120/3-120/4 = 10 so the answer should be 3. ?????
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ssc2012
replied to SSC CGL 2012 (Queries & Discussions) part-3
The answers is 9.6 cm.
make the diagram yourself and mark the center as O.
Drop a perpedicular OD to AB. clearly it divides AB into two equal halves 3cm each. Thus area of Area of OAB = (1/2) AB * OD = (1/2)6*4 = 12.
Now AO when extended meets BC at E. Further it should be noted that ...
make the diagram yourself and mark the center as O.
Drop a perpedicular OD to AB. clearly it divides AB into two equal halves 3cm each. Thus area of Area of OAB = (1/2) AB * OD = (1/2)6*4 = 12.
Now AO when extended meets BC at E. Further it should be noted that ...