can anyone send me attachment shortcut method of train,mixture,alligations etc

please please send me attachment

what will be the answer to this question :

If you have 3 tickets to a lottery for which 10 tickets were sold and 5 prizes are to be given, the probability that you will win at least one prize is:

a. 7/12

b. 9/12

c. 1/12

d. 11/12

please explain. thanks!

i think 11/12 is right

if the 3 tickets are such that none of them has any prize on them, then these three can be selected from 5 in 5C3 ways = 10 ways

total ways of selecting 3 tickets from 10 is 10C3 = 120 ways

so probability that none wins a prize = 10/120

so atleast one = 1 - 1/12 = 11/12

what will be the answer to this question :

If you have 3 tickets to a lottery for which 10 tickets were sold and 5 prizes are to be given, the probability that you will win at least one prize is:

a. 7/12

b. 9/12

c. 1/12

d. 11/12

please explain. thanks!

i got the answer! its 11/12.. correct me if i m wrong..

my logic : Probability that you will win at least one prize = 1 - probability that you will not win any prize. therefore 1-(7C5/10C5) i.e. 1-(1/12) = 11/12

7C5 coz all 5 prize will b from the remaining 7 tickets and 10C5 coz from 10 tickets, 5 prizes will be picked.

what will be the answer to this question :

If you have 3 tickets to a lottery for which 10 tickets were sold and 5 prizes are to be given, the probability that you will win at least one prize is:

a. 7/12

b. 9/12

c. 1/12

d. 11/12

please explain. thanks!

any idea how to solve questions like this.

x^2 - 2x + y^2 -4y +5 = 0 on the XY plane represents

1.a point

2.a circle

3.an ellipse

4.a hyperbola

x^2 -2x + 1 + y^2 -2*2y + 4 = 0

(x-1)^2 + (y-2)^2 = 0

so its a point !

any idea how to solve questions like this.

x^2 - 2x + y^2 -4y +5 = 0 on the XY plane represents

1.a point

2.a circle

3.an ellipse

4.a hyperbola

Derrida SaysAnd I ask why to do it? I'm sorry if you find my response stupid, but wouldn't there be other easier pickings in the paper?

It looks scary coz writing a matrix as such is not possible for me on computer. if omeobdy can solve it, it will be great help, otherwise coz i dont know how 2 do it, i would b leaving it. IMS has given such questions in JMET sample papers. dats y i wanted 2 know how 2 do it.

Ques. A= {(1,-1,0),(0,0,-1),(0,1,0)} is the matrix of linear transformation T with respect to basis {(1,0,0),(0,1,0),(0,0,1)}. Find the matrix of T with respect to the basis {(0,1,-1),(-1,0,1),(0,0,-1)}

i) A= {(1,0,-1),(1,-1,0),(2,2,-1)}

ii) A= {(0,1,0),(-1,0,0),(-1,-1,-1)}

iii) A= {(-1,1,-1),(1,1,0),(1,-2,-2)}

iv) A= {(1,-1,1),(1,1,0),(-1,2,-1)}

How to do this?

And I ask why to do it? I'm sorry if you find my response stupid, but wouldn't there be other easier pickings in the paper?

Ques. A= {(1,-1,0),(0,0,-1),(0,1,0)} is the matrix of linear transformation T with respect to basis {(1,0,0),(0,1,0),(0,0,1)}. Find the matrix of T with respect to the basis {(0,1,-1),(-1,0,1),(0,0,-1)}

i) A= {(1,0,-1),(1,-1,0),(2,2,-1)}

ii) A= {(0,1,0),(-1,0,0),(-1,-1,-1)}

iii) A= {(-1,1,-1),(1,1,0),(1,-2,-2)}

iv) A= {(1,-1,1),(1,1,0),(-1,2,-1)}

How to do this?

z +6 = +/- 3

z = -3 or -9

substitute

largest magnitude = 6

You see you've reduced the whole argand plane to the real number line....Nice .

BTW, anyone has any sample ATM tests?