The_Op's posts

The_Op
replied to Official Quant Thread for CAT 2010

We need to find 2^999 mod 10000

So, to make them co-primes, we cancel 2^4 from Nr. & Dr.

(we will multiply the remainder thus obtained with 2^4)

So, it becomes 2^995 mod 625

By Totient Theorem(already stated in previous posts)

(625) = 500

So, 2^995 mod 625 = 2^495 mod 625

Le...

So, to make them co-primes, we cancel 2^4 from Nr. & Dr.

(we will multiply the remainder thus obtained with 2^4)

So, it becomes 2^995 mod 625

By Totient Theorem(already stated in previous posts)

(625) = 500

So, 2^995 mod 625 = 2^495 mod 625

Le...

2

The_Op
replied to Official Quant Thread for CAT 2010

Let the nos. be 2k+1, 2k+3 and 2k+5

So,Sum of the squares is

(2k+1)^2 + (2k+3)^2 + (2k + 5)^2

= 12(k)^2 + 36k + 35

= 12(k^2 + 3k + 2) + 11

So, It gives a remainder of 11 when divided by 12

Of the given options,

only (d) satisfies this condition.

So,Sum of the squares is

(2k+1)^2 + (2k+3)^2 + (2k + 5)^2

= 12(k)^2 + 36k + 35

= 12(k^2 + 3k + 2) + 11

So, It gives a remainder of 11 when divided by 12

Of the given options,

only (d) satisfies this condition.

2

The_Op
replied to CAT 2010 LR-DI thread

Chemical Plant Caselet

Comparing the scenarios of all tanks

'-' => Outflow

'+" => Inflow

A : -20 + 90 - 10 = +60 litres/minute

B : +20 - 100 + 110 = +30 litres/minute

C : -90 -50 + 100 = -40 litres/minute

D : +10 + 50 - 110 = -50 litres/minute

So,D gets emptied first

Ti...

Comparing the scenarios of all tanks

'-' => Outflow

'+" => Inflow

A : -20 + 90 - 10 = +60 litres/minute

B : +20 - 100 + 110 = +30 litres/minute

C : -90 -50 + 100 = -40 litres/minute

D : +10 + 50 - 110 = -50 litres/minute

So,D gets emptied first

Ti...

5

The_Op
replied to CAT 2010 LR-DI thread

The possible sequences are

(1) 4,5,6,7,8,9

(2) 5,6,7,8,9,10

(3) 6,7,8,9,10,11

(4) 7,8,9,10,11,12

Now,

(1) can be rejected as max. possible sum of 3 nos. = 7 + 8 + 9 = 24 (We have 26)

(3) can be rejected as min. possible sum of 3 nos. = 6 + 7 + 8 = 21 (We have 19)

(4) can ...

(1) 4,5,6,7,8,9

(2) 5,6,7,8,9,10

(3) 6,7,8,9,10,11

(4) 7,8,9,10,11,12

Now,

(1) can be rejected as max. possible sum of 3 nos. = 7 + 8 + 9 = 24 (We have 26)

(3) can be rejected as min. possible sum of 3 nos. = 6 + 7 + 8 = 21 (We have 19)

(4) can ...

6