# Algebra, Quadratic Equations, Inequalities, Functions

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The number of real roots of the equation |1 - |x|| - (1.01)(1.01x) = 0 is/are
Page 1 of 97 ﻿Ashok went on a tour. He visited a total of 8 cities. In each city he spent र2 less than half the amount he had with him. He spent र100 in the last city he visited. Find the amount he had initially (in र).

12804
25604
24580
24804 This is an extremely easy question but I am missing sth while solving it algebraically. Pls help.

|y|+|y+2|=2................Solve for y @kimig  ·  166 karma

plzz give the exact solution with values and the correct answer too @priyanjit  ·  322 karma

y = [-2,0] . First consider for positive values, hence : y+y+2 =2 , so y = 0 and then consider for negative values, -y -y-2 =2 , so y= -2, so that is the range. I hope this is useful. Write a comment
Write a comment... any link or page on reflection of points/graphs specially for quadratic or cubic eq. ?? Write a comment
Write a comment... A=log10(1+2+3+.....................n)+log10^2. where n is a natural number .find the number of possible value of n for which but range is 1

(1)28

(2)31
(3)29
(4)38 confused , what does it means, "for which but range is 1" @priyanjit  ·  322 karma

is it 10 multiplied by (1+2+3..n) or it is base 10. Write a comment
Write a comment... How many 4-digit postive integral number are their base?If the number of such number is converted to the same base?

(1)2058
(2)5666
(3)6000
(4)NOTA

1 comment @karan77sethi  ·  30 karma

if any can do pl Write a comment
Write a comment... IF x=12, then the value of x^5-13x^4+13x^3-13x^2+13x-1?

(1)0

(2)1

(3)2

(4)3 @priyanjit  ·  322 karma just factorized it and took out x Write a comment
Write a comment... Find the number of real solution of a equation is

x=(x-1/2)^(1/2)+(1-1/2)^(1/2)

(1)0

(2)1

(3)2

(4)3 @rashmi84  ·  0 karma

1 @AV91  ·  0 karma

second term is non zero +ve while first term can not be negative because square root can't be -ve hence  no solution. Write a comment
Write a comment... The reflection of the graph y=(x+3)(x+4) in the point (2,2) is

-x^2+15x+52
-x^2+15x-52
x^2+15x-52
x^2+15x+52 The reflection of the graph y=(x+3)(x+4) in the point (2,2) is

-x^2+15x+52
-x^2+15x-52
x^2+15x-52
x^2+15x+52 A given sequence of terms is such that in any set of four consecutive terms, the sum of the first and third terms is equal to the sum of the second and fourth terms. The 3rd and 14th terms are 4 and 7 respectively and the sum of the first 18 terms is 57.

What is the 56th term of this sequence?

mann mai hai vishwaas, hum hongey kaamyaab ek din!! @chayanmunjal  ·  0 karma
@robin_jain619

please explain how you solved this?approach? @robin_jain619  ·  0 karma

assume sequence to be a,b,c,d,e now given a+c=b+d ,b+d=c+e by this a=e by this we can say that every fourth term is similar. solve it further you will get the answer. Write a comment
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