pushpendra.pal's posts
pushpendra.pal replied to [2009-2011] IIMK Final Results Out / Final Call...
Thank you for replying..
Could you please give me contact details of admission office coz i've tried the numbers listed on their site, but they haven't picked.
Also,in that mail i m supposed to submit the fees and other details before June 2, but as per starpict it's 20 may. Please help.
pushpendra.pal replied to [2009-2011] IIMK Final Results Out / Final Call...
Hey thr?
Do you have any info abt when is 2009-11 session going to start.
Also, I got a mail regarding selection, but still my name is not listed on admission link. why is it so?
pushpendra.pal replied to official quant thread for CAT 2009
I'll try to explain it with an example
Suppose if we have to find out the factors of number 40
Then it will be
1*40
2*20
4*10
5*8
As you can see from above factor pairs, one factor is less than square root of the number and other is greater than square root of the number an...
pushpendra.pal replied to official quant thread for CAT 2009
Could you please explain it a little bit more. Didn't get it
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pushpendra.pal replied to official quant thread for CAT 2009
Given number's (111....n times) value will be
n^(n-1)+n^(n-2)+n^(n-3)+.....+1
Now, rest part i'll prove by taking n=4 or n=5
when i put n=4 (even) number becomes n^3+n^2+n+1 which is divisible by n+1.
but when i put n=5(odd) number becomes n^4+n^3+n^2+b+1 which is not divisible by n+...
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pushpendra.pal replied to official quant thread for CAT 2009
We first have to calculate which number will be at 1000th place
5+6+7+8+9...n = 1000
By A.P. we get number of terms as 40, so 980th number will be 44,after that 20 digits will be 45
Sum of series will be 5^2+6^2+7^2......+44^2+45*20 = 30240 (d)
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pushpendra.pal replied to official quant thread for CAT 2009
I think it would be LCM of (2,3,4,5,6,7,8,9,10) -1
i.e 2520 -1 =2519
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pushpendra.pal replied to official quant thread for CAT 2009
Let's take 2^1/3 as k.
k^3 = 2
p = k^2+k
p^3 = k^6+k^3+3k^3
p^3 = 4 + 2 + 6p
p^3 = 6 + 6p
p^3 - 6p -6 = 0
Ans (a)
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pushpendra.pal replied to official quant thread for CAT 2009
Given
Investement ratio = a:b:c
Profit ratio = c^2:b^2:a^2
Let time periods' ratio be x:y:z
Hence x=(c^2/a), z=(a^2/c)
Required ratio = x:z = c^3/a^3
But, c=b+k and a=b-k
So, Required ratio will be (b+k)^3/(b-k)^3
= ^3
= ^3
Given b/k > 3. So, (b/k-1)>2
Req r...
pushpendra.pal replied to official quant thread for CAT 2009
I guess you've missed their annual profit shares.
Else answer can't be determined