rajsher's posts
rajsher replied to Quant Marathon
No doubt that the answer would be 0.448.
when u draw thw figure than u can see that the area common to the three circles will be just less than the half of the area common to the three circles. Is will get enclosed in the line of symmetry of the second part. udi baba my 1000th post.......
rajsher replied to Quantitative questions a day 51 to 100 - The di...
Why do we need to square the first root waala part twice? There might be a case that it may get cancelled by some other negative term in the second equation!!!
Say in the equation for the root 2^1/2 + 3^1/3, whih will be a 6 degree polynomial, thr is a possibility that one of the term in ther...
rajsher replied to Quant Marathon
If the zeros are increasing by 1 everytime then the answer will be remainder of 3 + 9*10^4 divided by 7, i.e. 4.
I thought that the question states that the term is only for odd powers.
rajsher replied to Quant Marathon
From fermats little theorem,
10^6=1mod7
so the question given to us reduced to
finding the remainder of 3+ 5*10^4
rajsher replied to quantitative teasers
After n days, if n=even
Number of men = n/2
boys= n/2-1
every man added does extra work of 1/400 per day. and every boy added does lesser work of 1/800 per day.
so after 18 days, the extra work done is
1/400*(1+3+...+17)-1/800(2+4+6...+16) = 81/400 - 36/400 = 45/400 which is just g...
rajsher replied to Quotas to INCREASE at the IITs, IIMS!!!
This article has left me dumbstruck! I dont know what to say!
The only thing I know and which i had said since the start is that I dont want to live in this country! and now I too have many sane people in my group like DG etc.
Some of you have questioned the outlash which we will face in...
rajsher replied to DI MARATHON for CAT06
Hi,
A request to all of you, whosoever is solving the puzzles, plz try to note down the time you take to solve the puzzle and put it along with the answer. It will help us determine the difficulty level and the estimated number of marks attached to the questions of the puzzle.
rajsher replied to Quantitative questions a day 51 to 100 - The di...
If u have reached here, then it is very simple, the answer is =
summation of all possible values of a*b
= 1/2(1/5+1/5^3+...) +1/2^3*(1/5+1/5^3+...) +.....
=(1/2 + 1/2^3+...)*(1/5+1/5^3+...)
=2/3*5/24
=5/36
but the given answer is 5/9
rajsher replied to Quotas to INCREASE at the IITs, IIMS!!!
what?? r U not gonna leave??
rajsher replied to Quantitative questions a day 51 to 100 - The di...
9) the answer is 7:20, u can make the calculations easier by making a big cone of radius 3r and height 3h and then proceeding with the question. (just remember the volume will be proportional to r^2 * h )
11) I also found than the only possibility is that T must coincide with Q, but i ddnt at...