thanks varun for givin me touch of jabalpur by opening this thread

i was missing jabalpur's threads as there was no thread of jabalpur

now u hav solved d problem. now cheers and

**lets start the marathon to cat08**

I really thought this was madatory...for our preparations..every city group is preparing very well...and so we all have to make some efforts...post and discuss...

Hello Sir,

I'm also from J.E.C.Thanks for this thread it resolved my prolonged problem.

**Today's concept...few tricky questions on divisibility**

concepts...

concepts...

**a^n - b^n is always divisible by a-b**

**a^n - b^n is divisible by a+b when n is even.**

**a^n + b ^n is divisible by a+b when n is odd.**

**a^n + b^n + c^n +... is divisible by a+b+c+.... when n is odd.**

**when last n digits of a no. are divided by 2^n, the remainder is same as the remainder when the entire no. is divided by 2^n.**

**Answers to yesterday's questions.**

1. smallest no. that must be added to 1000 so that the resultant no. leaves remainders 2,3,4,5 with 5,6,7,11 respectivelt----667

2. smallest no. that leaves remainders 1,2,5,6, when divided successively by 2,3,4,23.----such a no. doesnt exist as 5 rem with aint possible.

3. smallest no. that leaves remainders 4 everytime when successively divided by 7,5,10,13 respectively.----872

4. a no. leaves remainders 2,5,3,7 when successively divided by 3,7,6,9. what is the remainder when this no. is divided by 126?----80

5.find the largest no. that leaves same remainder when it divides 2345,7645,9845,6595 and 10095.----50

6.a no. when divided 88 leaves remainder 3. what is the remainder when its divided by 11? ----3

7.a no. when divided by 391 leaves rem. of 49. find the remainder when its divided by 39...options 29,10,none of these,cannot be determined.---cannot be detrmnd

**kudos to rockeezee who got most of them right!**

**questions for today...**

**1. 32^23 + 17^23 is definetly divisible by....**

**a. 49 b. 15 c. 49 & 15 d. none of these.**

**2. 32^23 - 17^23 is definetly divisible by....**

**a. 49 b. 15 c. 49 & 15 d. none of these.**

**3. 32^232 + 17^232 is definetly divisible by....**

**a. 49 b. 15 c. 49 & 15 d. none of these.**

**4. 32^232 - 17^232 is definetly divisible by....**

**a. 49 b. 15 c. 49 & 15 d. none of these.**

**5. 32^2321 + 17^2321 + 13^2321 + 18^2321 is definetly divisible by....**

**a. 40 b. 20 c. 80 d. all of these. e. none of these.**

**what is the remainder when 42527152653425416242624272427215287 is divided by :**

**6. 16**

**7. 32**

**8. 64**

**Today's concept...finding factors of a no. n sorting relevant questions.**

**concepts...**

**#1. to find total no. of factors of a number.**

=>first of all...express it in terms of prime numbers

e.g 1260^4.

express it as (2x2x3x3x5x7)^4 = 2^8 * 3^8 * 5^4*7^4.

=>now add 1 to the powers of every prime no. n multiply them all...u get the total no. of factors of 1260^4.

i.e (8+1)*(8+1)*(4+1)*(4+1) = 2025 = total no. of factors of 1260^4.

**#2 to find no. of odd factors of a number.**

leave power of 2 and multiply powers of all other prime nos after adding one to them.

i.e. (8 + 1)*(4+1)*(4+1) = 225 = no. of odd factors of 1260^4

**#3 to find no. of even factors of a number.**

take the difference of total factors and odd factors.

i.e. 2025 - 225 = 1800. = no. of even factors of 1260^4

**#4 to find in how many ways can a given no. be represented as product of two relatively prime factors**.

in this case, the power of prime no. becomes irrelevant as all the powers shud lie with the same factor else the two factors wont be relatively prime.

i.e in the above case 1260 = (2x2x3x3x5x7)^4 = 2^8 * 3^8 * 5^4*7^4.

now powers 8,8,4,4 have no importance...whats important is how many prime nos. are there...they are four...viz 2,3,5,7. hence 4.

now v have to form nos. using these 4 primr nos. its a like a question askin u...if u have 4 sweets...in how many ways can u eat them? the answer is 4C0..when u eat none... + 4C1 when eat any one...+4C2 + ...4C4...when u eat all.

similarly here, answer wud be 4C0 + 4C1 + 4C2 ...4C4 = 2^4 = 16.

