quant.

4 Posts  ·  9 Users
About this group
Q1. If x, y and z are integers and x + y + z = 3, the what is the minimum value of 1/x + 1/y + 1/z ? Q 2 what is the least value of (x-1) (x-3) (x-4) (x-6)+10, for real values of x?
Page 1 of 1

Post your query on of any of the currently runnning Quant threads, no need to create new threads for the same. :)

Locked.

Commenting on this post has been disabled by the moderator.
warrior
@warrior  ·  2,324 karma
Q1. If x, y and z are integers and x + y + z = 3, the what is the minimum value of
1/x + 1/y + 1/z ?
Q 2 what is the least value of (x-1) (x-3) (x-4) (x-6)+10, for real values of x?


1. x=y=1 and z=-5 we get -9/5 as min

2. (x-1) (x-3) (x-4) (x-6) club 1st and 4th, 2nd and 3rd

(x^2-7x+6)(
x^2-7x+12) = (y+6)(y+12) +10= y^2+18y+82=0

min will be at -b/2a= -9

so min = 1

and pramod bhai why new thread for this.Use some existing thread from next time onwards
Commenting on this post has been disabled by the moderator.
Q1. If x, y and z are integers and x + y + z = 3, the what is the minimum value of
1/x + 1/y + 1/z ?
Q 2 what is the least value of (x-1) (x-3) (x-4) (x-6)+10, for real values of x?

Q1 (1/x+1/y+1/z)(x+y+z) = (3+x/y+y/x +x/z+z/x+y/z+z/y)
x/y+y/x >= 2
=> (1/x+1/y+1/z)>=3
Q2 M = (x-1)(x-3)(x-4)(x-6) + 10
(x-1)(x-3)(x-4)(x-6) the following expression is -ve for 1
take x = 5
M = 2
take x = 2
M =2 hence the least possible is 2

BTW donot open threads for all qns try and use the existing threads
Commenting on this post has been disabled by the moderator.
Q1. If x, y and z are integers and x + y + z = 3, the what is the minimum value of
1/x + 1/y + 1/z ?
Q 2 what is the least value of (x-1) (x-3) (x-4) (x-6)+10, for real values of x?
Commenting on this post has been disabled by the moderator.