Thank you for replying..
Could you please give me contact details of admission office coz i've tried the numbers listed on their site, but they haven't picked.
Also,in that mail i m supposed to submit the fees and other details before June 2, but as per starpict it's 20 may. Please help.
Are they going to inform people who are nominated for preparatory courses?

I guess, Businessworld magazine rankings for 2009 r out.
Plzz, chk this out.

Businessworld - Breaking Through The Clutter


Thr is no place for IIM-K.
Did they not participate?
Or have they gone really that much below par?

As far as I know, 'K' would not have participated.
Otherwise it would have been in first 10.
But magazine has not mentioned anything about 'k'.
Whether they participated or not, that is mentioned in case of IIMB n IIMC

Seniors, any info on this.

Hey thr?
Do you have any info abt when is 2009-11 session going to start.
Also, I got a mail regarding selection, but still my name is not listed on admission link. why is it so?

4) Why do we check for factors just till square root of x and not beyond that till x for a prime number ?

I'll try to explain it with an example

Suppose if we have to find out the factors of number 40
Then it will be
1*40
2*20
4*10
5*8

As you can see from above factor pairs, one factor is less than square root of the number and other is greater than square root of the number and this will be true for all the cases.

Further it implies that if we are not able to find a factor up to the value of its square root. we won't be able to find above the square root as well, thus PRIME

Answer to the first question is 492.
Take the numbers in the form of 7x+2,8y+d' and 9z+d''.
taje two numbers at a time,interpret the values by finding out the first value for which other side is also an integer.and then keep this value in the second pair.

Could you please explain it a little bit more. Didn't get it

Try these....

At an island, people use a number system to base 'n' such that n<9. Which of the following is true of the remainder obtained when an inhabitant of that island divides by ?
(1) 0, if n is odd
(2)1, if n is even
(3)both 1 and 2
(4)neither 1 nor 2

Given number's (111....n times) value will be
n^(n-1)+n^(n-2)+n^(n-3)+.....+1

Now, rest part i'll prove by taking n=4 or n=5

when i put n=4 (even) number becomes n^3+n^2+n+1 which is divisible by n+1.
but when i put n=5(odd) number becomes n^4+n^3+n^2+b+1 which is not divisible by n+1 leaving 1 as remainder.


Remainder of n^4/(n+1) will be 1


Similarly if i take n=6
n^5+n^4+n^3+n^2+n+1 is divisible by n

and for n=7
n^6+n^5+n^4+n^3+n^2+n+1 is not divisible by n leaving 1 as remainder.


Thus for n=odd Remainder=1
and for n=even Remainder=0

Option-4 Neither 1 nor 2

Consider the series 5,5,5,5,5,6,6,6,6,6,6,7,7,7,7,7,7,7,.......and so on. What is the sum of first 1000 terms of the series?
1. 33295
2. 30270
3. 32265
4. 30240
5. 30965

Happy Solving!!

We first have to calculate which number will be at 1000th place

5+6+7+8+9...n = 1000

By A.P. we get number of terms as 40, so 980th number will be 44,after that 20 digits will be 45

Sum of series will be 5^2+6^2+7^2......+44^2+45*20 = 30240 (d)

2) 10 thieves steal x gold coins and escape.While all are asleep,2 thieves wake up and divide the coins between them and find 1 coin extra.Just then a third thief wakes up.So the 3 thieves divide all the coins among them and find 2 coins extra.Again a 4th thief wakes up and on dividing the coins among them,3 coins are extra.This continues till the 10th thief wakes up and on dividing the coins among them 9 coins are extra.What is the least value of x ?

I think it would be LCM of (2,3,4,5,6,7,8,9,10) -1
i.e 2520 -1 =2519

Friends...Help needed with these questions..

2.If P = 2^(2/3) + 2^(1/3) then which of the following is true ?
(a) p^3 - 6p - 6 = 0
(b) p^3 - 6p + 6 = 0
(c) p^3 + 6p - 6 = 0
(d) p^3 + 6p + 6 = 0
(e) -p^3 - 6p + 6 = 0

Let's take 2^1/3 as k.
k^3 = 2


p = k^2+k

p^3 = k^6+k^3+3k^3
p^3 = 4 + 2 + 6p
p^3 = 6 + 6p
p^3 - 6p -6 = 0

Ans (a)

Q. A,B and C start a business. Their investments are in the ratio a:b:c, where (b-a)=(c-b)=k and b>3k.Their annual profit shares are in the ratio c^2:b^2:a^2. what can be the ratio of their time periods?
Options: 9,10,11,8,7.

Given
Investement ratio = a:b:c
Profit ratio = c^2:b^2:a^2

Let time periods' ratio be x:y:z
Hence x=(c^2/a), z=(a^2/c)
Required ratio = x:z = c^3/a^3

But, c=b+k and a=b-k
So, Required ratio will be (b+k)^3/(b-k)^3

= ^3
= ^3

Given b/k > 3. So, (b/k-1)>2

Req ratio < 2^3

Only option that satifies this condition is e(7).

Q. A,B and C start a business. Their investments are in the ratio a:b:c, where (b-a)=(c-b)=k and b>3k. what can be the ratio of their time periods?
Options: 9,10,11,8,7.

I guess you've missed their annual profit shares.
Else answer can't be determined