Please continue here:

http://www.pagalguy.com/discussions/geometry-for-cat-2012-25074749/3053072

Hi Guys,

Geometry, Algebra and Number system form the major chunk of our QA section for CAT.

Proficiency in these three sections would definitely boost our Quants scores.

Contents of Geometry

1. Plane Geometry - Basics and Triangles

2. Polygons and Quadrilaterals

3. Circle

4. Mensuration

5. Trignometry

6. coordinate Geome

i tried to dowmload it..but was nt able to do so:-(...help..my email id is bhavyamehta1421@gmail.com

regards

bhavya

same here dude..were u able to do it later..plz reply..regards bhavya

vibhormittal360 SaysThere are 3 balls in a plane touching each other equally and above it another ball placed touching all the balls equally, we have the find the distance of the bottom of the above ball to the ground...how can this problem be solved???

Three balls touching each other can placed like

:-(:-(

:-(

consider these connected to each other, And a ball is above in the center,

now the ball center from earth above earth is radius of any ball.

now the centers of 3 balls makes the equilateral triangle.

try to imagine a ball above it...

if you keep a ball above it

it will take a shape like pyramid. base is Equi. triangle and top is in middle

if we draw a perpendicular on the triangle it will meet centroid. so centroid is 2/3 of perpendicular inside the triangle.

Now you need to again apply one time for hight.

than hight+ radius is your answer.

I hope I am pretty clear on that.

Thanks

Ashish

There are 3 balls in a plane touching each other equally and above it another ball placed touching all the balls equally, we have the find the distance of the bottom of the above ball to the ground...how can this problem be solved???

Guys which book is best for Geometry and trigo preparation? Please help me as I am going to start my prep.

Hi Puys,

I have a geometry Q which I'm stuck with. Please post the solution if u are able to solve it.Q)In a cyclic quadrilateral ABCD, AB = 2, BC = 3, CD = 4 and AD = 5. What is the ratio of the lengths of the diagonals?

a) 7:11

b) 11:13

c) 10:11

d) 13:15

e) 15:7

Thanks in advance,

Sandeep

**Diagonals in a Cyclic Quadrilateral**

In a cyclic quadrilateral ABCD the ratio of the diagonals equals the ratio of the sums of products of the sides that share the diagonals' end points. In other words,

(1) AC / BD = (ABAD + BCCD) / (ABBC + ADCD).

**Proof**

Triangles PAD and PBC are similar, so that

PA/PB = AD/BC = PD/PC,

which can be also written as

(2) ABAD/PA = ABBC/PB, and

BCCD/PC = ADCD/PD, In the same manner, the similarity of triangles PAB and PDC implies

(3) ABAD/PA = ADCD/PD.

which shows that four expressions

(4) ABAD/PA, ABBC/PB, BCCD/PC, and ADCD/PD are all equal. (1) follows by combining the first and the thrid terms and also the second and the fourth.

Hi Puys,

I have a geometry Q which I'm stuck with. Please post the solution if u are able to solve it.**Q)** In a cyclic quadrilateral ABCD, AB = 2, BC = 3, CD = 4 and AD = 5. What is the ratio of the lengths of the diagonals?

a) 7:11

b) 11:13

c) 10:11

d) 13:15

e) 15:7

Thanks in advance,

Sandeep

sorry the data was missing

Q is the point of intersection of AC and DB inside the circle

wat is point Q dude ??? i mean how is AQB forming...data missing i guess