@vinishverma

for a set of particular distinct integral values a,b,c and d. The equation (n+a)(n+b)(n+c)(n+d)= 25 holds. for how many distinct integral values of n does it holds

2 answers 0

1 answer 1

2 answers 2

1 answer more than 2

×

lets take n value starting from 0 for n=0 (0+1)(0-1)(0+5)(0-5)=25

n=3, (3+2)(3-2)(3-4)(3-8)=25

n=4, (4+1)(4-3)(4-5)(4-9)=25

Hence there are more than 2 posibilities to arrive at integer solution for the equation..

pls let me know if its appropriate?

regards

KBM

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