# advance maths for beginners-concepts and doubts

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to discuss advance maths topics in detail

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The least number that must be substracted from 63520 to make the result a perfect square is

hum honge kaamyab ek din ........................
@vishiac  ·  5,092 karma

@caemento For every now and then, dont say sorry bro... 😂 😂

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@caemento  ·  2,052 karma

@vishiac 👌 😂 😂

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if a^2=by+cz,   b^2=cz+ax, and c^2=ax+by, then value of x/(a+x) +y/(b+y)+z/(c+z) is

options 1       a+b+c          1/a+1/b+1/c        0

hum honge kaamyab ek din ........................
@caemento  ·  2,052 karma

@vishiac fine bro😀

@caemento  ·  2,052 karma

@vishiac need 2 b in study mode now😑

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if x+1/x=3

then x^3+1/x^2=

options   11,    83/9       7       13/9

hum honge kaamyab ek din ........................
@vishiac  ·  5,092 karma

@caemento But ans will be surd, not a whole number

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@SujataPatil  ·  2,359 karma

@vishiac bro this @caemento has given wrong ques to solve!!!! 😂

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if x+1/x=1

then (x+1)^5+1/(x+1)^5=

options

a)4     b)8   c)1      d)2

hum honge kaamyab ek din ........................
@SujataPatil  ·  2,359 karma

@vishiac hmmm.... calc mistake!!! 😐

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@caemento  ·  2,052 karma

@SujataPatil it happens 😄

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@vishiac bro hav to ask few ques.... i too hav solved those... but having some confusion!!!

@vishiac  ·  5,092 karma

@SujataPatil Spend 30mins to build ur vocab everyday(maybe collection of 20 words a day) (then u wil have no problem with synonyms and antonyms)... If I touch a newspaper, its only to do Su-do-ku 😆 😆 .... That makes u better than me..... 😂

@SujataPatil  ·  2,359 karma
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@SujataPatil @caemento When the question comes asking for maximum possiblities and minimum possibilities and includes variables, concentrate on two things 1. boundary conditions 2. which variables has to be considered or varied (this part comes only with practise)....... When too many variables are there, use options rather than solving and check if it satisfies the boundary conditions......

@SujataPatil can u just repost that image which u had posted in morning.... I am on desktop now... Its better u upload it as a separate post.

@caemento  ·  2,052 karma

@vishiac bro leaving now 👋

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@vishiac  ·  5,092 karma
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@vishiac @caemento if the sum of (2n+1) prime num where n€N is an even num , then one of d prime num's must be a. 2 b. 3 c. 5 d. 7

@caemento  ·  2,052 karma

@grawat  ·  62 karma

@SujataPatil 49 answer for the difference one

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@caemento @SujataPatil what's going on ppl... Two more days then I will join u actively.. Got anything for me, I have 15-20min...

@vishiac  ·  5,092 karma

@SujataPatil check on optimization problems it will in these kind of problems.... I will be back at 9.30 and will post on how to do go for such problems... Now out of time :(

@SujataPatil  ·  2,359 karma

@vishiac ok bro.. ☺

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@SujataPatil  ·  2,359 karma

@caemento correct bro... 525z + 341... for z=0,1... so two 3 digit nums

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@caemento  ·  2,052 karma
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