http://www.pagalguy.com/discussions/official-quant-thread-for-cat-2013-25088456

plz can u solve this 2 sum step by step if u dt mind

hi chakshu06

for 1ques. divide the numerator and the denominator by b(cube)

also divide the numerator and denominator by d(square)

simplify and u'll get..

(a/b)^3 + 1

_________________

(a/b)^2 + (a/b)*(c/d)

substitute the values.... and u'll get 19/18.

for ques 2.

see let the three digit number be abc

it's given tens digit, i.e b=(a+c)/2

also,

10b+c 10a+b

_____ = _____

b+c a+b

put b=(a+c)/2

u'll get a=c

hence

numbers can be of the form ...

111

222

333

444

555

666

777

888

999

Correct me, if i am wrong :)

ans 1) 19/18

1. If a:b= 3:4 and c:d= 2:3 then find a(cube)* c(square) + b(cube)* d(square) divided by a*b(square)* d(square) +a(square)*b*c*d