(n^2-1) is always divisible by 3 for all values which are not 3 or its multiples
as for n = 3, 6, 9... they are anyway multiples of 3.
mbakarvuche's posts
mbakarvuche
replied to Number System - Questions & Discussions
This expression is always divisible by 3.
(n^2-1) is always divisible by 3 for all values which are not 3 or its multiples
as for n = 3, 6, 9... they are anyway multiples of 3.
(n^2-1) is always divisible by 3 for all values which are not 3 or its multiples
as for n = 3, 6, 9... they are anyway multiples of 3.