distance travelled by car in 1/2 hr= dist travelled by bus in 1 hr so speed ratio=sc/sb=2 total distance travelled by both in whole travel=2X80=160km distance share covered by car =2/3of 160 in 80 mins speed=40kmph.....
The car covers distance (4/3)C in 4/3 hours Meanwhile in 110 mins, the bus would have covered 11/12C distance.
Now (4/3)C+(11/12)C = 2*80 = 160 =>C=640/9
and hence B=320/9
distance travelled by car in 1/2 hr= dist travelled by bus in 1 hr so speed ratio=sc/sb=2 total distance travelled by both in whole travel=2X80=160km distance share covered by car =2/3of 160 in 80 mins speed=40kmph.....
distance travelled by car in 1/2 hr= dist travelled by bus in 1 hr so speed ratio=sc/sb=2 total distance travelled by both in whole travel=2X80=160km distance share covered by car =2/3of 160 =40kmph.....
distance travelled by car in 1/2 hr= dist travelled by bus in 1 hr so speed ratio=sc/sb=2 total distance travelled by both in whole travel=2X80=160km distance share covered by car =2/3of 160 =40kmph.....
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The concepts of Set Theory are applicable not only in Quant, Data Interpretation and Logical Reasoning but also in solving syllogism questions. Let us first understand the basics of the Venn Diagram before we move on to the concept of maximum and minimum. A large nu...
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lovey89
@ravihanda : In example 2 how did you find the max value ....
16 Apr.
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