santhosh_163's posts
santhosh_163 commented on a ping
RIP Neil Armstrong :(
santhosh_163 wow, new PG looks like FB :D . 26 Aug '12.
santhosh_163 looks cool :) though i love the old one more :-/ guess.... 26 Aug '12.
santhosh_163 replied to Official Quant Thread for CAT 2012 [part 3]
is there some proof ? or is there any way to solve ?
santhosh_163 commented on an article
Dr Uday Karmarkar Dr Uday Karmarkar, founder and director of the Business and Information Technologies Project (BIT) at the University of California's Anderson School of Management. BIT studies the impact of new online information and communication technologies on business practices worldwide. Karmarkar is in consideration ...
santhosh_163 what is the reason behind asking real name after every po.... 07 Apr '12.
santhosh_163 replied to Official Quant Thread for CAT 2012 [part 3]
max will be 2011*2010
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santhosh_163 replied to Official Quant Thread for CAT 2012 [part 3]
na your answer is right but approach isnt.. if the 2010 elements of both set same.. for ex: 1 to 2010, then the sum can be 2 to 4020 which itself is 4019.. if the next element you take is say 0 or 2011, then you will get one more new sum either 1 or 4021.. hence 4020 is the minimum no of elements
santhosh_163 replied to Official Quant Thread for CAT 2012 [part 3]
cant find any good approach.. is it 4010 by any chance ? :)
edit : sorry 4020.. i meant 2011+2010-1 but made a mistake in the addition
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santhosh_163 replied to Official Quant Thread for CAT 2012 [part 3]
d) 4356
rest three numbers have differences in multiples of 24
Edit : all of these..
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santhosh_163 replied to Official Quant Thread for CAT 2012 [part 3]
the question is atleast.. you have to go backwards.. the 5 questions can be solved in 5^5 ways which is 3125.. while there are only 3000 students.. so work backwards.. there is also a addition mistake.. it should be 821 which is exactly 125 more than 696 same way as 3125 is 125 more than 3000
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santhosh_163 replied to Official Quant Thread for CAT 2012 [part 3]
use the first statement alone.. figure out the water and milk content.. its 60 water and 20 milk.. now the second statement suggests that 20 milk needs to become 20% which is 1/5.. therefore total mixture has to be 20*5 = 100 litres.. already 60 litres water is present which means you need to ad...
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santhosh_163 replied to Official Quant Thread for CAT 2012 [part 3]
oh my bad.. didnt think that the question was in terms of m
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