Hi Puys,
i seriously wanna look at the question paper and solutions of 1320 and 1319.. Don wanna look at 1318 lol.. Please PM me or mail me to

Does anyone have any idea about iim's criteria this year? Will there be any changes from the previous year?

chevy Says

OA: 1/4

Hi, I don have any idea in these kinda problems. please someone here explain it pls.

Q.
The expression
333^555 +555^333
is divisible by
a. 2
b. 3
c. 37
d. 11
e. All of these

My take would be option e.All of these.

chking divisibility of 2:
Rule: number should be an even number

last digit of 333^555 will be 7 (by property of cyclicity)

last digit of 555^ will be 5 (obivously 5 power anything, last digit is 5)

7+5=12 hence 2 will be the last digit which is even.
hence the expression will be divisible by 2.

chking divisibility of 3:
Rule: sum of digits should be divisible by 3
3+3+3=9 divisible by 3
so 333 power anything will be divisible by 3

5+5+5=15 divisible by 3
so 555 power anything will be divisible by 3

And,remember remainders are additive in nature hence 0+0/3 =0

hence the expression will be divisible by 3.

This much work would suffice to prove option should be e.All of these

Thanks a lot man:-)

Hi All,
Can anyone please explain abt Euler's Theroem?
Also let me know where should we use it?

Thanks In Advance...

All the Best

Hey puys,
i am working for cognizant..anybody there from the same firm preparing for cat 2012
If you re interested na,tel me we could share few questions wit each other during office time..it ll be so effective..