Viraj_Deshpande's posts
Viraj_Deshpande commented on an article
Dressed in shorts and a crumpled white t-shirt and sitting coyly in his apartment in Dombivali, on the outskirts of Mumbai, Shashank Prabhu looks more like the teenager next door who you'd see rushing to his tuition classes. But once he begins to speak, the confidence and command of a topper are quite evident. Prabhu topped t...
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drvispute C u in IIM next yr !. 04 Sep '10.
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Viraj_Deshpande replied to Quant by Arun Sharma
My solution:
Every no. can be expressed in the form of 9k or 9k+1 or 9k-1 or 9k+2 or 9k-2 or 9k+3 or 9k-3 or 9k+4 or 9k-4, where k is an integer.
2998 = 9 * 337 + 1
Thus, 1 to 3000 (Excluding 1 and 3000) has
334 nos. of type 9k+2 (because of no. 2999) and
333 nos. of type 9k+1, 9k,...
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Viraj_Deshpande replied to Revant aka Profootball25 getting hitched!
Congrats Revant!
Viraj_Deshpande replied to Number System
6711+4179 is possible.
First_timer's solution (above) is correct.
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Viraj_Deshpande replied to Number System
Test of divisibility by 11 is that sum of odd-placed nos = sum of even-placed nos.
Looking at the options, their (sum of even-placed nos. - sum of odd placed nos.) = (8-7=)1, (14-7=)7, (8-10=)-2 and (14-10=)4 respectively.
y=1, z=7, w=3 or 6 or 9, x=2 or 4 or 6 or 8
Thus the nos. (and t...
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Viraj_Deshpande replied to Quantagious
(x+y)^2 = x^2+2xy+y^2 = 2007 - 54X^2 = 9 (223 - 6X^2)
Thus, (x+y) = 3k, where k is an integer
9k^2 = 9(223-6x^2) gives 6x^2=223-k^2
Since 3 divides (223 - k^2), k^2 should be of the form (3p+1).
k^2 of the form (3p+1) where (223-k^2)/6 is also a perfect square are found by listing the...
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Viraj_Deshpande replied to Geometry
Area of triangle = 0.5*b*c*sinA
Thus area = 10sinA
Clearly, this is <=10, equality existing when A=90 degrees.
Bound means the maximum value it can attain.
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Viraj_Deshpande replied to official quant thread for CAT 2009
RHS is not 22752*x. It is only one no. with x in its units place. Hope this clears the confusion
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Viraj_Deshpande replied to official quant thread for CAT 2009
Their HCF is 45 means they dont have any other common factor except 45, otherwise it would've figured in the HCF. Hence, once we divide both by 45, what remains should be a pair of co-prime nos.
Viraj_Deshpande replied to official quant thread for CAT 2009
No. of divisors of 21600 with HCF 45 = No of co-prime divisors of 21600/45 (=480). This should help.
There is some formula for no. of pairs of co-prime divisors. Cant recollect now. Will post here if I manage to recollect in time.