but the factors have to exist in pairs...hence 2^4/2 = 8 factors are possible.

on a general note...a no. formed of n prime nos has 2^(n-1) pair of co-prime factors

**Answers to yesterday's questions**

**1. 32^23 + 17^23 is definetly divisible by....**

**a. 49 b. 15 c. 49 & 15 d. none of these.**

**2. 32^23 - 17^23 is definetly divisible by....**

**a. 49 b. 15 c. 49 & 15 d. none of these.**

**3. 32^232 + 17^232 is definetly divisible by....**

**a. 49 b. 15 c. 49 & 15 d. none of these.**

**4. 32^232 - 17^232 is definetly divisible by....**

**a. 49 b. 15 c. 49 & 15 d. none of these.**

**5. 32^2321 + 17^2321 + 13^2321 + 18^2321 is definetly divisible by....**

**a. 40 b. 20 c. 80 d. all of these. e. none of these.**

**what is the remainder when 42527152653425416242624272427215287 is divided by :**

**6. 16----7**

**7. 32----23**

**8. 64----55**

**questions for today...**

**on the very simple fundas above, very tricky questions can be framed.**

**Find the smallest no. that has exactly.....**

**1. 16 factors**

**2. 12 factors**

**3. 60 factors**

**4. how many factors of 27000 are perfect cubes?**

**how many A.Ps are possible such that first term is 1235 and the last term is 3535 and there are atleast...**

**5. 3 terms**

**6. 4 terms**

**7. 5 terms**

**8. 6 terms**

**How many values of a are possible if x^2 + ax + 2400 has...**

**9. integral roots**

**10. roots which are natural nos.**

Hey we can discuss here everyone's mock analysis..and things which r needed to be taken care of ...a good strategy needs to be done...thats all..

Ok,

As far the strategy goes , I read some of the analyses of some good people , and this is what I suggest.:

VA general strategies:

1.Read an RC as if you are the author. Blank ur mind when u start the RCs. Ur individual opinion while reading/doing an RC is useless. So is you prior knowledge. The questions are asked from the viewpoint of the author, and youve got to answer them in that sense. Remember, for RCs, You DO NOT have any knowledge/opinion.

2.Read newspapers and enjoy them. Dont read stupid weird articles just because you want to improve your VA. Read funny, sexy articles that you like and enjoy. Its a much better way of improving your English than reading up on the etymology of words from thick red books.

3.Word-lists are stupid and a waste of time. They are not important for CAT. Burn your word-lists.

DI general strategies:

1.Do NOT spend more time on a set just because youve already spent some time on it. Wasted time does not merit more time to be wasted. If after 20 minutes of reading a set, you do not understand it, the LEAVE it!

2.Practice! Practice only from mock-cats. The BRMs are generally for ppl who are going to give cat in 2010, and I expect none of you are like that.

QA general strategies:

1.Make sure you read ALL the questions! Even if they are from pathetic topics like PnC or Probability. This way, youll never feel like a fool later for not having read a question completely.

General strategies:

1.Give equal importance to the three sections in terms of time. This simple rule, whenever violated, has caused havoc. Do not allot less than 40 minutes for any section, whatever be the compulsion.

2.Your primary aim in all these mocks is to clear ALL the cut-offs in every paper. Trust a 4-times cat taker on this, if you can clear ALL three cut-offs in cat, theres a 99.99% chance of you clearing the total cut-off as well, and making it to the next stage.

3.Do not bother whether the paper is tough or not. Your job is to make sure that by the end of the paper you have read all the questions and feel happy that youve given it your best shot.

4.Remember, the Real competition is with yourself and your past scores. The zillion other people writing the mock are not your problem. Its their problem that you are writing the mock as well.

Wasie bahut kuch CP hai thorugh dusre Threads...but still its good info as a collection

Hi,

This Is Varun,

I am starting this new JEC study group.

Aims at creating a virtual Coaching ,where we all can contribute and can give tips and get tips for preparation for This year's MBA exams.

Our discussion will vary from CAT to JMET,SNAP and every other MBA exams which poeple are aiming for.

CAT starts at NOV 16 2008 and so our preparation should also..reach the climax till NOW 16 .

Its an introductory thread ..Looking for all poeple to contribute...

I will remind every one ..do not ignore GK...Its imporatant for IIFT.

I apreciate if u all contribute good poeple to this thread...