Would love to come, agar seat milti he to..
Afterall its in Pune.

Hi Pune Junta,

Count me in too for CAT 2012 study group. Well, I have been part of PG since long time now. Actually, was a member of PDT 09. Had decided against MBA after season 09-10 , but the more i spend my time in my job, the more i realise importance of MBA to move up the ladder.

I may well be a veteran here with almost 5.5 years of work ex and with a good experience of writing CAT and OMETs. Will be always ready to help younger puys with any sort of queries they have.

I don't know if I should be preparing for CAT in the first place, and I don't care of the outcome. What I know is that there is still some fire left in me and THE thirst hasn't actually quenched.

I may sound crazy, but isn't this place called pagalguy!

Looking for support, encouragement and a helluva knowledge..

PS : ThinkAce saar... __^__O

Time to break silence

Easy one :

We are called 'track pizzas' in Newyork and 'One-unders' in London

Identify "We" :grin:

Commiting suicide by throwing oneself in front of an underground metro train.

ABC is a right angled triangle.
AC is the hypotenuse, and the lengths of all sides are integers. XYZ is another right angled triangle with XZ as hypotenuse.
given that XZ=SqrtAC
For what values of AC is it possible to find integer values for XY and YZ?
1)Even values
2)Odd values
3)Values divisible by 4 but not by 8
4)Values which are perfect squares
5)All values

Its not given that XZ has to be integer. In that case all values of AC can give integer values of XY and YZ.

Any pythagorean triplet can be written in the form of (a^2-b^2, 2ab, a^2+b^2) where x and y are integers

thus, for triangle ABC, AC = a^2+b^2 = XZ^2.
but XZ^2 = XY^2 + YZ^2
=> a^2+b^2 = XY^2 + YZ^2
=> XY = a and YZ = b.

upudit0 Says

A girl has a certain number of pets. All but two are dogs, all but two are cats and all but two are goats.How many pets does this girl have?

3 pets. 1 dog, 1 cat and 1 goat.

yes.
method plz.........

1.if N= 55^3+17^3-72^3, then N is divisible by
a. 7,13
b. 3,13
c. 3,17
d. none

2. if X = ( 16^3 + 17^3 + 18^3 + 19^3), what is the remainder when x id divided by 70.

1) 3,17

a^3+b^3-(a+b)^3 = -3ab(a+b)

2) 0

(16^3 + 19^3) + (17^3+18^3) = 70

In a sports contest there were m medals awarded on n successive days (n > 1).
1. On the first day 1 medal and 1/7 of the remaining m - 1 medals were awarded.
2. On the second day 2 medals and 1/7 of the now remaining medals was awarded; and so
on.
3. On the nth and last day, the remaining n medals were awarded.
How many days did the contest last, and how many medals were awarded altogether?

jain bhai ,sood bhai ,allan bhai plzz iska koi genuine approach dhundiye i have tried hit and trial

Hmmm...

end of 1st day remaining medals = m- = f(1) (lets say)
end of 2nd day remaining medals = f(1)- = f(2)
similarly,
end of (n-1)th day remaining medals = f(n-2)- = n (since on nth day only n medals were remaining...)

solving for f(n-2) = (13n-6)/6
this should be a whole number, so 13n should be divisible by 6..
so n = 6,12,18.....

what to do next...

A fisherman's day is rated as good if he catches 9 fishes, fair if 7 fishes and bad if 5 fishes. He catches 53 fishes in a week n had all good, fair n bad days in the week. So how many good, fair n bad days did the fisher man had in the week?
_/\_ Jain bhai,Allan bhai,Udit bhai,Koshti bhai and others as wellllllllll

x+y+z = 7
9x+7y+5z = 53

=> x-z = 2 and 2x+y = 9

since he had all the days atleast once, therefore x>2 and x<6
so the possible values of x are (5,4,3)

x = 5 will not satisfy 2x+y = 9 as y would be negative.

so, x= (4,3) y=(1,3) z=(2,1)..
possible solutions = (4,1,2) and (3,3,1)

In a group of N people, the probability of 2 people in the group sharing their birthdays is atleast 50 percent. What is the value of smallest such N.

A woman took a certain number of eggs to the market and sold some of them.
The next day, through the industry of her hens, the number left over had been doubled, and she sold the same number as the previous day.
On the third day the new remainder was tripled, and she sold the same number as before.On the fourth day the remainder was quadrupled, and her sales the same as before.On the fifth day what had been left over were quintupled, yet she sold exactly the same as on all the previous occasions and so disposed of her entire stock.What is the smallest number of eggs she could have taken to market the first day, and how many did she sell daily? Note that the answer is not zero.

***********************************************8
QA small terrace at a football ground comprises 15 steps, each of which is 50 m wide and is built of solid concrete. Each step rises to 0.25 m and a length of 0.5 m. Calculate the total volume of concrete required to the build the terrace.
OPTIONS
1) 750 cc
2) 650 cc
3) 550 cc
4) None of these

My Take

1) Total eggs she took on first day = 103
Eggs she sold everyday = 60.

2) 750, but its coming out to be 750 cu m, instead of 750 cu c. In the exam i would have selected 4) None of these.