Count me in this time

Dear Sir,

@[562370:chetso]: Thanks for reverting back.

Hi Puys,

Captcha daal daal ke jaan nikal gai. :/

@Predilected said: remainder 3^268/22=????

27 ...

let x y z be 13p 13 q 13r resp.
so
p+q+r = 9
but each of p q r has to be +ve
put p' = p+1 ... similarly for q and r
p'+q'+r' = 6
so 8c2 = 28 ways
but when all are equal i.e at p=q=r = 3 x y z wont be co prime

so total 28-1 = 27 triplets

The HCF of three natural numbers x, y and z is 13. If the sum of x, y and z is 117, then how many ordered triplets (x, y, z) exist?

a. 28
b. 27
c. 54
d. 55

let the numbers be 13a,13b,13c
13a+13b+13c = 117
a+b+c = 9
a,b,c>0
8c2 = 28
- case when all three are equal
27

Arre bhai log,

8C2 kyun aaya? Koi please explain kardo

B.Com (H) from DU, 3 yrs work ex in advertising. Am lookin at the top 15 in the US. Might apply to R3 of one or two but mainly targeting R1 in Sept for class of 2012-14

Hi, Just wanted a quick check on how can you apply in top 15 US B-Schools with a 3 year Indian degree? Most of the univs in US demand a 4 year US equivalent i.e a 4 year Indian degree or a 3 years bachelors + 2 years masters.

Wouldn't you face any hindrance due to this?

How do you plan to bridge the gap between a 3 year Indian degree and a 4 year US degree? I presume you just have a Bcom(H) from DU.

Thanks :)

P.S - I too am sailing on the same boat. Still contemplating my options for bridging the gap. A little insight into this would be of great help.