808
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harsimran29fe
@harsimran29fe  ·  10 karma

@vishiac here it is

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Post 6380201246195712
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harsimran29fe
@harsimran29fe  ·  10 karma

@vishiac why this trick didnt came to my mind?

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harsimran29fe
@harsimran29fe  ·  10 karma

@vishiac thank you sir😇

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AB is a platform 325m from B at 100m distance there is a bridge of length 250 m . In between that bridge there is a pole ,the time taken by the train to cross the pole from A is 40secs. Find the lenght of train . @vishiac

2 comments
vishiac
@vishiac  ·  5,074 karma

@harsimran29fe The data here is insufficient to answer the question... Is the question complete...?? Just check once again and let me know

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harsimran29fe
@harsimran29fe  ·  10 karma

@vishiac no idea

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Post 4937790099816448
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harsimran29fe
@harsimran29fe  ·  10 karma

@vishiac got it

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vishiac
@vishiac  ·  5,074 karma

@harsimran29fe Start from one end of diameter, move 600m towards N then from there move 800m towards E reaching the other end of diameter... this forms an right angled triangle with diameter as hypotenuse. Apply pythagorus theorem, (dia)^2 = 600^2 + 800^2.... so diameter = 1000

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Now I'm facing similar problem with this question too.

Post 5998721579876352
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vishiac
@vishiac  ·  5,074 karma

@harsimran29fe Bro same consideration, consider what if pedestrian doesn't move. Then speed of car is speed = distance / time, we know distance is 0.6 and time is 6min = 6/60hr = 0.1hr... speed is 0.6/0.1 =6km/hr... but the pedestrian was also moving with speed of 2km/hr in same direction so car's actual speed = 6+2 = 8km/hr

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vishiac
@vishiac  ·  5,074 karma

@harsimran29fe else u can straight away consider both are moving in same direction so relative speed is (X -2)km/hr where X is speed of car... Now speed (X-2)= distance /time = 0.6/0.1 = 6, so X = 6+2 = 8km/hr

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