QA 23A 18C 5W - 49

VA 23A 17C 6W - 45

OA 46A 35C 11W-94

Hardest mock of the season(havn't given 1301)

QA was difficult(not one question was a sitter)

LR was out of this world...i took 42 min to solve 3 sets and was left with 28 min for VA in which i attempted all grammar/vocab questions and 1 RC( 4 questions wala- attempted 3)

so it tested my patience as i have never taken more than 25 min in LR section...!!!

Can anyone tell me what %ile would these scores have gotten ?

@[549423:ashish1909] Please send me the aimcat papers1318,1316 and 1314 guys..Just started preparing for cat 2012...Tension has gripped my nerves! E Mail: pravatnanda@yahoo.com

@[267494:priyaghosh] : please give me your mail id.. I will fwd you !

someone please mail me the pdf of 1314..it will be very helpful

@ashish1909 said: please send me the aimcat ques papers 1318,1316and 1314 ........will be very thankfull to you ....my mail id is ash_sharma45@yahoo.com

please send me the aimcat ques papers 1318,1316and 1314 ........will be very thankfull to you ....my mail id is ash_sharma45@yahoo.com

Hi Puys,

Doing some question of Maxima and Minima

Don't have answere for some question

I am writitng question and my answere

Please check

Ques.To find the dimension of the cubical box of maximum vol that has one croner at the origin, three sides that contains the corner lying in the 3 cordiante planes and the opposited corner lying on the plane 2x+3y+4z=12 in the first octant ?

My answere 64/81 cubic unit.

Q2.Find The Maximum Value of x^2y if x and y are restricred to positive real number satisfying 6x+5y=45

My Answer 225

Q3.For any +ve constant a, what is the maximum value of x/(x^2 +a) for +ve x ?

My Answer 1/(2 squroot a)

Q4.Find the Least value of xy+2xz+3yz for +ve number x,y,z saisfying xyz=48.

My ANswer 72

Q5.Find the minimum value of the product (x+y^2+z^3)( (1/x) +(1/y^2) + (1/z^3)) for +va value of x,y,z

My answer is 9

Q6.Find the smallest value of 5x+(16/x)+21 for +ve value of x

My Answer 8*squrt5+21

Please reply ur answer with explanation.

Thanks and Regards

Another Puy

@[346223:yesarpit] PM me also my mail id is mpsgrover@gmail.com 😃