QUANT-2013. A topic A time

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Hello puys.As discussed we have decided to start a group where in we will prepare QUANT, dealing one topic at a time, till all the concepts are covered in that chapter. *Please see* this is *strictly* for questions dealing with ongoing top...
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@DeAdLy Bhai busy with some stuff....aaj kal thoda kum aata hoon pg par...will start full on from april onwards....:)
Born a RED..Will die a RED!!! YNWA!!!! https://www.youtube.com/watch?v=tPEmC3vN-bQ
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bhai log @saurav205 ,@Logrhythm @vbhvgupta @chandrakant.k & all others

tum logon ne to ye forum thanda kara diya
Khudi ko kar buland itna ki har takdir se pehle, Khuda bande se ye puche bata teri raza kya hai.
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@Pradeep_Rss said:
Avg weight of 5 officers is 42 kg . an officer was replaced by a new one so the avg increased by 500 gms . weight of new officer?? and the weight of the replaced officer ??
Cannot be determined....
You will just get their difference...
Born a RED..Will die a RED!!! YNWA!!!! https://www.youtube.com/watch?v=tPEmC3vN-bQ
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@Pradeep_Rss said:
Avg weight of 5 officers is 42 kg . an officer was replaced by a new one so the avg increased by 500 gms . weight of new officer?? and the weight of the replaced officer ??
I don't think this can be uniquely determined...

let the weight of all officers be 42 kg
avg = 42
replace one 42 kg with 44.5 kg to get avg as 42.5

or

let weight of 3 officers be 42 kg, 1 officer be 43 kg and 1 officer be 41 kg
let us remove 41 kg and add 43.5 to make avg 42.5

there can be other combinations as well....

so it cannot be determined uniquely....
There’s a beast within every man that stirs when you put a sword in his hand.
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Avg weight of 5 officers is 42 kg . an officer was replaced by a new one so the avg increased by 500 gms . weight of new officer?? and the weight of the replaced officer ??
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@aditi88 said:
guys can ne1 do this fr me im nt getting it ...
here you go :
first 50 runs : 4*4 +1*6 (4 fours and 1 six)
till he reaches 200 (every 30 run : 3 4s and 1*6)
total runs in boundaries till he reaches 200 = 4*4(for the 1st 50 runs) + 5*4*3(for the 5 30s he scores till he reaches 200) + 1*6(first 50 he scores 1 six) + 6*5(for the 5 30s he scores till he reaches 200)
= 112 runs

thereafter 2*6 + 1*4 for every 25 runs
maximum % will be when he scores 375 runs (h scores a triple century, as given in the question) and minimum % when he scores 300

so when eh scores 300 : he scores 4 25s and 1 25 contains 16 runs in boundaries .
so total boundary runs = 112+ 16*4 = 176
similary for 375 :
112 + 16*7 =224
calculate them in terms of % you'll get 59.73(for 375 runs) and 58.66(this is for 300 runs)
difference is approx 1.07
Born a RED..Will die a RED!!! YNWA!!!! https://www.youtube.com/watch?v=tPEmC3vN-bQ
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@aditi88 said:
guys can ne1 do this fr me im nt getting it ...
givme sometime...this is a long question but simple maths...
Take the upper case as 375 and lower case as 300...
and just follow the conditions given in the question..you will surely get the answer...
Born a RED..Will die a RED!!! YNWA!!!! https://www.youtube.com/watch?v=tPEmC3vN-bQ
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@saurav205 said:
Q4
guys can ne1 do this fr me im nt getting it ...:(
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@aditi88 said:
i dint knew abt the thread sm1 quoted me in this tats hw i saw re .........neways will try being alive...
hmm...visit the mumbai study group forum...you will remember how you came here...
anyway no spamming

Sorry guys for spamming..
Born a RED..Will die a RED!!! YNWA!!!! https://www.youtube.com/watch?v=tPEmC3vN-bQ
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@saurav205 said:
Q3options are :8lts11.5 lts13.3 lts16.5 lts18 lts
13.3 lit...OA
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