vivek417's posts

vivek417
replied to official quant thread for cat08

m^2 + 100m + 1000 = k^2

(m+50)^2 = k^2 +1500

(m+50-k)(m+50+k) = 1500

Now 1500 = 2^2*3^1*5^3...

So we have 3*2*4 = 24 factors

Now m+50+k should always be greater than 50

& m+50-k should always be less than 50

Use these criteria to filter out the values from 24 factors.....we w...

(m+50)^2 = k^2 +1500

(m+50-k)(m+50+k) = 1500

Now 1500 = 2^2*3^1*5^3...

So we have 3*2*4 = 24 factors

Now m+50+k should always be greater than 50

& m+50-k should always be less than 50

Use these criteria to filter out the values from 24 factors.....we w...

vivek417
replied to official quant thread for cat08

Here we have sin q + cos q = -b/a

& sin q * cos q = c/a

Now for the options....divide throughout by a^2....

like a^2-b^2+2ac=0

divide by a^2 then we have 1 - (b/a)^2 + 2*(c/a) = 0....now put the values & check.....thats it

Thus answer is b.

Thanks

Vivek

& sin q * cos q = c/a

Now for the options....divide throughout by a^2....

like a^2-b^2+2ac=0

divide by a^2 then we have 1 - (b/a)^2 + 2*(c/a) = 0....now put the values & check.....thats it

Thus answer is b.

Thanks

Vivek

vivek417
replied to official quant thread for cat08

Let the triangle be ABC & square be MNOP...

Here M lies on AB while P lies on BC.

Let side of square = x

So Sin 60 = x/BM

BM = 2x/root(3)

AMN is equilateral triangle...clearly visible

So AM = x

But BM + AM = 1

So 2x/root(3) + x = 1

Solve this to get the answer.

Thank...

Here M lies on AB while P lies on BC.

Let side of square = x

So Sin 60 = x/BM

BM = 2x/root(3)

AMN is equilateral triangle...clearly visible

So AM = x

But BM + AM = 1

So 2x/root(3) + x = 1

Solve this to get the answer.

Thank...

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