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rastoginamit @pratskool bhai thoda detailed exlanation de sakte ho kya.

Officail Soln.
There are 40 women in 100m, 30 in 200m, 25 in 400 m
and 50 in 800m who can participate in other events as
well. There are at least 10 women who participate in
800 m only.
Let the number of women participating in the three
events 100m, 200m and 400m be p; in the three events
100m, 200m and 800m be q; in the three events 100m,
400m and 800m be r; in the three events 200m, 400m
and 800m be s.

So p+q+r≤40 ...(1)

p+q+s≤30 ...(2)
(2)
p+r+s≤25 ...(3)
(3)
q+r+s≤50 ...(4)
(4)
Adding the four inequalities, we get:

3(p+q+r+s)≤145

p+q+r+s≤48.33

Let’s take the maximum possible integer value of
(p + q + r + s) i.e.
48.

Adding (2) and (3), we get:

(p+s)+(p+q+r+s)≤55

p+s≤7 which is inconsistent with (1) as it gives
a negative value of p.

The maximum possible value of (p + q + r + s) would
be 47. So a maximum of 47 women can participate in
exactly 3 events.
It can be done with multiple sets of values of p, q, r ,s.
One set of values would be:
p = 0, q = 22, r = 18, s = 7 which would mean that:

• 22 women participate in 100m, 200m and 800m.

• 18 women participate in 100m, 400m and 800m.

• 7 women participate in 200m, 400m and 800m.

#11 • 27 Apr Like 1
rastoginamit @pratskool @techsurge Bhai, koi upar wala soln(official) dk krhi samjha do.
#12 • 27 Apr Like
rastoginamit @techsurge Bhai, ye toh copy paste soln h from CL. Mujhe khud samajh ni aaya.
#13 • 27 Apr Like

B I U

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rastoginamit replied to Official Quant thread for CAT 2013

rastoginamit

28 Apr

Help Needed

13 Comments

rastoginamit @pratskool @techsurge Bhai, koi upar wala soln(official) .... 27 Apr.

rastoginamit @techsurge Bhai, ye toh copy paste soln h from CL. Mujhe .... 27 Apr.

rastoginamit

10:50 PM, 27 Apr '13

Official Quant thread for CAT 2013

28 Apr

Help Needed

Don't ever let somebody tell you…you can't do something.

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rastoginamit @pratskool bhai thoda detailed exlanation de sakte ho kya.

Officail Soln.
There are 40 women in 100m, 30 in 200m, 25 in 400 m
and 50 in 800m who can participate in other events as
well. There are at least 10 women who participate in
800 m only.
Let the number of women participating in the three
events 100m, 200m and 400m be p; in the three events
100m, 200m and 800m be q; in the three events 100m,
400m and 800m be r; in the three events 200m, 400m
and 800m be s.

So p+q+r≤40 ...(1)

p+q+s≤30 ...(2)
(2)
p+r+s≤25 ...(3)
(3)
q+r+s≤50 ...(4)
(4)
Adding the four inequalities, we get:

3(p+q+r+s)≤145

p+q+r+s≤48.33

Let’s take the maximum possible integer value of
(p + q + r + s) i.e.
48.

Adding (2) and (3), we get:

(p+s)+(p+q+r+s)≤55

p+s≤7 which is inconsistent with (1) as it gives
a negative value of p.

The maximum possible value of (p + q + r + s) would
be 47. So a maximum of 47 women can participate in
exactly 3 events.
It can be done with multiple sets of values of p, q, r ,s.
One set of values would be:
p = 0, q = 22, r = 18, s = 7 which would mean that:

• 22 women participate in 100m, 200m and 800m.

• 18 women participate in 100m, 400m and 800m.

• 7 women participate in 200m, 400m and 800m.

#11 • 27 Apr Like 1
rastoginamit @pratskool @techsurge Bhai, koi upar wala soln(official) dk krhi samjha do.
#12 • 27 Apr Like
rastoginamit @techsurge Bhai, ye toh copy paste soln h from CL. Mujhe khud samajh ni aaya.
#13 • 27 Apr Like

B I U

Press Shift+Enter to add a new line.

rastoginamit posted a ping

rastoginamit

27 Apr

rastoginamit commented on a post

rastoginamit

27 Apr

Help Needed
The question given below is followed by two statements, A and B. Mark the answer using the following instructions:Mark (a) if the question can be answered by using either statement alone.Mark
(b) if the question can be answered by using one of the statements alone, but cannot ...

19 Comments

rastoginamit @pratskool Ans= b. 1st alone is sufficient. :/ Can you su.... 27 Apr.

rastoginamit @placiddisciple useful piece of information. thank you :) . 27 Apr.

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