For distinct. Total combinations is 55. Now let's say x=y!=z. So 1,1,10. 2,2,8... 5,5,2. Total 5 combinations. Subtract 1 where x=y=z. So 4 solutions. Similarly for y=z. And x=z. So total 12 combinations. Now add back x=y=z. So 13 combinations. So distinct possibilities are 55-13 = 42
For distinct. Total combinations is 55. Now let's say x=y!=z. So 1,1,10. 2,2,8... 5,5,2. Total 5 combinations. Subtract 1 where x=y=z. So 4 solutions. Similarly for y=z. And x=z. So total 12 combinations. Now add back x=y=z. So 13 combinations. So distinct possibilities are 55-13 = 42
@sohamsp14 y=z and x=z mein 7 total kaise aya?? thoda sa detail please.
yaha pe 10 ,1,1 ayega kya???