MaskedMenace's posts

MaskedMenace
replied to AIMCAT 1318: Discussion thread

The guy who started the thread should have made it public while creating a poll, then its possible to see the names of guys who polled.

I think, now a moderator can change it.

I think, now a moderator can change it.

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MaskedMenace
commented on an article

Shaishav Amrut Solanki, is the Indian Institute of Management (IIM) Indore's first author - could very well be the first on-campus author among all IIMs. Having just released a book few days ago, the young author is all smiles seeing it do brisk business. The book, the author claims is as much fiction as non-fiction and abo...

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31 Comments

Clifford_Dsouza
if writers move into Managerial colleges then where would....

AssassinCT
Disheartened after reading his interview. Very negativ....

MaskedMenace
replied to Official Quant Thread for CAT 2011 [Part 6]

We need to find numbers divisible by 3,5 and eliminate those divisible by 21,35,15 and add those divisible by 105.

divisible by 3 => 102 to 999 => 897/3 + 1 => 300

divisible by 5 => 105 to 995 => 895/5 + 1 => 180

Divisible by 21 => 21*47 is near 999 so , 47 - 4 = 43 such numbers

Divis...

divisible by 3 => 102 to 999 => 897/3 + 1 => 300

divisible by 5 => 105 to 995 => 895/5 + 1 => 180

Divisible by 21 => 21*47 is near 999 so , 47 - 4 = 43 such numbers

Divis...

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MaskedMenace
replied to Official Quant Thread for CAT 2011 [Part 5]

Its not possible to make all of them equal.

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MaskedMenace
replied to Official Quant Thread for CAT 2011 [Part 5]

129*127*125*122*119*117

Last digit is 0

now, Last two digits of

29*27*25*61*19*17 is 25

1/x + 1/y = 1/196

(x+196)(y+196) = 196^2

RHS takes all the divisors of 196^2 = 14^4 => 7^4 * 2^4 => 25

(Oops Ordered pairs i ignored)

@RC89 : Wish you a Happy Birthday

Last digit is 0

now, Last two digits of

29*27*25*61*19*17 is 25

1/x + 1/y = 1/196

(x+196)(y+196) = 196^2

RHS takes all the divisors of 196^2 = 14^4 => 7^4 * 2^4 => 25

(Oops Ordered pairs i ignored)

@RC89 : Wish you a Happy Birthday

3

MaskedMenace
replied to Official Quant Thread for CAT 2011 [Part 5]

Its 2^n - 1, n is number of weights

(For more info search for towers of Hanoi)

(For more info search for towers of Hanoi)

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MaskedMenace
replied to Official Quant Thread for CAT 2011 [Part 5]

7^6 is the number of cases in which the 6 tickets chosen are numbered between 1 to 7 i.e., where there is no 8, 9 or 10.

6^6 is the number of cases in which the 6 tickets are numbered between 1 to 6 i.e. where there is no 7, 8, 9 or 10.

7^6 - 6^6 is the no of cases in which 7 is there and a...

6^6 is the number of cases in which the 6 tickets are numbered between 1 to 6 i.e. where there is no 7, 8, 9 or 10.

7^6 - 6^6 is the no of cases in which 7 is there and a...

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MaskedMenace
replied to Official Quant Thread for CAT 2011 [Part 5]

Here are the solutions

(19,684)

(21,252)

(27,108 )

(45,60)

(99,44)

(19,684)

(21,252)

(27,108 )

(45,60)

(99,44)

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MaskedMenace
replied to Official Quant Thread for CAT 2011 [Part 5]

Two digit prime numbers can be

(11,31,41,61,71) & (17,37,47,67,97)

or

(13,23,43,53,73,83)&(19,29,59,79,89)

So, total distinct products are 5*5 + 6*5 = 55

Case 1: 3_ _ _ => 27 - 2 => 25

Because, we do not get 222 & 333 case

Case 2: 4_ _ _ => 27 - 1 => 26

Because we do not g...

(11,31,41,61,71) & (17,37,47,67,97)

or

(13,23,43,53,73,83)&(19,29,59,79,89)

So, total distinct products are 5*5 + 6*5 = 55

Case 1: 3_ _ _ => 27 - 2 => 25

Because, we do not get 222 & 333 case

Case 2: 4_ _ _ => 27 - 1 => 26

Because we do not g...