nil1989's posts
nil1989 replied to Indian Premier League- Season 5 & Fantasy Leagu...
2 exceptional things in one day:-
KKR winning it for shahrukh and
Facebook(our server never sleeps) going blank for maintanence...
what a day in cricket and world history!!! by d way 3 cheers for kkr...
WE ROCK!!!
nil1989 replied to Official Quant Thread for CAT 2012 [part 3]
the logic for 7 identical things to 5 people-
1 st we have to find out all d cases-
eg(7,0,0,0,0)-5 ways
(6,1,0,0,0)- 5c2*2 ways
(5,2,0,0,0)-5c2*2ways
(5,1,1,0,0)-5c3*(3!/2) ways
(4,3,0,0,0)-5c2*2 ways
(4,2,1,0,0)-5c3*3! ways
and there are a few more cases-
it ends with...
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nil1989 replied to Official Quant Thread for CAT 2012 [part 3]
hence 8*13C3*4C3*4C3
seems to be correct.
i missed out on the negative values.. btw then jst check out my way once.. i guess thr is some error in it apart from the negative value thing. @ sam
___/\___ chillfactor sir
nil1989 replied to Official Quant Thread for CAT 2012 [part 3]
m extremely sorry for those repeated posts..
my net wasn't working properly....
sry again!!!
nil1989 replied to Official Quant Thread for CAT 2012 [part 3]
factorise 15360 to get 2^10*3*5
now write all of them serially 2 2 2 2 2 2 2 2 2 2 3 5.
we have 4 cases now:-
1> no nos is 1: we select 3 partition out of 11 in 11c3 ways.
2> 1 nos is 1: select that in 4c1 ways and then select 2 out of 11 partitions.
therefore total= 4* 11c2
3>...
nil1989 replied to Official Quant Thread for CAT 2012 [part 3]
factorise 15360 to get 2^10*3*5
now write all of them serially 2 2 2 2 2 2 2 2 2 2 3 5.
we have 4 cases now:-
1> no nos is 1: we select 3 partition out of 11 in 11c3 ways.
2> 1 nos is 1: select that in 4c1 ways and then select 2 out of 11 partitions.
therefore total= 4* 11c2
3>...
nil1989 replied to Official Quant Thread for CAT 2012 [part 3]
factorise 15360 to get 2^10*3*5
now write all of them serially 2 2 2 2 2 2 2 2 2 2 3 5.
we have 4 cases now:-
1> no nos is 1: we select 3 partition out of 11 in 11c3 ways.
2> 1 nos is 1: select that in 4c1 ways and then select 2 out of 11 partitions.
therefore total= 4* 11c2
3>...
nil1989 replied to Official Quant Thread for CAT 2012 [part 3]
factorise 15360 to get 2^10*3*5
now write all of them serially 2 2 2 2 2 2 2 2 2 2 3 5.
we have 4 cases now:-
1> no nos is 1: we select 3 partition out of 11 in 11c3 ways.
2> 1 nos is 1: select that in 4c1 ways and then select 2 out of 11 partitions.
therefore total= 4* 11c2
3>...
nil1989 replied to Official Quant Thread for CAT 2012 [part 3]
is the soln to the pblm a*b*c*d=15360 :- 455?
nil1989 replied to Official Quant Thread for CAT 2012 [part 3]
is the soln to the rem pblm 20?
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