k_himanshu's posts

k_himanshu
replied to Official Quant Thread for CAT 2011 [Part 3]

sorry for the misspelling of the options bro.

your answer is correct

The option was 44(4/9)

:D

your answer is correct

The option was 44(4/9)

:D

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1

k_himanshu
replied to Official Quant Thread for CAT 2011 [Part 3]

Yes, the options are correct. It is from Time Sectional test.

k_himanshu
replied to Official Quant Thread for CAT 2011 [Part 3]

Sachin, Saurav and Rahul enter into a partnership with capitals of 18000, 24000 and 48000. Saurav, apart from his share of profit, receives a certain percentage of the profit for managing the business. Sachin' s share in the profit is 30000. Find the percentage of the profit that Rahul receives i...

k_himanshu
replied to Official Quant Thread for CAT 2011 [Part 3]

answer is 5

(n-1)*Middle Term = 45- Middle Term

so, Middle term = 45/n

now n=Middle term(m) +4

i.e. m(m+4) = 45

5(5+4) = 45

hence m = 5

(n-1)*Middle Term = 45- Middle Term

so, Middle term = 45/n

now n=Middle term(m) +4

i.e. m(m+4) = 45

5(5+4) = 45

hence m = 5

k_himanshu
replied to University of Georgia - Terry College of Business

can you please tell what are the MBA programs that are available at Terry college of business?

Thanks in advance,

Himanshu

Thanks in advance,

Himanshu

k_himanshu
replied to Official Quant Thread for CAT 2011 [Part 3]

Hi chill Bhai,

I got your solution man however can you pls explain why D should have to be a perfect sq ?

Thanks,

Himanshu

I got your solution man however can you pls explain why D should have to be a perfect sq ?

Thanks,

Himanshu

k_himanshu
replied to Official Quant Thread for CAT 2011 [Part 3]

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k_himanshu
replied to Official Quant Thread for CAT 2011 [Part 3]

Sorry. That's incorrect.

k_himanshu
replied to Official Quant Thread for CAT 2011 [Part 3]

geometric approach :

(x+y) = k(x-y)

here, x+y is line 1 and x-y is line 2.

These who are equated hence they have same distance from the origion.

slope of line 1 : 1/1 = 1

slope of line 2 : -1/1 = -1

slope1*slope2 = -1

hence these two lines are perpendicular.

x^2+y^2 is t...

(x+y) = k(x-y)

here, x+y is line 1 and x-y is line 2.

These who are equated hence they have same distance from the origion.

slope of line 1 : 1/1 = 1

slope of line 2 : -1/1 = -1

slope1*slope2 = -1

hence these two lines are perpendicular.

x^2+y^2 is t...