I am also facing problems while filling up Academic details...

@ranjitgrv
I think for N>=5

@killeronrampage
Pakka hai bhai...
LOL...
plzz check using calculator ... main bhi kar raha hunn ....will let u know...gimme 2 mins
check for N>=5

@nesh28 just did that and got 23..thnx bro

@killeronrampage
nahi hota hai yeh!!!!
111 111 % 7 = 0
reason is E(7) is 6...
If N is prime... N-1 times repeat ka jo funda hai wahiin se aata hai...
Since N-1 is EULER of N

@venomizer
find the remainder of 55555 .... 93 times divided by 98?
E(98)=98(1-1/7)(1-1/2)=98*6/7*1/2=42
so 5555....42 times % 98 =0
=>5555....84 times % 98 =0
55555 .... 93 times={55555 .... 84 times*10^9 + 555...9 times}%98
=>555...9 times %98
Ab iska kya karein??
23??

@viveksingh1005
Delhi --a----(1)---b----(2)----c-------(3)---d---Chandi
1 2 3 ==>Stoppage Stations
a , b ,c are gaps and given b,c>0
a+b+c+d=35(3 are 1 2 3 the stoppage stations)
=>a+b'+c'+d=33
36 C 3ways

@rachit_28
30^20^10^5/19
E(19)=18
we find
20^10^5 mod 18
=>20^100000 mod 18
20 mod 18 =2
2^100000 mod 18
=>2^ 99999 mod 9 (cancel 2)
=> now 2^6 mod 9=1
2^999996 mod 9 =1
left 2^3 mod 9=8
multiply the canecelled 2 again
16
30^(18x+16)mod 19
=>30^16 m...

@akki2711
a+b+c=100
a,b,c>=1
so
a-1 + b-1 + c-1 =97
=>a'+b'+c'=97
then 97+2 C 2