Official Quants Group|CAT:2019|MBA:2020-2022

Minimum value 0.

Write 4a^2 + 12a in form of perfect square, it will be written as 4(a^2 +9/4 + 2*3a/2), do the same thing for the elements containing b too, you shall have this: 4(a+3/2)^2 + 9(b-4/3)^2.

005,014,023,113,122. There is no case jisme koi box aisa na ho jisme 1 or less balls hain.

We can just think of it this way. No box can have more than 1 ball. So maximum balls that we can arrange are 3. We have 5. So 0 ways. I think the purpose of the question was just to confuse the test taker as you would usually expect the number of balls to be less than number of boxes in such a question

26*26*26*26.

@TanujA3 thanks. I got it. I was thinking of 26*25*24*23 but then it says that repetition is allowed

@Cutiepie1995 the avg is coming as 172. The answer is 173.9 as marked. Explain pls

Oh the range has been mentioned since x, y, z values are not defined. Thanks :)

P = 25200 , Q  = 25410  Difference is 210

i) For CI, Annual istallment of X=14520 is made. P= (X/1.1) + (X/1.21) See the present value of the each installment

ii) For SI, Final amount after 2 years = (1.1)X+X  This is equal to Q(1.2) 

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Just form the equations normally.

Let no of educated ppl = e

Let salary of 1 educated person = x

(ex + 20*25)/ (e + 20) = A

(ex + 20*10)/(e+20) = A - 10

Now,divide first eqn by second.

you would get ex = 30A - 500

Put this in first eqn, you would get e as 10.

@anushavalecha11 thanks man