shalin.ved's posts

shalin.ved
replied to 9th All India PaGaLGuY Meet (AIPGM), Pune May 2...

Would love to come, agar seat milti he to..

Afterall its in Pune.

Afterall its in Pune.

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shalin.ved
replied to Pune CAT 2012 Study Group

Hi Pune Junta,

Count me in too for CAT 2012 study group. Well, I have been part of PG since long time now. Actually, was a member of PDT 09. Had decided against MBA after season 09-10 , but the more i spend my time in my job, the more i realise importance of MBA to move up the ladder.

I may...

Count me in too for CAT 2012 study group. Well, I have been part of PG since long time now. Actually, was a member of PDT 09. Had decided against MBA after season 09-10 , but the more i spend my time in my job, the more i realise importance of MBA to move up the ladder.

I may...

5

shalin.ved
replied to quizzophile cum phylomath

Commiting suicide by throwing oneself in front of an underground metro train.

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shalin.ved
replied to Official Quant Thread for CAT 2012 [part 2]

Its not given that XZ has to be integer. In that case all values of AC can give integer values of XY and YZ.

Any pythagorean triplet can be written in the form of (a^2-b^2, 2ab, a^2+b^2) where x and y are integers

thus, for triangle ABC, AC = a^2+b^2 = XZ^2.

but XZ^2 = XY^2 + YZ^2

=> ...

Any pythagorean triplet can be written in the form of (a^2-b^2, 2ab, a^2+b^2) where x and y are integers

thus, for triangle ABC, AC = a^2+b^2 = XZ^2.

but XZ^2 = XY^2 + YZ^2

=> ...

shalin.ved
replied to Official Quant Thread for CAT 2012 [part 2]

3 pets. 1 dog, 1 cat and 1 goat.

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shalin.ved
replied to Official Quant Thread for CAT 2012 [part 2]

1) 3,17

a^3+b^3-(a+b)^3 = -3ab(a+b)

2) 0

(16^3 + 19^3) + (17^3+18^3) = 70

a^3+b^3-(a+b)^3 = -3ab(a+b)

2) 0

(16^3 + 19^3) + (17^3+18^3) = 70

shalin.ved
replied to Official Quant Thread for CAT 2012 [part 2]

Hmmm...

end of 1st day remaining medals = m- = f(1) (lets say)

end of 2nd day remaining medals = f(1)- = f(2)

similarly,

end of (n-1)th day remaining medals = f(n-2)- = n (since on nth day only n medals were remaining...)

solving for f(n-2) = (13n-6)/6

this should be a whole num...

end of 1st day remaining medals = m- = f(1) (lets say)

end of 2nd day remaining medals = f(1)- = f(2)

similarly,

end of (n-1)th day remaining medals = f(n-2)- = n (since on nth day only n medals were remaining...)

solving for f(n-2) = (13n-6)/6

this should be a whole num...

shalin.ved
replied to Official Quant Thread for CAT 2012 [part 2]

x+y+z = 7

9x+7y+5z = 53

=> x-z = 2 and 2x+y = 9

since he had all the days atleast once, therefore x>2 and x<6

so the possible values of x are (5,4,3)

x = 5 will not satisfy 2x+y = 9 as y would be negative.

so, x= (4,3) y=(1,3) z=(2,1)..

possible solutions = (4,1,2) and (3,3,1)

9x+7y+5z = 53

=> x-z = 2 and 2x+y = 9

since he had all the days atleast once, therefore x>2 and x<6

so the possible values of x are (5,4,3)

x = 5 will not satisfy 2x+y = 9 as y would be negative.

so, x= (4,3) y=(1,3) z=(2,1)..

possible solutions = (4,1,2) and (3,3,1)

2

shalin.ved
replied to Official Quant Thread for CAT 2012 [part 2]

In a group of N people, the probability of 2 people in the group sharing their birthdays is atleast 50 percent. What is the value of smallest such N.

shalin.ved
replied to Official Quant Thread for CAT 2012 [part 2]

My Take

1) Total eggs she took on first day = 103

Eggs she sold everyday = 60.

2) 750, but its coming out to be 750 cu m, instead of 750 cu c. In the exam i would have selected 4) None of these.

1) Total eggs she took on first day = 103

Eggs she sold everyday = 60.

2) 750, but its coming out to be 750 cu m, instead of 750 cu c. In the exam i would have selected 4) None of these.

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