# Time ,speed and distance Question by arun sharma

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Two bodies A and B start from opposite ends P and Q of a straight road. They meet at a point 0.6D from P . Find the point of their fourth meeting. hw to solve this type of question
Page 1 of 2 The number of days taken by A and B together to complete a piece of work is the ratio of 6. When you sum up the no of days taken by A and B separately u will end up in a 2 digit prime no. What's the no of days taken by them to do the work together Write a comment
Write a comment... Shaurya and Arjit take a straight road to the same terminal point and travel with same constant speed. At the initial moment, the position of two and terminalpoint forms an quilateral trianle. When arjit covered a distance of 80km, the triangle becomes right-angled. When Arjit waas at a distance of 120 km from the terminal point, shaurya arrived at the point. FInd the distance between them at the initial moment assuming there are integral distance throughout the moment described.

300
240
200
225 Lonavala and Khandala are two stations 600 km apart. A train starts from Lonavala and moves towards Khandala at the rate of 25km/h. After two hours, another train starts from Khandala at the rate of 35km/h. How far from Lonavala will they will cross each other?

250km
475km
279.166km
300km The Sinhgad Express left Pune at Noon sharp. Two hours later, Deccan queen started from Pune in the same direction. The Deccan Queen overtook the Sinhgad Express at 8:00 pm. Find the average speed of the two trains over this journey if the sum of their average speeds is 70kmph.

34.28 kmph
35 kmph
50 kmph
12 kmph A and B working separately can do a piece of work in 6 and 9 days respectively; they work on alternate days starting with A on the first day. In how many days will the work be done? Please help me explain the same.

3 days
7 days
10 days
11 days Rakesh started from x for y at a speed of 18km/hr after every 10 mins he increased his speed by 6kmphr. if xy=25km after how many minutes will he reach y?

40
50
60
70 Alexander swims from X to Y, and back in 10 hours.

He drops his goggles at point X and the goggles take 15 hours to float to Y.What is the ratio of the speed to Alexander in still water to that of the current?
10:1
6:1
3:1
(3+root13):2
4:1 The total area covered by the hour hand of a clock in 4 days is 4/5th of the total area covered by the minute hand in one day.What is the ratio of the length of the minute hand to the length of the hour hand?

plz give the explanation
6:2 root3
1:root3
root5: 2 root3
4: root3
root5:3 root3 if A covered 42

then we can break it into 10 from A to B

10 from B to A

10 from A to B

10 from B to A

then 2 from A

so now A is at .2D from A

***** Write a comment
Write a comment... sry i didn't get the last point Write a comment
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