vivek417's posts
vivek417 replied to Number System
U have...the following eqns
x+y+z = 105
x+0.5y+0.25z = 50.5
& z = (233.33/100) x
Solve these in terms of x & y..to get the values..thats all
Thanks
Vivek
vivek417 replied to Fact, Inference, Judgement For CAT 2008
My take:-
1) J
2) I
3) J
4) J
Thanks
Vivek
vivek417 replied to official quant thread for cat08
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vivek417 replied to official quant thread for cat08
m^2 + 100m + 1000 = k^2
(m+50)^2 = k^2 +1500
(m+50-k)(m+50+k) = 1500
Now 1500 = 2^2*3^1*5^3...
So we have 3*2*4 = 24 factors
Now m+50+k should always be greater than 50
& m+50-k should always be less than 50
Use these criteria to filter out the values from 24 factors.....we w...
vivek417 replied to official quant thread for cat08
Here we have sin q + cos q = -b/a
& sin q * cos q = c/a
Now for the options....divide throughout by a^2....
like a^2-b^2+2ac=0
divide by a^2 then we have 1 - (b/a)^2 + 2*(c/a) = 0....now put the values & check.....thats it
Thanks
Vivek
vivek417 replied to official quant thread for cat08
Clearly only b satisfies the criteria. (0,0) gives negative result while (2,3) gives positive.
Thanks
Vivek
vivek417 replied to official quant thread for cat08
Here is my solution....
Sum of all numbers formed by n digits (a,b,c,d...n) = (n-1)! * (Sum of all digits) * 11...n times
So here we have 3! *(2+3+3+4) * 1111 = 79992
But since we have 2 3's...so total sum 79992/2 = 39996
Thanks
Vivek
vivek417 replied to official quant thread for cat08
I am getting answer as 3.5.
Lines are as follows:-
y=-x
y=-x+1
y= x-2
& y= x+5
So area = (7/2)*(2)^0.5 * (1/2)*(2)^0.5 = 7/2 =3.5
Thanks
Vivek
vivek417 replied to official quant thread for cat08
Let the triangle be ABC & square be MNOP...
Here M lies on AB while P lies on BC.
Let side of square = x
So Sin 60 = x/BM
BM = 2x/root(3)
AMN is equilateral triangle...clearly visible
So AM = x
But BM + AM = 1
So 2x/root(3) + x = 1
Solve this to get the answer.
Thank...
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vivek417 replied to official quant thread for cat08
(2x/3^0.5) + x = 1...here x is side of square
Solve it ...we get x = 2(3)^0.5 - 3
So area of square = x^2 = 21-12(3)^0.5
Thanks
Vivek